Paran's cell phone company charges a flat rate of $25 per month plus $0.25 per text. Marcel's cell phone company charges a flat rate of $100 and $1 per text. Marcel's bill for the month is four times Paran's. If they sent the same number of texts, how many did they each send?
Guidance
When a system has no solution or an infinite number of solutions and we attempt to find a single, unique solution using an algebraic method, such as substitution, the variables will cancel out and we will have an equation consisting of only constants. If the equation is untrue as seen below in Example A, then the system has no solution. If the equation is always true, as seen in Example B, then there are infinitely many solutions.
Example A
Solve the system using substitution:
Solution: Since the second equation is already solved for
Since the substitution above resulted in the elimination of the variable,
Example B
Solve the system using substitution:
Solution: We can solve for
Now, substitute this expression into the second equation and solve for
In the process of solving for
Example C
Solve the following system using substitution.
Solution: Before we begin, first, notice that the second equation is a multiple of the first. Each term is multiplied by 3. Therefore, we know that they are the same equation and will coincide. This system has infinitely many solutions.
Intro Problem Revisit The system of linear equations represented by this situation is:
Using substitution, we get:
There are an infinite number of solutions, so it can't be determined exactly how many texts Paran and Marcel sent.
Guided Practice
Solve the following systems using substitution. If there is no unique solution, state whether there is no solution or infinitely many solutions.
1.
2.
3.
Answers
1. Substitute the first equation into the second and solve for
Since the result is a true equation, the system has infinitely many solutions.
2. Solve the first equation for
Since the result is an untrue equation, the system has no solution.
3. Solving the second equation for
Now we can use this value of
Therefore, this system has a solution at (0, 0). After solving systems that result in 0 = 0, it is easy to get confused by a result with zeros for the variables. It is perfectly okay for the intersection of two lines to occur at (0, 0).
Explore More
Solve the following systems using substitution.
 .


17x−3yy=5=3x+1

 .


4x−14yy=21=27x+7

 .


−24x+9y8x−3y=12=−4

 .


y6x+8y=−34x+9=72

 .


2x+7yy=12=−23x+4

 .


2xy=−6y+11=−13x+7

 .


12x−45y5x−8y=8=50

 .


−6x+16yx=38=83y−193

 .


x5x+3y=y=0

 .


12x+3yy=−15=x−5

 .


23x+16yy=2=−4x+12

 .


16x−4yy=3=4x+7

 .


x−4y8y−2x=10=−30

 .


4x+5y12x+15y=3=9

 .


7x−y35x−5y=14=60
