The volume of a sphere can be represented by the formula \begin{align*}V=\frac{4 \pi r^3}{3}\end{align*}

### Algebraic Expressions with Fraction Bars

Fraction bars count as grouping symbols for PEMDAS, and should be treated as a set of parentheses. All numerators and all denominators can be treated as if they have invisible parentheses. When real parentheses are also present, remember that the innermost grouping symbols should be evaluated first. If, for example, parentheses appear in a numerator, they would take precedence over the fraction bar. If the parentheses appear outside of the fraction, then the fraction bar takes precedence.

#### Let's use PEMDAS to solve the following problems:

- Simplify the expression: \begin{align*}\frac{z+3}{4}-1 \text{ when }z=2.\end{align*}
z+34−1 when z=2.

Begin by substituting the appropriate value for the variable:

\begin{align*}\frac{(2+3)}{4} -1 = \frac{5}{4} -1\end{align*}

Rewriting 1 as a fraction, the expression becomes:

\begin{align*}\frac{5}{4} - \frac{4}{4} = \frac{1}{4}\end{align*}

- Simplify the expression \begin{align*}\left (\frac{a+2}{b+4} - 1 \right ) + b\end{align*}
(a+2b+4−1)+b when \begin{align*}a = 3\end{align*} and \begin{align*}b = 1\end{align*}

Begin by substituting the appropriate value for the variable:

\begin{align*}\frac{(3+2)}{(1+4)} = \frac{5}{5} = 1\end{align*}

\begin{align*}(1 - 1) + b\end{align*} Substituting 1 for *b,* the expression becomes \begin{align*} 0 + 1 = 1\end{align*}

- Simplify the expression \begin{align*}2 \times \left( \frac{w+(x-2z)}{(y+2)^2} -1 \right)\end{align*} , when \begin{align*}w=11, x=3, y=1, \text{ and }z= \text{-}2.\end{align*}

Begin by substituting the appropriate values for the variables:

\begin{align*}2 \left ( \frac{[11+(3-2(-2))]}{[(1+2)^2)]} - 1 \right ) = 2 \left ( \frac{(11+7)}{3^2} -1 \right ) = 2 \left (\frac{18}{9} - 1 \right )\end{align*}

Continue simplifying:

\begin{align*}2\left ( \frac{18}{9} - \frac{9}{9} \right ) = 2 \left ( \frac{9}{9} \right ) = 2(1)= 2\end{align*}

### Examples

#### Example 1

Earlier, you were told that the volume of a sphere can be represented by the formula \begin{align*}V=\frac{4 \pi r^3}{3},\end{align*} where \begin{align*}r\end{align*} is the radius. You were also told that there is a sphere that has a radius of 4 feet.

To find the volume of the sphere, first plug in 4 for the radius:

\begin{align*}V=\frac{4\pi r^3}{3}=\frac{4\pi (4)^3}{3}\end{align*}

Now, treat the fraction bar as a grouping symbol and complete the operations above and below the bar independently until the numerator and denominator are simplified.

Working with the numerator, simplify the exponent first:

\begin{align*}\frac{4\pi (4)^3}{3}=\frac{4\pi (64)}{3}\end{align*}

Now multiply the numerator. You can either leave the symbol \begin{align*}\pi\end{align*} and just multiply 4 and 64 or you can use 3.14 as an estimate for \begin{align*}\pi\end{align*} and end up with a decimal answer. In this case, we will leave the symbol

#### Example 2

Use the order of operations to evaluate the following expression when \begin{align*}x=6 \text{ and }y=2:\end{align*}

\begin{align*}\left (\frac{x-1}{y-1} \right )^2 + \frac{2x}{y^2}\end{align*}

Begin by substituting in 6 for \begin{align*}x\end{align*} and 1 for \begin{align*}y\end{align*}.

\begin{align*}\left (\frac{6-1}{2-1} \right )^2 + \frac{2(6)}{2^2}\end{align*}

First, we work with what is inside the parentheses. There, we have a fraction so we have to simplify the fraction first, simplifying the numerator and then the denominator before dividing. We can simply the other fraction at the same time.

\begin{align*}\left (\frac{5}{1} \right )^2 + \frac{12}{4}\end{align*}

Next we simplify the fractions, and finish with exponents and then addition:

\begin{align*} (5 )^2 + 3=25+3=28\end{align*}

### Review

Use the order of operations to simplify the following expressions.

- \begin{align*}\frac{2 \cdot (3 + (2 - 1))}{4 - (6 + 2)} - (3 - 5)\end{align*}
- \begin{align*}\frac{(2+3)^2}{3-8} - \frac{3\cdot(10-4)}{7-4}\end{align*}

Evaluate the following expressions involving variables.

- \begin{align*}\frac{jk}{j + k}\end{align*} when \begin{align*}j = 6\end{align*} and \begin{align*}k = 12\end{align*}
- \begin{align*}\frac{4x}{9x^2 - 3x + 1}\end{align*} when \begin{align*}x = 2\end{align*}
- \begin{align*}\frac{z^2}{x + y} + \frac{x^2}{x - y}\end{align*} when \begin{align*}x = 1, \ y = -2\end{align*}, and \begin{align*}z = 4\end{align*}
- \begin{align*}\frac{4xyz}{y^2 - x^2}\end{align*} when \begin{align*}x = 3, \ y = 2\end{align*}, and \begin{align*}z = 5\end{align*}
- \begin{align*}\frac{x^2 - z^2}{xz - 2x(z - x)}\end{align*} when \begin{align*}x = -1\end{align*} and \begin{align*}z = 3\end{align*}

The formula to find the volume of a square pyramid is \begin{align*}V=\frac{s^2 (h)}{3}.\end{align*} Evaluate the volume for the given values:

- \begin{align*}s=4\ inches,h=18\ inches\end{align*}
- \begin{align*}s=10\ feet,h=50\ feet\end{align*}
- \begin{align*}h=7\ meters,s=12\ meters\end{align*}
- \begin{align*}h=27\ feet,s=13\ feet\end{align*}
- \begin{align*}s=16\ cm,h=90\ cm\end{align*}

### Review (Answers)

To see the Review answers, open this PDF file and look for section 1.4.