What if you needed to solve the quadratic equation x2+x−5=0 in order to determine the width of a rectangular map? You graphed the function f(x)=x2+x−5, but from the graph you can only tell the approximate width, and you want a more precise answer. In this Concept, you'll learn to use the quadratic formula to solve quadratic equations like the one representing this situation so that you can get exact solutions to the equations.
Guidance
Previous Concepts have presented three methods to solve a quadratic equation:
 By graphing to find the zeros;
 By solving using square roots; and
 By using completing the square to find the solutions
This Concept will present a fourth way to solve a quadratic equation: using the quadratic formula.
History of the Quadratic Formula
As early as 1200 BC, people were interested in solving quadratic equations. The Babylonians solved simultaneous equations involving quadratics. In 628 AD, Brahmagupta, an Indian mathematician, gave the first explicit formula to solve a quadratic equation. The quadratic formula was written as it is today by the Arabic mathematician AlKhwarizmi. It is his name upon which the word “Algebra” is based.
The solution to any quadratic equation in standard form, 0=ax2+bx+c, is:
x=−b±b2−4ac−−−−−−−√2a
Example A
Solve x2+10x+9=0 using the quadratic formula.
Solution:
We know from the last Concept the answers are x=−1 or x=−9.
By applying the quadratic formula and a=1,b=10, and c=9, we get:
xxxxxx=−10±(10)2−4(1)(9)−−−−−−−−−−−−√2(1)=−10±100−36−−−−−−−√2=−10±64−−√2=−10±82=−10+82 or x=−10−82=−1 or x=−9
Example B
Solve −4x2+x+1=0 using the quadratic formula.
Solution:
Quadratic formula:Plug in the values a=−4,b=1,c=1:Simplify:Separate the two options:Solve:xxxxx=−b±b2−4ac−−−−−−−√2a=−1±(1)2−4(−4)(1)−−−−−−−−−−−−√2(−4)=−1±1+16−−−−−√−8=−1±17−−√−8=−1+17−−√−8 and x=−1−17−−√−8≈−.39 and x≈.64
Example C
Solve 8t2+10t+3=0 using the quadratic formula.
Solution:
Quadratic formula:Plug in the values a=8,b=10,c=3:Simplify:Separate the two options:Separate the two options:Solve:xxxxxx=−b±b2−4ac−−−−−−−√2a=−10±(10)2−4(8)(3)−−−−−−−−−−−−√2(8)=−10±100+96−−−−−−−√16=−10±196−−−√16=−10+196−−−√16 and x=−10−196−−−√16=−10+1416 and x=−10−1416=14 and x=−32
Guided Practice
Solve 3k2+11k=4 using the quadratic formula.
Solution:
First, we must make it so one side is equal to zero:
3k2+11k=4⇒3k2+11k−4=0
Now it is in the correct form for using the quadratic formula.
Quadratic formula:Plug in the values a=3,b=11,c=−4:Simplify:Separate the two options:Separate the two options:Solve:xxxxxx=−b±b2−4ac−−−−−−−√2a=−11±(11)2−4(3)(−4)−−−−−−−−−−−−−√2(3)=−11±121+48−−−−−−−√6=−11±169−−−√6=−11+169−−−√6 and x=−11−169−−−√6=−11+136 and x=−11−136=13 and x=−4
 What is the quadratic formula? When is the most appropriate situation to use this formula?
 When was the first known solution of a quadratic equation recorded?
Solve the following quadratic equations using the quadratic formula.

x2+4x−21=0

x2−6x=12

3x2−12x=38

2x2+x−3=0

−x2−7x+12=0

−3x2+5x=0

4x2=0

x2+2x+6=0
Khan Academy
https://www.khanacademy.org/math/trigonometry/polynomial_and_rational/quad_formula_tutorial/e/quadratic_equation