At a craft fair, Jamal bought two wooden crafts and one needlework craft for a total of $21. At the same craft fair, Kenia bought two needwork crafts and four wooden crafts for a total of $28. Did Jamal and Kenia buy the same items? Why or why not? Assume no discounts were offered.
Systems with No or Infinitely Many Solutions Using Graphing
So far we have looked at linear systems of equations in which the lines always intersected in one, unique point. What happens if this is not the case? What could the graph of the two lines look like?
Let's graph the following systems.
\begin{align*}y &= 2x5\\
y &= 2x+4\end{align*}
In this problem both lines have the same slope but different \begin{align*}y\end{align*}
\begin{align*}2x3y &= 6\\
4x + 6y &= 12\end{align*}
In this problem both lines have the same slope and \begin{align*}y\end{align*}
\begin{align*} y = \frac{2}{3}x2 \ and \ y = \frac{2}{3}x2\end{align*}
When we graph them, they are one line, coincident, meaning they have all points in common. This means that there are an infinite number of solutions to the system. Because this system has at least one solution it is considered to be consistent.
Consistent systems are systems which have at least one solution. If the system has exactly one, unique solution then it is independent. If the system has infinite solutions, then it is called dependent.
Let's classify the following system:
\begin{align*}10x2y &= 10\\
y &= 5x5\end{align*}
Rearranging the first equation into slope intercept form we get \begin{align*}y=5x5\end{align*}
Examples
Example 1
Earlier, you were asked if Jamal and Kenia bought the same items.
The system of linear equations represented by this situation is: \begin{align*}2w + n &= 21\\
4w + 2n &= 28\end{align*}
If you graph these two linear equations on the same graph, there is no point of intersection. Therefore there is no solution and Jamal and Kenia couldn't have bought the same items.
Classify the following systems as consistent, inconsistent, independent or dependent. You may do this with or without graphing them. You do not need to find the unique solution if there is one.
Example 2
\begin{align*}5xy &= 15\\
x+5y &= 15\end{align*}5x−yx+5y=15=15
The first step is to rearrange both equations into slope intercept form so that we can compare these attributes.
\begin{align*}5xy &= 15 \rightarrow y=5x15\\
x+5y &= 15 \rightarrow y=  \frac{1}{5}x+3\end{align*}
The slopes are not the same so the lines are neither parallel nor coincident. Therefore, the lines must intersect in one point. The system is consistent and independent.
Example 3
\begin{align*}9x12y &= 24\\
3x+4y &= 8\end{align*}9x−12y−3x+4y=−24=8
Again, rearrange the equations into slope intercept form:
\begin{align*}9x12y = 24 & \rightarrow y=\frac{3}{4}x+2 \\
3x+4y = 8 & \rightarrow y=\frac{3}{4}x+2 \end{align*}
Now, we can see that both the slope and the \begin{align*}y\end{align*}
Example 4
\begin{align*}6x+8y &= 12\\
3x4y &= 10\end{align*}6x+8y−3x−4y=12=10
The equations can be rewritten as follows:
\begin{align*}6x+8y &= 12 \rightarrow y=  \frac{3}{4}x+\frac{3}{2} \\
3x4y &= 10 \rightarrow y=  \frac{3}{4}x\frac{5}{2} \end{align*}
In this system the lines have the same slope but different \begin{align*}y\end{align*}
Review
Describe the systems graphed below both algebraically (consistent, inconsistent, dependent, independent) and geometrically (intersecting lines, parallel lines, coincident lines).
Classify the following systems as consistent, inconsistent, independent or dependent. You may do this with or without graphing them. You do not need to find the unique solution if there is one.
 .

 \begin{align*}4xy &= 8\\
y &= 4x+3\end{align*}
4x−yy=8=4x+3
 \begin{align*}4xy &= 8\\
y &= 4x+3\end{align*}
 .

 \begin{align*}5x+y &= 10\\
y &= 5x+10\end{align*}
5x+yy=10=5x+10
 \begin{align*}5x+y &= 10\\
y &= 5x+10\end{align*}
 .

 \begin{align*}2x2y &= 11\\
y &= x+13\end{align*}
2x−2yy=11=x+13
 \begin{align*}2x2y &= 11\\
y &= x+13\end{align*}
 .

 \begin{align*}7x+3y &= 21\\
14x6y &= 42\end{align*}
−7x+3y14x−6y=−21=42
 \begin{align*}7x+3y &= 21\\
14x6y &= 42\end{align*}
 .

 \begin{align*}y &=  \frac{3}{5}x+1\\
3x+5y &= 5\end{align*}
y3x+5y=−35x+1=5
 \begin{align*}y &=  \frac{3}{5}x+1\\
3x+5y &= 5\end{align*}
 .

 \begin{align*}6xy &= 18\\
y &= \frac{1}{6}x+3\end{align*}
6x−yy=18=16x+3
 \begin{align*}6xy &= 18\\
y &= \frac{1}{6}x+3\end{align*}
In problems 1015 you will be writing your own systems. Your equations should be in standard form, \begin{align*}Ax+By=C\end{align*}
 Write a system which is consistent and independent.
 Write a system which is consistent and dependent.
 Write a system which is inconsistent.
 Write a system where the solution is (1, 2), one line is vertical and the second is horizontal.
 Write a system where the solution is (1, 2), one line is vertical or horizontal and the second is neither.
 Write a system where the solution is (1, 2) and neither line is vertical nor horizontal.
Answers for Review Problems
To see the Review Answers, open this PDF file and look for section 3.3.