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# Intercepts by Substitution

## Graphing equations that form lines by finding x and y intercepts

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Intercepts by Substitution

Suppose the number of gallons of gas left in the tank of a car depends on the number of miles driven and can be represented by a linear equation. You know how much gas is in the tank when 0 miles have been driven, and you also know after how many miles you will have 0 gallons left in the tank. Could you graph the linear equation?

### Finding Intercepts by Using Substitution

Graphing solutions to an equation of two variables using a table can be time-consuming. Fortunately, there are several ways to make graphing solutions easier. This Concept will focus on graphing a line by finding its intercepts

In geometry, there is a postulate that states, “Two points determine a line.” Therefore, to draw any line, all you need is two points. One way is to find its intercepts.

An intercept is the point at which a graphed equation crosses an axis.

The x\begin{align*}x-\end{align*}intercept is an ordered pair at which the line crosses the x\begin{align*}x-\end{align*}axis (the horizontal axis). Its ordered pair has the form (x,0)\begin{align*}(x,0)\end{align*}.

The y\begin{align*}y-\end{align*}intercept is an ordered pair at which the line crosses the y\begin{align*}y-\end{align*}axis (the vertical axis). Its ordered pair has the form (0,y)\begin{align*}(0,y)\end{align*}.

By finding the intercepts of an equation, you can quickly graph all the possible solutions to the equation.

Remember that the Substitution Property allows the replacement of a variable with a numerical value or another expression. You can use this property to help find the intercepts of an equation.

#### Let's graph the following linear equations using its intercepts:

1. 2x+3y=6\begin{align*}2x+3y=-6\end{align*}

The x\begin{align*}x-\end{align*}intercept has the ordered pair (x,0)\begin{align*}(x,0)\end{align*}. Therefore, the y\begin{align*}y-\end{align*}coordinate has a value of zero. By substituting zero for the variable of y\begin{align*}y\end{align*}, the equation becomes:

2x+3(0)=6\begin{align*}2x+3(0)=-6\end{align*}

Continue solving for x\begin{align*}x\end{align*}:

2x+02xx=6=6=3\begin{align*}2x+0& =-6\\ 2x& =-6\\ x& =-3\end{align*}

The x\begin{align*}x-\end{align*}intercept has an ordered pair of (–3, 0).

Repeat the process to find the y\begin{align*}y-\end{align*}intercept. The ordered pair of the y\begin{align*}y-\end{align*}intercept is (0,y)\begin{align*}(0,y)\end{align*}. Using substitution:

2(0)+3y3yy=6=6=2\begin{align*}2(0)+3y& =-6\\ 3y& =-6\\ y& =-2\end{align*}

The y\begin{align*}y-\end{align*}intercept has the ordered pair (0, –2).

To graph the line formed by the solutions of the equation 2x+3y=6\begin{align*}2x+3y=-6\end{align*}, graph the two intercepts and connect them with a straight line.

1. 4x2y=8\begin{align*}4x-2y=8\end{align*}

Determine the x\begin{align*}x-\end{align*}intercept by substituting zero for the variable y\begin{align*}y\end{align*}.

4x2(0)4xx=8=8=2\begin{align*}4x-2(0)& =8\\ 4x& =8\\ x& =2\end{align*}

The ordered pair of the x\begin{align*}x-\end{align*}intercept is (2, 0). By repeating this process, you'll find the y\begin{align*}y-\end{align*}intercept has the ordered pair (0, –4). Graph these two ordered pairs and connect them with a line.

1. x2y=10\begin{align*}x-2y=10\end{align*}

First, find the intercepts by substituting in zero for x\begin{align*}x\end{align*} and y\begin{align*}y\end{align*}:

Substitute in zero for x.Simplify.Solve for y.(0)2y2yy=10=10=5\begin{align*} \text{Substitute in zero for x.} && (0)-2y &=10 \\ \text{Simplify.} && -2y&=10 \\ \text{Solve for y.}&& y&=-5 \end{align*}

This means that the y\begin{align*}y\end{align*}-intercept is at the point (0,-5).

Substitute in zero for y.Solve for x.x6(0)x=10=10\begin{align*} \text{Substitute in zero for y.} && x-6(0) &=10 \\ \text{Solve for x.}&& x&=10 \end{align*}

This means that the x\begin{align*}x\end{align*}-intercept is at the point (10,0).

