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Horizontal and Vertical Asymptotes

Guidelines that graphs approach based on zeros and degrees in rational functions.

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Practice Horizontal and Vertical Asymptotes
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Asymtotes and Rational Functions

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Complete the table.
Word Definition
Vertical Asymtote ___________________________________________________________
___________ A horizontal line marking a specific value toward which the graph of a function may approach, but will generally not cross
Oblique Asymtote ___________________________________________________________
___________ function that is a ratio of two polynomials
End Behavior ___________________________________________________________
___________ A single point that is not possible on the graph of an otherwise continuous function 


Remember: Rational functions are defined as r(x)=\frac{p(x)}{q(x)} where p(x) and q(x) are polynomials

In your own words, what is an asymtote? ________________________________________


How do you find asymtotes?



To find a vertical asymtote:

  1. Set the denominator to 0

  2. Solve for x


This graph has two vertical asymtotes and one horizontal asymtote:


For more on vertical asymtotes, click here.



To find a horizontal asymtote:

  1. Put in standard form

  2. Remove all terms but the one where x has the largest exponent in numerator and denominator

  3. Three possibilities:

    1. If the degree of the numerator is smaller than the degree of the denominator, the horizontal asymptote crosses the y- axis at y=0

    2. If the degree of the denominator and the numerator are the same, the horizontal asymptote equals to the ratio of the leading coefficients

    3. If the degree of the numerator is larger than the degree of the denominator, then there is no horizontal asymptote

Horizontal asymtotes often indicate end behavior.  As the values of x get very large or very small, the graph of the rational function will approach (but not reach) the horizontal asymptote. If there is no horizontal asymtote the function will continue to ___________.
For more on horizontal asymtotes, click here.


If the degree of the numerator is one greater than the degree of the denominator, then there is an oblique asymtote. To find this asymtote:

  1. Divide the numerator and the denominator
  2. Re-write that function in the form \frac{f(x)}{D(x)}=Q(x)+\frac{R(x)}{D(x)} where Q(x) is the quotient and R(x) is the remainder
  3. Q(x) is the asymtote

Oblique asymtotes are diagonal lines:



For more on oblique asymtotes, click here.


Holes occur when one term in the numerator cancels with one term in the denominator. It is not an asymtote, it is merely a missing point.


For more on holes, click here


Identify the asymtotes and holes. Then sketch the graph.
  1. f(x) = \frac{x + 7}{3x - 10}
  2. f(x) = \frac{x^3 + 7x}{3x^2 - 6x + 13}
  3. f(x) = \frac{x^2 + 2x}{-4x + 8}
  4. f(x) = \frac{x + 14x - 10}{x^2 + x + 2}
  5. f(x) = \frac{4}{x^3 + 9x}
  6.  y = \frac{4x^3}{x^2 + 3}
  7.  y = \frac{(3x)(x + 8)}{x + 2}
  8. f(x) = \frac{x^3 + 4}{x^2}
  9. y = \frac{4x^4 - 2}{2x^3}
Factor the numerator and denominator, then set the denominator equal to zero and solve to find restrictions on the domain.
  1. y = \frac{x^2 + 3x - 10}{x - 2}
  2. f(x) = \frac{x^2 + 2x -24}{x - 4}
  3. f(x) = \frac{x^2 - 12x +32}{x - 4}
  4. y = \frac{x^2 +\frac{21}{20}}{x + \frac{4}{5}}
  5. y = \frac{x^2 +13x + 42}{x +7}

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