Scott and Brooke are organizing a fundraiser for their school. They are planning a pasta dinner, where adult tickets will cost $16 and kids' tickets will cost $8. Their goal is to make $2000. If they sell only adult tickets, how many must they sell to reach their goal? If they sell only kids' tickets, how many must they sell to reach their goal?

### Graphing a Line in Standard Form

When a line is in standard form, there are two different ways to graph it. The first approach is to change the equation to slope-intercept form and then graph it. The second approach is to use standard form to find the \begin{align*}x\end{align*}

Let's graph \begin{align*}5x - 2y = -15\end{align*}

Let’s use approach #1; change the equation to slope-intercept form.

\begin{align*}5x -2y &= -15\\
-2y &= -5x - 15\\
y &= \frac{5}{2}x + \frac{15}{2}\end{align*}

The \begin{align*}y-\end{align*}

Now, let's find the *x* and *y* intercepts of the equation \begin{align*}4x - 3x = 21\end{align*} and then graph this equation.

The other coordinate will be zero at these points. Therefore, for the \begin{align*}x-\end{align*}intercept, plug in zero for \begin{align*}y\end{align*} and for the \begin{align*}y-\end{align*}intercept, plug in zero for \begin{align*}x\end{align*}.

\begin{align*}4x - 3(0) &= 21 && 4(0) -3y = 21\\ 4x &= 21 && \quad \ \ -3y = 21\\ x &= \frac{21}{4} \ or \ 5.25 && \qquad \quad \ y = -7\end{align*}

Let's use approach #2 from above. Plot each intercept on their respective axes and draw a line to connect them.

### Examples

#### Example 1

Earlier, you were asked to find the number of adult and kids' tickets Scott and Brooke must sell to reach their goal.

The equation, in standard form, for the pasta dinner sales goal is \begin{align*}2000 = 16x + 8y\end{align*}. If they sell only adult tickets, we are looking for the *x*-intercept, so set *y* equal to zero.

\begin{align*}2000 = 16x + 8(0)\\ 2000 = 16x\\ x = 125\end{align*}

Therefore, they must sell 125 adult tickets to reach their goal.

If they sell only kids' tickets, we are looking for the *y*-intercept, so set *x* equal to zero.

\begin{align*}2000 = 16(0) + 8y\\ 2000 = 8y\\ y = 250\end{align*}

Therefore, they must sell 250 kids' tickets to reach their goal.

#### Example 2

Graph \begin{align*}4x + 6y = 18\end{align*} by changing it into slope-intercept form.

Change \begin{align*}4x + 6y = 18\end{align*} into slope-intercept form by solving for \begin{align*}y\end{align*}, then graph.

\begin{align*}4x +6y &= 18\\ 6y &= -4x + 18\\ y &= - \frac{2}{3}x + 3\end{align*}

#### Example 3

Graph \begin{align*}5x - 3y = 30\end{align*} by plotting the intercepts.

Substitute in zero for \begin{align*}x\end{align*}, followed by \begin{align*}y\end{align*} and solve each equation.

\begin{align*}5(0) - 3y &= 30 && 5x -3(0) = 30\\ -3y &= 30 && \qquad \quad 5x = 30\\ y &= -10 && \qquad \quad \ x = 6\end{align*}

Now, plot each on their respective axes and draw a line.

### Review

Graph the following lines by changing the equation to slope-intercept form.

- \begin{align*}-2x + y = 5\end{align*}
- \begin{align*}3x + 8y = 16\end{align*}
- \begin{align*}4x -2y = 10\end{align*}
- \begin{align*}6x + 5y = -20\end{align*}
- \begin{align*}9x - 6y = 24\end{align*}
- \begin{align*}x + 4y = -12\end{align*}

Graph the following lines by finding the intercepts.

- \begin{align*}2x + 3y = 12\end{align*}
- \begin{align*}-4x + 5y = 30\end{align*}
- \begin{align*}x - 2y = 8\end{align*}
- \begin{align*}7x + y = -7\end{align*}
- \begin{align*}6x + 10y = 15\end{align*}
- \begin{align*}4x -8y = -28\end{align*}
- \begin{align*}y=3\end{align*}
**Writing**Which method do you think is easier? Why?**Writing**Which method would you use to graph \begin{align*}x = -5\end{align*}? Why?

### Answers for Review Problems

To see the Review answers, open this PDF file and look for section 2.7.