### Examples

#### Example 1

Earlier, you were asked to suppose that the number of gallons left in the tank of a car depends on the number of miles driven and can be represented by a linear equation. Could you graph the linear equation if you know how much gas is in the tank when 0 miles have been driven and how many miles it will take to have 0 gallons left in the tank?

Yes, you can draw a line with any two points. In this case, the amount of gas in the tank when 0 miles have been driven will be the y\begin{align*}y-\end{align*}intercept while the number of miles it will take to have 0 gallons left in the tank will be the x\begin{align*}x-\end{align*}intercept. With these two points, you can draw the line that represents the linear equation.

#### Example 2

Find the intercepts and use them to graph y=2x+8\begin{align*}y=-2x+8\end{align*}.

Substitute in zero for x\begin{align*}x\end{align*} and y\begin{align*}y\end{align*}, in order to find the intercepts.

Substitute in zero for x.Solve for y.yy=2(0)+8=8\begin{align*} \text{Substitute in zero for x.} && y&=-2(0)+8 \\ \text{Solve for y.}&& y&=8 \end{align*}

This means that the y\begin{align*}y\end{align*}-intercept is at the point (0,8).

Substitute in zero for y.Solve for x.0x=2x+8=4\begin{align*} \text{Substitute in zero for y.} && 0&=-2x+8 \\ \text{Solve for x.}&& x&=4 \end{align*}

This means that the x\begin{align*}x\end{align*}-intercept is at the point (4,0).

### Review

1. Define intercept.
2. What is the ordered pair for an x\begin{align*}x-\end{align*}intercept?

Find the intercepts for the following equations using substitution.

1. y=3x6\begin{align*}y=3x-6\end{align*}
2. y=2x+4\begin{align*}y=-2x+4\end{align*}
3. y=14x21\begin{align*}y=14x-21\end{align*}
4. y=73x\begin{align*}y=7-3x\end{align*}
1. Which intercept does a vertical line have?
2. Does the equation y=5\begin{align*}y=5\end{align*} have both an x\begin{align*}x-\end{align*}intercept and a y\begin{align*}y-\end{align*}intercept? Explain your answer.
3. Write an equation having only an x\begin{align*}x-\end{align*}intercept at (–4, 0).
4. How many equations can be made with only one intercept at (0, 0)? Hint: Draw a picture to help you.

Mixed Review

For 11-12, determine whether each ordered pair is a solution to the equation.

1. 5x+2y=23;(7,6)\begin{align*}5x+2y=23;(7,-6)\end{align*}and (3, 4)
2. 3a2b=6;(0,3)\begin{align*}3a-2b=6;(0,3)\end{align*}and\begin{align*}\left (\frac{5}{3},\frac{-1}{2}\right )\end{align*}.
3. Graph the solutions to the equation \begin{align*}x=-5\end{align*}.
4. Solve: \begin{align*}\frac{4}{5} k-16=-\frac{1}{4}\end{align*}.
5. Is the following relation a function? \begin{align*}\left \{(-1,1),(0,0),(1,1),(2,3),(0,6)\right \}\end{align*}
6. Using either a finite set of counting numbers, whole numbers, or integers, how would you describe the domain of the following situation: The number of donuts purchased at a coffee shop on a particular day?
7. Find the percent of change: Old price = $1,299; new price =$1,145.

To see the Review answers, open this PDF file and look for section 4.5.

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### Vocabulary Language: English Spanish

$X$-intercept

An ordered pair at which the line crosses the $x-$axis (the horizontal axis). Its ordered pair has the form $(x,0)$.

$Y$-intercept

The $y-$intercept is an ordered pair at which the line crosses the $y-$axis (the vertical axis). Its ordered pair has the form $(0,y)$.

Intercept

The intercepts of a curve are the locations where the curve intersects the $x$ and $y$ axes. An $x$ intercept is a point at which the curve intersects the $x$-axis. A $y$ intercept is a point at which the curve intersects the $y$-axis.

Intercept Method

The intercept method is a way of graphing a linear function by using the coordinates of the $x$ and $y$-intercepts. The graph is drawn by plotting these coordinates on the Cartesian plane and then joining them with a straight line.