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# Equations with Fractions

## Solve equations including fractional values

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Practice Equations with Fractions
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Equations with Fractions

In this year’s student election for president, there were two candidates. The winner received 13\begin{align*}\frac{1}{3}\end{align*} more votes than the loser. If there were 588 votes cast for president, how many votes did each of the two candidates receive?

### Guidance

When introducing fractions into an equation, the same rules for solving any equation apply. You need to keep the equations in balance by adding, subtracting, multiplying, or dividing on both sides of the equals sign in order to isolate the variable. The goal still remains to get your variable alone on one side of the equals sign with your constant terms on the other in order to solve for this variable.

With fractions, there is sometimes an added step of multiplying and dividing the equation by the numerator and denominator in order to solve for the variable. Or, if there are multiple fractions that do not have the same denominator, you must first find the least common denominator (LCD) before combining like terms.

#### Example A

Solve: 13t+5=1\begin{align*}\frac{1}{3}t+5=-1\end{align*}.

Solution:

Therefore \begin{align*}t = -18\end{align*}.

#### Example B

Solve: \begin{align*}\frac{3}{4}x-3=2\end{align*}.

Solution:

Therefore \begin{align*}x=\frac{20}{3}\end{align*}.

#### Example C

Solve: \begin{align*}\frac{2}{5}x-4=-\frac{1}{5}x+8\end{align*}.

Solution:

Therefore \begin{align*}x = 20\end{align*}.

#### Concept Problem Revisited

In this year’s student election for president, there were two candidates. The winner received \begin{align*}\frac{1}{3}\end{align*} more votes. If there were 588 votes cast for president, how many votes did each of the two candidates receive?

Let \begin{align*}x =\end{align*} votes for candidate 1 (the winner)

Let \begin{align*}y =\end{align*} votes for candidate 2

\begin{align*}x + y = 588\end{align*}

You must have only one variable in the equation in order to solve it. Let’s look at another relationship from the problem.

Now substitute into the original problem.

So candidate 2 received 252 votes. Candidate 1 must have received \begin{align*}588 - 252 = 336\end{align*} votes. Note that \begin{align*}336=252+\frac{1}{3}\cdot 252\end{align*}.

### Vocabulary

Fraction
A fraction is a part of a whole consisting of a numerator divided by a denominator. For example, if a pizza is cut into eight slices and you ate 3 slices, you would have eaten \begin{align*}\frac{3}{8}\end{align*} of the pizza. \begin{align*}\frac{3}{8}\end{align*} is a fraction with 3 being the numerator and 8 being the denominator.
Least Common Denominator
The least common denominator or lowest common denominator is the smallest number that all of the denominators (or the bottom numbers) can be divided into evenly. For example with the fractions \begin{align*}\frac{1}{2}\end{align*} and \begin{align*}\frac{1}{3}\end{align*}, the smallest number that both 2 and 3 will divide into evenly is 6. Therefore the least common denominator is 6.

### Guided Practice

1. Solve for x: \begin{align*}\frac{2}{3}x=12\end{align*}.

2. Solve for x: \begin{align*}\frac{3}{4}x-5=19\end{align*}.

3. Solve for x: \begin{align*}\frac{1}{4}w-3=\frac{2}{3}w\end{align*}.

1.

Therefore \begin{align*}x = 18\end{align*}.

2.

Therefore \begin{align*}x = 32\end{align*}.

3.

Since all the denominators are the same (12), we can simplify further:

Therefore \begin{align*}w = -\frac{36}{5}\end{align*}.

### Practice

Solve for the variable in each of the following equations.

1. \begin{align*}\frac{1}{3}p=5\end{align*}
2. \begin{align*}\frac{3}{7}j=8\end{align*}
3. \begin{align*}\frac{2}{5}b+4=6\end{align*}
4. \begin{align*}\frac{2}{3}x-2=1\end{align*}
5. \begin{align*}\frac{1}{3}x+3=-3\end{align*}
1. \begin{align*}\frac{1}{8}k+\frac{2}{3}=5\end{align*}
2. \begin{align*}\frac{1}{6}c+\frac{1}{3}=-2\end{align*}
3. \begin{align*}\frac{4}{5}x+3=\frac{2}{3}\end{align*}
4. \begin{align*}\frac{3}{4}x-\frac{2}{5}=\frac{1}{2}\end{align*}
5. \begin{align*}\frac{1}{4}t+\frac{2}{3}=\frac{1}{2}\end{align*}
1. \begin{align*}\frac{1}{3}x+\frac{1}{4}x=1\end{align*}
2. \begin{align*}\frac{1}{5}d+\frac{2}{3}d=\frac{5}{3}\end{align*}
3. \begin{align*}\frac{1}{2}x-1=\frac{1}{3}x\end{align*}
4. \begin{align*}\frac{1}{3}x-\frac{1}{2}=\frac{3}{4}x\end{align*}
5. \begin{align*}\frac{2}{3}j-\frac{1}{2}=\frac{3}{4}j+\frac{1}{3}\end{align*}

### Vocabulary Language: English

Denominator

Denominator

The denominator of a fraction (rational number) is the number on the bottom and indicates the total number of equal parts in the whole or the group. $\frac{5}{8}$ has denominator $8$.
fraction

fraction

A fraction is a part of a whole. A fraction is written mathematically as one value on top of another, separated by a fraction bar. It is also called a rational number.
Least Common Denominator

Least Common Denominator

The least common denominator or lowest common denominator of two fractions is the smallest number that is a multiple of both of the original denominators.