Have you ever planted a garden? Take a look at this dilemma.

Mario and his brother have built a garden bed with an area of 144 square feet. If the shape of the garden is a square, then what is the length of one side of the garden? What is the perimeter of this garden?

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To figure this out, you will need to understand how to solve equations that involve radicals. This Concept will teach you how to find success.
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### Guidance

Do you remember
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exponents?
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An exponent is a number that raises a base to a power.
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We can recognize exponents because they are little numbers next to larger numbers. The little number is the
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exponent
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and the large number is the

**. The exponent tells you how many times to multiply a base by itself.**

*base*\begin{align*}7^2\end{align*}

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This means that we multiply the base of 7 by itself two times. This is how we evaluate a power.
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@$\begin{align*}7 \times 7 = 49\end{align*}@$

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This is the answer.
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We can also perform an operation that is the opposite of raising a number to a power; we can find the root of a number. This is an expression that is the opposite of raising a number to a power. We call it a
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root
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**or a**

*radical.*When you see a number that looks like this, @$\begin{align*}\sqrt{16}\end{align*}@$ , this means that we are looking for the root of the number that is inside the radical symbol.

In this case, the answer would be 4 because 4 x 4 = 16.

We can also see radicals in an equation. When we have a radical in an equation, we can solve the equation by using what we have learned about squares and square roots. Let’s take a look.

@$\begin{align*}x^2=100\end{align*}@$

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To solve this equation let’s think about what we know. We know that a value times itself is going to equal 100. Up until this point we have solved equations by using the inverse operation. We can use that again here too. The variable is squared; we want to get it by itself by using an inverse operation. The inverse of squaring a number is to find the square root of the number. Let’s see what happens if we find the square root of both sides of the equation.
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@$\begin{align*}\sqrt{x^2}= \sqrt{100}\end{align*}@$

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The exponent 2 and the radical cancel each other out because they are inverses of each other. Let’s cross them out.
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@$\begin{align*}\sqrt{x^2}=\sqrt{100}\end{align*}@$

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Now are left with:
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@$$\begin{align*}x&=\sqrt{100}\\ x&=10\end{align*}@$$

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This is the answer.
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Solve each equation.

#### Example A

@$\begin{align*}x^2=36\end{align*}@$

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Solution:
@$\begin{align*}x = 6\end{align*}@$
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#### Example B

@$\begin{align*}x^2=81\end{align*}@$

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Solution:
@$\begin{align*}x = 9\end{align*}@$
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#### Example C

@$\begin{align*}x^3+2=66\end{align*}@$

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Solution:
@$\begin{align*}x = 4\end{align*}@$
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Now let's go back to the dilemma from the beginning of the Concept.

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First, we have to break down what we know about the garden. We know the area.
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@$\begin{align*}A = 144 \ sq.feet\end{align*}@$

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We also know that the formula for area is
@$\begin{align*}s^2\end{align*}@$
.
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Now we can write an equation to figure out the first part of the problem, the length of one of the sides.
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@$\begin{align*}s^2=144 \ sq.feet\end{align*}@$

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If we take the square root of both sides, then we will be able to solve for the value of the side of the garden.
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@$$\begin{align*}sqrt{s^2} &= \sqrt{144}\\ s&=12 \ feet\end{align*}@$$

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The length of one of the sides of the garden is 12 feet.
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Next, we need to figure out the perimeter of the garden.
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@$\begin{align*}P=4s\end{align*}@$

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Let’s substitute in the known value for the side of the garden.
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@$\begin{align*}P=4(12)\end{align*}@$

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The perimeter of the garden is 48 square feet.
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### Guided Practice

Here is one for you to try on your own.

@$\begin{align*}x^2=121\end{align*}@$

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Solution
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To solve this equation let’s think about what we know. We know that a value times itself is going to equal 100. Up until this point we have solved equations by using the inverse operation. We can use that again here too. The variable is squared; we want to get it by itself by using an inverse operation. The inverse of squaring a number is to find the square root of the number. Let’s see what happens if we find the square root of both sides of the equation.

@$\begin{align*}\sqrt{x^2}= \sqrt{121}\end{align*}@$

@$\begin{align*}\sqrt{x^2}=\sqrt{121}\end{align*}@$

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Now are left with:
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@$$\begin{align*}x&=\sqrt{121}\\ x&=11\end{align*}@$$

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This is the answer.
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### Video Review

Solving Radical Equations with One Radical

### Explore More

Directions: Solve each equation involving radical expressions.

- @$\begin{align*}x^2=121\end{align*}@$
- @$\begin{align*}x^2=144\end{align*}@$
- @$\begin{align*}x^2=64\end{align*}@$
- @$\begin{align*}x^2=169\end{align*}@$
- @$\begin{align*}x^2=16\end{align*}@$
- @$\begin{align*}x^3=64\end{align*}@$
- @$\begin{align*}x^3=27\end{align*}@$
- @$\begin{align*}x^2+3=147\end{align*}@$
- @$\begin{align*}x^2-2=23\end{align*}@$
- @$\begin{align*}x^2+5=30\end{align*}@$
- @$\begin{align*}x^3+4=68\end{align*}@$
- @$\begin{align*}x^3+10=135\end{align*}@$
- @$\begin{align*}x^2-4=21\end{align*}@$
- @$\begin{align*}x^2-6=30\end{align*}@$
- @$\begin{align*}x^2-12=37\end{align*}@$