What if you had a system of linear equations like \begin{align*} x  y = 10\end{align*}
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CK12 Foundation: 0706S Comparing Methods for Solving Linear Systems by Elimination (H264)
Guidance
Now that we’ve covered the major methods for solving linear equations, let’s review them. For simplicity, we’ll look at them in table form. This should help you decide which method would be best for a given situation.
Method:  Best used when you...  Advantages:  Comment: 

Graphing  ...don’t need an accurate answer.  Often easier to see number and quality of intersections on a graph. With a graphing calculator, it can be the fastest method since you don’t have to do any computation.  Can lead to imprecise answers with noninteger solutions. 
Substitution 
...have an explicit equation for one variable (e.g. \begin{align*}y = 14x + 2\end{align*} 
Works on all systems. Reduces the system to one variable, making it easier to solve.  You are not often given explicit functions in systems problems, so you may have to do extra work to get one of the equations into that form. 
Elimination by Addition or Subtraction  ...have matching coefficients for one variable in both equations.  Easy to combine equations to eliminate one variable. Quick to solve.  It is not very likely that a given system will have matching coefficients. 
Elimination by Multiplication and then Addition and Subtraction  ...do not have any variables defined explicitly or any matching coefficients.  Works on all systems. Makes it possible to combine equations to eliminate one variable.  Often more algebraic manipulation is needed to prepare the equations. 
The table above is only a guide. You might prefer to use the graphical method for every system in order to better understand what is happening, or you might prefer to use the multiplication method even when a substitution would work just as well.
Example A
Two angles are complementary when the sum of their angles is \begin{align*}90^\circ\end{align*}
Solution
First we write out our 2 equations. We will use \begin{align*}x\end{align*}
\begin{align*}x + y &= 90\\ 2x &= 3y + 9\end{align*}
First, we’ll solve this system with the graphical method. For this, we need to convert the two equations to \begin{align*}y = mx + b\end{align*}
\begin{align*}& x + y = 90 \qquad \ \Rightarrow y = x + 90\\ & 2x = 3y + 9 \qquad \Rightarrow y = \frac{2}{3}x  3\end{align*}
The first line has a slope of 1 and a \begin{align*}y\end{align*}
In the graph, it appears that the lines cross at around \begin{align*}x = 55, y =35\end{align*}
Example B
In this example, we’ll try solving by substitution. Let’s look again at the system:
\begin{align*}x + y &= 90\\ 2x &= 3y + 9\end{align*}
We’ve already seen that we can start by solving either equation for \begin{align*}y\end{align*}
\begin{align*}y = 90  x\end{align*}
Substitute into the second equation:
\begin{align*}& 2x = 3(90  x) + 9 && distribute \ the \ 3:\\ & 2x = 270  3x + 9 && add \ 3x \ to \ both \ sides:\\ & 5x = 270 + 9 = 279 && divide \ by \ 5:\\ & x = 55.8^\circ\end{align*}
Substitute back into our expression for \begin{align*}y\end{align*}
\begin{align*}y = 90  55.8 = 34.2^\circ\end{align*}
Angle \begin{align*}A\end{align*}
Example C
Finally, in this example, we’ll try solving by elimination (with multiplication):
Rearrange equation one to standard form:
\begin{align*}& x + y = 90 \qquad \Rightarrow 2x + 2y = 180\end{align*}
Multiply equation two by 2:
\begin{align*}&2x = 3y + 9 \qquad \Rightarrow 2x  3y = 9\end{align*}
Subtract:
\begin{align*}& \quad \qquad \qquad \qquad 2x + 2y = 180\\ & \qquad \qquad \  \ \ (2x  3y) = 9\\ & \qquad \qquad \underline{\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;}\\ & \quad \qquad \qquad \qquad \qquad 5y = 171\\ \\ & \text{Divide by 5 to obtain} \ y = 34.2^\circ\end{align*}
Substitute this value into the very first equation:
\begin{align*}x + 34.2 &= 90 && subtract \ 34.2 \ from \ both \ sides:\\ x &= 55.8^\circ\end{align*}
Angle \begin{align*}A\end{align*} measures \begin{align*}55.8^\circ\end{align*}; angle \begin{align*}B\end{align*} measures \begin{align*}34.2^\circ\end{align*}.
Even though this system looked ideal for substitution, the method of multiplication worked well too. Once the equations were rearranged properly, the solution was quick to find. You’ll need to decide yourself which method to use in each case you see from now on. Try to master all the techniques, and recognize which one will be most efficient for each system you are asked to solve.
Watch this video for help with the Examples above.
CK12 Foundation: Comparing Methods for Solving Linear Systems
Vocabulary
 A linear system of equations is a set of equations that must be solved together to find the one solution that fits them both.
 Solving linear systems by substitution means to solve for one variable in one equation, and then to substitute it into the other equation, solving for the other variable.
 The purpose of the elimination method to solve a system is to cancel, or eliminate, a variable by either adding or subtracting the two equations. Sometimes the equations must be multiplied by scalars first, in order to cancel out a variable.
Guided Practice
Solve the system \begin{align*}\begin{cases} 5s+2t=6\\ 9s+2t=22\end{cases}\end{align*}.
Solution:
Since these equations are both written in standard form, and both have the term \begin{align*}2t\end{align*} in them, we will will use elimination by subtracting. This will cause the \begin{align*}t\end{align*} terms to cancel out and we will be left with one variable, \begin{align*}s\end{align*}, which we can then isolate.
\begin{align*}& \qquad \ 5s+2t=6\\ &\underline{\;\;  \ (9s+2t = 22) \;\;}\\ & \qquad \ 4s+0t =16\\ & \qquad \ 4s=16\\ & \qquad \ s=4\end{align*}
\begin{align*}5(4)+2t&=6\\ 20+2t&=6\\ 2t&=14\\ t&=7\end{align*}
The solution is \begin{align*}(4,7)\end{align*}.
Practice
Solve the following systems using any method.

\begin{align*}x = 3y\!\\
x  2y = 3\end{align*}

\begin{align*}y = 3x + 2\!\\
y = 2x + 7\end{align*}

\begin{align*}5x  5y = 5\!\\
5x + 5y = 35\end{align*}

\begin{align*}y = 3x  3\!\\
3x  2y + 12 = 0\end{align*}

\begin{align*}3x  4y = 3\!\\
4y + 5x = 10\end{align*}

\begin{align*}9x  2y = 4\!\\
2x  6y = 1\end{align*}
 Supplementary angles are two angles whose sum is \begin{align*}180^\circ\end{align*}. Angles \begin{align*}A\end{align*} and \begin{align*}B\end{align*} are supplementary angles. The measure of Angle \begin{align*}A\end{align*} is \begin{align*}18^\circ\end{align*} less than twice the measure of Angle \begin{align*}B\end{align*}. Find the measure of each angle.
 A farmer has fertilizer in 5% and 15% solutions. How much of each type should he mix to obtain 100 liters of fertilizer in a 12% solution?
 A 150yard pipe is cut to provide drainage for two fields. If the length of one piece is three yards less that twice the length of the second piece, what are the lengths of the two pieces?
 Mr. Stein invested a total of $100,000 in two companies for a year. Company A’s stock showed a 13% annual gain, while Company B showed a 3% loss for the year. Mr. Stein made an 8% return on his investment over the year. How much money did he invest in each company?