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# One-Step Equations and Inverse Operations

## Add and subtract like terms as a step to solve equations.

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Practice One-Step Equations and Inverse Operations

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Equations with Variables on One Side

### Introduction

[Figure1]

Erin, Jillian, Stephanie and Jacob went to the movies. The total bill for the tickets and snacks came to 72.00. What is an equation that represents this situation? How much should each teen pay to split the bill evenly? __________________________________________________________________________________ _________________________________________________________________________________ __________________________________________________________________________________ ### Guidance When solving any equation, your job is to find the value for the letter that makes the equation _________. Solving equations with variables on one side can be done with the help of models such as a balance or algebra tiles. When solving equations with variables on one side of the equation there is one main rule to follow: ____________________________ ________________________________ of the equals sign. For example, if you add a number to the left side of an equals sign, you must add the same number to the right side of the equals sign. #### Example A 5a+2=17\begin{align*}5a + 2 = 17\end{align*} Solution: The problem can be solved if you think about the problem in terms of a balance. You know that the two sides are ________ so the balance has to stay horizontal. You can place each side of the equation on each side of the balance. In order to solve the equation, you have to get the variable a\begin{align*}a\end{align*} all by itself. Always remember that you need to keep the balance ______________. This means that whatever you do to one side of the equation, you have to do to the other side. First subtract 2 from both sides to get rid of the 2 on the left. Since 5 is multiplied by a\begin{align*}a\end{align*}, you can get a\begin{align*}a\end{align*} by itself (or isolate it) by dividing by 5. Remember that whatever you do to one side, you have to do to the other. If you simplify this expression, you get: Therefore a=3\begin{align*}a = 3\end{align*}. You can check your answer to see if you are correct by substituting your answer back into the original equation. 5a+25(3)+215+217=17=17=17=17 \begin{align*}5a + 2 &= 17\\ 5({\color{red}3}) + 2 &= 17\\ 15 + 2 &= 17\\ 17 &= 17 \ \ \end{align*} #### Example B 7b7=42\begin{align*}7b - 7 = 42\end{align*} Solution: Again, you can solve the problem if you think about the problem in terms of a balance (or a seesaw). You know that the two sides are equal so the balance has to stay horizontal. You can place each side of the equation on each side of the balance. In order to solve the equation, you have to get the variable b\begin{align*}b\end{align*} all by itself. Always remember that you need to keep the balance horizontal. This means that whatever you do to one side of the equation, ______________________________________________________. First add ___ from both sides to get rid of the ___ on the left. Since 7 is multiplied by b\begin{align*}b\end{align*}, you can get b\begin{align*}b\end{align*} by itself (or isolate it) by dividing by 7. Remember that whatever you do to one side, you have to do to the other. If you simplify this expression, you get: Therefore b=7\begin{align*}b = 7\end{align*}. You can check your answer to see if you are correct. 7b77(7)749742=42=42=42=42 \begin{align*}7b - 7 &= 42\\ 7({\color{red}7}) - 7 &= 42\\ 49 - 7 &= 42\\ 42 &= 42 \ \ \end{align*} This same method can be extended by using algebra tiles. If you let rectangular tiles represent the _________, square tiles represent one ______, green tiles represent positives numbers, and white tiles represent the negative numbers, you can solve the equations using an alternate method. The green algebra x\begin{align*}x-\end{align*}tiles represent variables; therefore, there are 3 c\begin{align*}c\end{align*} blocks for the equation. The other green blocks represent the numbers or constants. There is a 2 on the left side of the equation so there are 2 square green blocks. There is an 11 on the right side of the equation so there are 11 square green blocks on the right side of the equation. Solution: To solve, add two negative tiles to the right and left hand sides. The same rule applies to this problem as to all of the previous problems. Whatever you do to one side you have to do to the other. This leaves us with the following: You can reorganize these to look like the following: Organizing the remaining algebra tiles allows us to realize the answer to be x=3\begin{align*}x = 3\end{align*} or for your example c=3\begin{align*}c = 3\end{align*}. Let’s do your check as with the previous two problems. 3c+23(3)+29+211=11=11=11=11 \begin{align*}3c + 2 &= 11\\ 3({\color{red}3}) + 2 &= 11\\ 9 + 2 &= 11\\ 11 &= 11 \ \ \end{align*} #### Concept Problem Revisited There are four teens going to the movies (Erin, Jillian, Stephanie, and Jacob). The total bill was72.00. Therefore your equation ___________. you divide by ______ to find your answer.

Show work__

Therefore each teen will have to pay _________ for their movie ticket and snack.

### Vocabulary

Constant
A constant is a numerical ___________. For example in the equation 4x+72=0\begin{align*}4x + 72 = 0\end{align*}, the ____ is a constant.
Equation
An equation is a mathematical statement with expressions separated by an _________________.
Numerical Coefficient
In mathematical equations, the numerical coefficients are the numbers associated with the variables. For example, with the expression 4x\begin{align*}4x\end{align*}, 4 is the ____________________ and x\begin{align*}x\end{align*} is the _____________
Variable
A variable is an unknown quantity in a ________________________. It is represented by a letter. It is sometimes referred to as the ___________ coefficient.

### Guided Practice

1. Use a model solve for the variable in the equation x5=12\begin{align*}x-5=12\end{align*}.

2. Use a different model to solve for the variable in the equation 3y+9=12\begin{align*}3y+9=12\end{align*}.

3. Solve for x\begin{align*}x\end{align*} in the equation 3x2x+16=3\begin{align*}3x-2x+16=-3\end{align*}.

[Figure2]

Practice

Use the models that you have learned to solve for the variables in the following problems. Write problems and show work on a seperate  sheet of paper

1. a+3=5\begin{align*}a+3=-5\end{align*}
2. 2b1=5\begin{align*}2b-1=5\end{align*}
3. 4c3=9\begin{align*}4c-3=9\end{align*}
4. 2d=3\begin{align*}2-d=3\end{align*}
5. 43e=2\begin{align*}4-3e=-2\end{align*}
1. x+3=14\begin{align*}x+3=14\end{align*}
2. 2y7=5\begin{align*}2y-7=5\end{align*}
3. 3z+6=9\begin{align*}3z+6=9\end{align*}
4. 5+3x=3\begin{align*}5+3x=-3\end{align*}
5. 2x+2=4\begin{align*}2x+2=-4\end{align*}
1. 4x+13=5\begin{align*}-4x+13=5\end{align*}
2. 3x5=22\begin{align*}3x-5=22\end{align*}
3. 112x=5\begin{align*}11-2x=5\end{align*}
4. 2x4=4\begin{align*}2x-4=4\end{align*}

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