Xpress Taxi Service charges $1.50 per minute traveled minus $0.25 per minute spent in stopped traffic. You only have $10 in your wallet, so that is the maximum amount you can spend on your ride. In which quadrant(s) would the graph represented by this situation fall?

### Graphing Inequalities

Graphing linear inequalities is very similar to graphing lines. First, you need to change the inequality into slope-intercept form. At this point, we will have a couple of differences. If the inequality is in the form \begin{align*}y < mx + b\end{align*}

The second difference is the shading. Because these are inequalities, not just the line is the solution. Depending on the sign, there will be shading above or below the line. If the inequality is in the form \begin{align*}y < mx + b\end{align*}

If the inequality is in the form \begin{align*}y > mx + b\end{align*}

Let's graph the following inequalities.

- \begin{align*}4x -2y < 10\end{align*}
4x−2y<10

First, change the inequality into slope-intercept form. Remember, that if you have to divide or multiply by a negative number, you must flip the inequality sign.

Now, graph the inequality as if it was a line. Plot \begin{align*}y = 2x - 5\end{align*}

Now, we need to determine the shading. You can use one of two methods to do this. The first way is to use the graphs and forms from above. The equation, in slope-intercept form, matches up with the purple dashed line and shading. Therefore, we should shade above the dashed blue line.

The alternate method would be to test a couple of points to see if they work. If a point is true, then the shading is over that side of the line. If we pick (-5, 0), the inequality yields \begin{align*}-20 < 10\end{align*}

- \begin{align*}y \le - \frac{2}{3}x + 6\end{align*}
y≤−23x+6

This inequality is already in slope-intercept form. So, graph the line, which will be solid, and then determine the shading. Looking at the example graphs above, this inequality should look like the red inequality, so shade below the line.

Test a point to make sure our shading is correct. An easy point in the shaded region is (0, 0). Plugging this into the inequality, we get \begin{align*}0 \le 6\end{align*}

Let's determine the linear inequality that is graphed below.

Find the equation of the line portion just like you've done before. The given points on the line are (0, 8) and (6, 2) (from the points drawn on the graph). This means that the \begin{align*}y-\end{align*}

\begin{align*}^*\end{align*}

### Examples

#### Example 1

Earlier, you were asked to find which quadrant(s) into which the graph represented by the situation would fall.

To solve this taxi cab problem, we must first set up an inequality to represent the situation.

\begin{align*}1.5x - 0.25y \le 10\end{align*}

You can't travel a negative number of miles or sit in traffic for a negative number of minutes. Therefore both *x* and *y* must have zero or positive values. When both *x* and *y* are positive, the graph occurs in the first quadrant only. Graph the function to check this answer.

#### Example 2

Graph \begin{align*}3x - 4y > 20\end{align*}

First, change the inequality into slope-intercept form.

\begin{align*}3x -4y & > 20\\
-4y & > -3x + 20\\
y & < \frac{3}{4}x -5\end{align*}

Now, we need to determine the type of line and shading. Because the sign is “<,” the line will be dashed and we will shade below.

Test a point in the shaded region to make sure we are correct. If we test (6, -6) in the original inequality, we get \begin{align*}42 > 20\end{align*}

#### Example 3

Graph \begin{align*}x < -1\end{align*}

To graph this line on the \begin{align*}x-y\end{align*}*dashed* line at -1. Then, the shading will be to the left of the dashed line because that is where \begin{align*}x\end{align*}

#### Example 4

What is the equation of the linear inequality?

Looking at the line, the \begin{align*}y-\end{align*}

### Review

Graph the following inequalities.

- \begin{align*}y > x -5\end{align*}
y>x−5 - \begin{align*}3x -2y \ge 4\end{align*}
3x−2y≥4 - \begin{align*}y < -3x + 8\end{align*}
y<−3x+8 - \begin{align*}x +4y \le 16\end{align*}
x+4y≤16 - \begin{align*}y < -2\end{align*}
y<−2 - \begin{align*}y < - \frac{1}{2}x - 3\end{align*}
y<−12x−3 - \begin{align*}x \ge 6\end{align*}
x≥6 - \begin{align*}8x +4y \ge -20\end{align*}
8x+4y≥−20 - \begin{align*}-4x + y \le 7\end{align*}
−4x+y≤7 - \begin{align*}5x -3y \ge -24\end{align*}
5x−3y≥−24 - \begin{align*}y > 5x\end{align*}
y>5x - \begin{align*}y \le 0\end{align*}
y≤0

Determine the equation of each linear inequality below.

### Answers for Review Problems

To see the Review answers, open this PDF file and look for section 2.11.