What if you were given the coordinates of two points like (4, 1) and (0, -3)? How could you find the midpoint of the line segment joining the two points? After completing this Concept, you'll be able to find the midpoint of any line segment using the Midpoint Formula.

### Watch This

CK-12 Foundation: The Midpoint Formula

For a graphic demonstration of the midpoint formula, watch this video:

PatrickJMT: The Midpoint Formula

### Guidance

In the last concept, you saw how to find the distance between two points. In this concept, you will learn how to find the point exactly half way between two points.

#### Example A

*Find the coordinates of the point that is in the middle of the line segment connecting the points \begin{align*}A = (-7, -2)\end{align*} A=(−7,−2) and \begin{align*}B = (3, -8)\end{align*}.*

**Solution**

Let’s start by graphing the two points:

We see that to get from point \begin{align*}A\end{align*} to point \begin{align*}B\end{align*} we move 6 units down and 10 units to the right.

In order to get to the point that is halfway between the two points, it makes sense that we should move half the vertical distance and half the horizontal distance—that is, 3 units down and 5 units to the right from point \begin{align*}A\end{align*}.

The midpoint is \begin{align*}M = (-7 +5, -2 - 3) = (-2, -5)\end{align*}.

**The Midpoint Formula**

We now want to generalize this method in order to find a formula for the midpoint of a line segment.

Let’s take two general points \begin{align*}A = (x_1, y_1)\end{align*} and \begin{align*}B = (x_2, y_2)\end{align*} and mark them on the coordinate plane:

We see that to get from \begin{align*}A\end{align*} to \begin{align*}B\end{align*}, we move \begin{align*}x_2 - x_1\end{align*} units to the right and \begin{align*}y_2 - y_1\end{align*} units up.

In order to get to the half-way point, we need to move \begin{align*}\frac{x_2-x_1}{2}\end{align*} units to the right and \begin{align*}\frac{y_2-y_1}{2}\end{align*} up from point \begin{align*}A\end{align*}. Thus the midpoint \begin{align*}M\end{align*} is at \begin{align*}\left(x_1+\frac{x_2-x_1}{2}, y_1+\frac{y_2-y_1}{2}\right)\end{align*}.

This simplifies to \begin{align*}M =\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)\end{align*}. This is the **Midpoint Formula:**

The midpoint of the line segment connecting the points \begin{align*}(x_1, y_1)\end{align*} and \begin{align*}(x_2, y_2)\end{align*} is \begin{align*}\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)\end{align*}.

It should hopefully make sense that the midpoint of a line is found by taking the average values of the \begin{align*}x\end{align*} and \begin{align*}y-\end{align*}values of the endpoints.

#### Example B

*Find the midpoint between the following points.*

a) (-10, 2) and (3, 5)

b) (3, 6) and (7, 6)

**Solution**

Let’s apply the Midpoint Formula: \begin{align*}\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)\end{align*}

a) the midpoint of (-10, 2) and (3, 5) is \begin{align*}\left(\frac{-10+3}{2}, \frac{2+5}{2}\right)=\left(\frac{-7}{2}, \frac{7}{2}\right)=\underline{\underline{(-3.5,3.5)}}\end{align*}

b) the midpoint of (3, 6) and (7, 6) is \begin{align*}\left(\frac{3+7}{2}, \frac{6+6}{2}\right)=\left(\frac{10}{2}, \frac{12}{2}\right)=\underline{\underline{(5,6)}}\end{align*}

#### Example C

*A line segment whose midpoint is (2, -6) has an endpoint of (9, -2). What is the other endpoint?*

**Solution**

In this problem we know the midpoint and we are looking for the missing endpoint.

The midpoint is (2, -6).

One endpoint is \begin{align*}(x_1, x_2) = (9, -2)\end{align*}.

Let’s call the missing point \begin{align*}(x, y)\end{align*}.

We know that the \begin{align*}x-\end{align*}coordinate of the midpoint is 2, so: \begin{align*}2=\frac{9+x_2}{2} \Rightarrow 4=9+x_2 \Rightarrow x_2=-5\end{align*}

We know that the \begin{align*}y-\end{align*}coordinate of the midpoint is -6, so:

\begin{align*}-6=\frac{-2+y_2}{2} \Rightarrow -12=-2+y_2 \Rightarrow y_2=-10\end{align*}

The missing endpoint is **(-5, -10).**

Here’s another way to look at this problem: To get from the endpoint (9, -2) to the midpoint (2, -6), we had to go 7 units left and 4 units down. To get from the midpoint to the other endpoint, then, we would need to go 7 more units left and 4 more units down, which takes us to (-5, -10).

Watch this video for help with the Examples above.

CK-12 Foundation: The Midpoint Formula

### Guided Practice

*Find the midpoint between the points (4, -5) and (-4, 5).*

**Solution**

Let’s apply the Midpoint Formula: \begin{align*}\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)\end{align*}

The midpoint of (4, -5) and (-4, 5) is \begin{align*}\left(\frac{4-4}{2}, \frac{-5+5}{2}\right)=\left(\frac{0}{2}, \frac{0}{2}\right)=\underline{\underline{(0,0)}}\end{align*}

### Explore More

Find the midpoint of the line segment joining the two points.

- (3, -4) and (6, 1)
- (2, -3) and (2, 4)
- (4, -5) and (8, 2)
- (1.8, -3.4) and (-0.4, 1.4)
- (5, -1) and (-4, 0)
- (10, 2) and (2, -4)
- (3, -3) and (2, 5)
- An endpoint of a line segment is (4, 5) and the midpoint of the line segment is (3, -2). Find the other endpoint.
- An endpoint of a line segment is (-10, -2) and the midpoint of the line segment is (0, 4). Find the other endpoint.
- Find a point that is the same distance from (4, 5) as it is from (-2, -1), but is
*not*the midpoint of the line segment connecting them.

### Answers for Explore More Problems

To view the Explore More answers, open this PDF file and look for section 11.12.