What if you were given an inequality like \begin{align*}-3x^3 < -81\end{align*} and told that one of its solutions was \begin{align*}x > 3\end{align*}? How could you determine if that solution were correct? After completing this Concept, you'll be able to check the solutions to inequations like this one.

### Watch This

CK-12 Foundation: 0109S Check Solutions to Inequalities

### Try This

For more practice solving inequalities, check out http://www.aaastudy.com/equ725x7.htm.

### Guidance

To check the solution to an inequality, replace the variable in the inequality with the value of the solution. If the solution is correct, the simplified inequality will produce a true statement.

#### Example A

*Check that the given number is a solution to the inequality:* \begin{align*}a = 10; \ 20a \le 250\end{align*}

**Solution**

Replace the variable in the inequality with the given value.

\begin{align} 20(a) & \le 250\\ 20(10) & \le 250\\ 200 & \le 250\\ \end{align}

**\begin{align*}200 \le 250\end{align*} is a true statement**. This means that \begin{align*}a = 10\end{align*} is a solution to the inequality \begin{align*}20a \le 250\end{align*}.

Note that \begin{align*}a = 10\end{align*} is not the only solution to this inequality. Recall that inequalities may be simplified using essentially the same processes as equations. If we divide both sides of the inequality by 20, we can write it as \begin{align*}a \le 12.5\end{align*}. This means that actually any number less than or equal to 12.5 is a solution to the inequality.

#### Example B

*Check that the given number is a solution to the inequality:* \begin{align*}b = -0.5; \ \frac{3 - b}{b} > -4\end{align*}

**Solution:**

\begin{align} \frac{3 - (b)}{(b)} & > -4\\ \frac{3 - (-0.5)}{(-0.5)} &> -4\\ \frac{3 + 0.5}{-0.5} &> -4\\ - \frac{3.5}{0.5} & > -4\\ -7 &> -4\\ \end{align}

**This statement is false**. This means that \begin{align*}b = - 0.5\end{align*} is not a solution to the inequality \begin{align*}\frac{3 - b}{b} > -4\end{align*}.

#### Example C

*To organize a picnic, Peter needs at least two times as many hamburgers as hot dogs. He has 24 hot dogs. What is the possible number of hamburgers Peter has?*

**Solution:**

**Define**

Let \begin{align*}x\end{align*} represent the number of hamburgers

**Translate**

Peter needs at least two times as many hamburgers as hot dogs. He has 24 hot dogs.

This means that twice the number of hot dogs is less than or equal to the number of hamburgers.

\begin{align*}2 \times 24 \le x, \ \text{or} \ 48 \le x\end{align*}

**Answer**

Peter needs at least 48 hamburgers.

**Check**

48 hamburgers is twice the number of hot dogs. More than 48 hamburgers is more than twice the number of hot dogs. **The answer checks out**.

Watch this video for help with the Examples above.

CK-12 Foundation: Check Solutions to Inequalities

### Guided Practice

*Check that the given number is a solution to the inequality:* \begin{align*}x = \frac{3}{4}; \ 4x + 5 \le 8\end{align*}

**Solution:**

\begin{align} 4(x)+5 &\le 8\\ 4 \left ( \frac{3}{4} \right ) + 5 &\ge 8\\ 3 + 5 &\ge 8\\ 8 &\ge 8\\ \end{align}

**The statement \begin{align*}8 \ge 8\end{align*} is true **because this inequality includes an equals sign, and since 8 is equal to itself it is also “greater than or equal to” itself. This means that \begin{align*}x = \frac{3}{4}\end{align*} is a solution to the inequality \begin{align*}4x + 5 \le 8\end{align*}.

### Explore More

For 1-4, check whether the given number is a solution to the corresponding inequality.

- \begin{align*}x = 12; \ 2(x + 6) \le 8x\end{align*}
- \begin{align*}z = -9; \ 1.4z + 5.2 > 0.4z\end{align*}
- \begin{align*}y = 40; \ - \frac{5}{2}y + \frac{1}{2} < -18\end{align*}
- \begin{align*}t = 0.4; \ 80 \ge 10(3t + 2)\end{align*}
- On your new job you can be paid in one of two ways. You can either be paid $1000 per month plus 6% commission of total sales or be paid $1200 per month plus 5% commission on sales over $2000. For what amount of sales is the first option better than the second option? Assume there are always sales over $2000.

For 6-14, suppose a phone company offers a choice of three text-messaging plans. Plan A gives you unlimited text messages for $10 a month; Plan B gives you 60 text messages for $5 a month and then charges you $0.05 for each additional message; and Plan C has no monthly fee but charges you $0.10 per message.

- If \begin{align*}m\end{align*} is the number of messages you send per month, write an expression for the monthly cost of each of the three plans.
- For what values of \begin{align*}m\end{align*} is Plan A cheaper than Plan B?
- For what values of \begin{align*}m\end{align*} is Plan A cheaper than Plan C?
- For what values of \begin{align*}m\end{align*} is Plan B cheaper than Plan C?
- For what values of \begin{align*}m\end{align*} is Plan A the cheapest of all? (Hint: for what values is A both cheaper than B and cheaper than C?)
- For what values of \begin{align*}m\end{align*} is Plan B the cheapest of all? (Careful—for what values is B cheaper than A?)
- For what values of \begin{align*}m\end{align*} is Plan C the cheapest of all?
- If you send 30 messages per month, which plan is cheapest?
- What is the cost of each of the three plans if you send 30 messages per month?

### Answers for Explore More Problems

To view the Explore More answers, open this PDF file and look for section 1.9.