# Linear Systems with Multiplication

## Multiply as needed to set coefficients opposite, add to cancel variables

%
Progress

MEMORY METER
This indicates how strong in your memory this concept is
Progress
%
Linear Systems with Multiplication

Suppose that you want to buy some guppies and rainbowfish for your aquarium. If you buy 10 guppies and 15 rainbowfish, it will cost you $90, and if you buy 15 guppies and 10 rainbowfish, it will cost you$85. How much do guppies and rainbowfish each cost? Can you set up a system of equations to find out? How would you go about solving it?

### Multiplying Linear Systems

The previous Concepts have provided three methods to solve systems: graphing, substitution, and elimination through addition and subtraction. As stated in each Concept, these methods have strengths and weaknesses. Below is a summary.

Graphing

A good technique to visualize the equations and when both equations are in slope-intercept form.

Solving a system by graphing is often imprecise and will not provide exact solutions.

Substitution

Works particularly well when one equation is in standard form and the second equation is in slope-intercept form.

Can be difficult to use substitution when both equations are in standard form.

Works well when both equations are in standard form and the coefficients of one variable are additive inverses.

Can be difficult to use if one equation is in standard form and the other is in slope-intercept form.

Addition or subtraction does not work if the coefficients of one variable are not additive inverses.

Although elimination by addition and subtraction does not work without additive inverses, you can use the Multiplication Property of Equality and the Distributive Property to create additive inverses.

Multiplication Property and Distributive Property:

If , then and

While this definition box may seem complicated, it really states that you can multiply the entire equation by a particular value and then use the Distributive Property to simplify. The value you are multiplying by is called a scalar.

#### Let's solve the following systems of equations:

Neither variable has additive inverse coefficients. Therefore, simply adding or subtracting the two equations will not cancel either variable. However, there is a relationship between the coefficients of the variable.

By multiplying the second equation by the scalar 2, you will create additive inverses of . You can then add the equations.

To find the value, use the Substitution Property in either equation.

The solution to this system is .

Not only does neither variable have additive inverse coefficients, but there also isn't a relationship between the coefficients of either variable. In other words, the coefficients of each variable do not share any common factors. Therefore, we can try to eliminate either variable first. We will show how to solve this problem by eliminating .

In order to make have the same coefficient in each equation, we must multiply one equation by the coefficient of in the other equation. We need to multiply the first equation by 2 and the second equation by 3. If we make one of those numbers negative, we can easily eliminate . It does not matter which one we make negative:

To find the value, use the Substitution Property in either equation.

The solution to this system is .

#### Now, let's solve the following real-world problem using systems of equations:

Andrew and Anne both use the I-Haul truck rental company to move their belongings from home to the dorm rooms on the University of Chicago campus. I-Haul has a charge per day and an additional charge per mile. Andrew travels from San Diego, California, a distance of 2,060 miles in five days. Anne travels 880 miles from Norfolk, Virginia, and it takes her three days. If Anne pays $840 and Andrew pays$1,845.00, what does I-Haul charge:

1. per day?
2. per mile traveled?

Begin by writing a system of linear equations: one to represent Anne and the second to represent Andrew. Let amount charged per day and amount charged per mile.

There are no relationships seen between the coefficients of the variables. Instead of multiplying one equation by a scalar, we must multiply both equations by the least common multiple.

The least common multiple is the smallest value that is divisible by two or more quantities without a remainder.

Suppose we wanted to eliminate the variable because the numbers are smaller to work with. The coefficients of must be additive inverses of the least common multiple.

4. A baker sells plain cakes for $7 or decorated cakes for$11. On a busy Saturday, the baker started with 120 cakes, and sold all but three. His takings for the day were $991. How many plain cakes did he sell that day, and how many were decorated before they were sold? 5. Twice John’s age plus five times Claire’s age is 204. Nine times John’s age minus three times Claire’s age is also 204. How old are John and Claire? #### Quick Quiz 1. Is (–3, –5) a solution to the system ? 2. Solve the system: . 3. Joann and Phyllis each improved their flower gardens by planting daisies and carnations. Joann bought 10 daisies and 4 carnations and paid$52.66. Phyllis bought 3 daisies and 6 carnations and paid $43.11 How much is each daisy? How much is each carnation? 4. Terry’s Rental charges$49 per day and $0.15 per mile to rent a car. Hurry-It-Up charges a flat fee of$84 per day to rent a car. Write these two companies' charges in equation form and use the system to determine at what mileage the two companies will charge the same for a one-day rental.

To see the Review answers, open this PDF file and look for section 7.5.

### Notes/Highlights Having trouble? Report an issue.

Color Highlighted Text Notes

### Vocabulary Language: English Spanish

TermDefinition
Least Common Multiple The least common multiple of two numbers is the smallest number that is a multiple of both of the original numbers.
elimination method The purpose of the elimination method to solve a system is to cancel, or eliminate, a variable by either adding or subtracting the two equations. Sometimes the equations must be multiplied by scalars first, in order to cancel out a variable.
elimination The elimination method for solving a system of two equations involves combining the two equations in order to produce one equation in one variable.
Least Common Denominator The least common denominator or lowest common denominator of two fractions is the smallest number that is a multiple of both of the original denominators.