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# Solving Equations with Fractional Exponents

## Raise fractional exponents to their inverse power to cancel

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Practice Solving Equations with Fractional Exponents
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Solving Rational Exponent Equations

The period (in seconds) of a pendulum with a length of L (in meters) is given by the formula \begin{align*}P = 2\pi{(\frac{L}{9.8})}^{\frac{1}{2}}\end{align*}. If the period of a pendulum is \begin{align*}10\pi\end{align*} is the length of the pendulum 156.8?

### Guidance

This concept is very similar to the previous two. When solving a rational exponent equation, isolate the variable. Then, to eliminate the exponent, you will need to raise everything to the reciprocal power.

#### Example A

Determine if x = 9 is a solution to \begin{align*}2x^{\frac{3}{2}}-19=35\end{align*}.

Solution: Substitute in x and see if the equation holds.

9 is a solution to this equation.

#### Example B

Solve \begin{align*}3x^{\frac{5}{2}}=96\end{align*}.

Solution: First, divide both sides by 3 to isolate \begin{align*}x\end{align*}.

\begin{align*}x\end{align*} is raised to the five-halves power. To cancel out this exponent, we need to raise everything to the two-fifths power.

Check: \begin{align*}3(4)^{\frac{5}{2}}=3 \cdot 2^5=3 \cdot 32=96\end{align*}

#### Example C

Solve \begin{align*}-2(x-5)^{\frac{3}{4}}+48=-202\end{align*}.

Solution: Isolate \begin{align*}(x-5)^{\frac{3}{4}}\end{align*} by subtracting 48 and dividing by -2.

To undo the three-fourths power, raise everything to the four-thirds power.

Check: \begin{align*}-2(630-5)^{\frac{3}{4}}+48=-2 \cdot 625^{\frac{3}{4}}+48=-2 \cdot 125+48=-250+48=-202\end{align*}

Intro Problem Revisit We need to plug 156.8 in to the equation \begin{align*}P = 2\pi{(\frac{L}{9.8})}^{\frac{1}{2}}\end{align*} for L and solve. If our answer equals \begin{align*}10\pi\end{align*}, then the given length is correct.

\begin{align*}8\pi\end{align*} does not equal \begin{align*}10\pi\end{align*}, so the length cannot be 156.8.

### Guided Practice

Solve the following rational exponent equations and check for extraneous solutions.

1. \begin{align*}8(3x-1)^{\frac{2}{3}}=200\end{align*}

2. \begin{align*}6x^{\frac{3}{2}}-141=1917\end{align*}

1. Divide both sides by 8 and raise everything to the three-halves power.

Check: \begin{align*}8(3(42)-1)^{\frac{2}{3}}=8(126-1)^{\frac{2}{3}}=8(125)^{\frac{2}{3}}=8 \cdot 25=200\end{align*}

2. Here, only the \begin{align*}x\end{align*} is raised to the three-halves power. Subtract 141 from both sides and divide by 6. Then, eliminate the exponent by raising both sides to the two-thirds power.

Check: \begin{align*}6(49)^{\frac{3}{2}}-141=6 \cdot 343-141=2058-141=1917\end{align*}

### Explore More

Determine if the following values of x are solutions to the equation \begin{align*}3x^{\frac{3}{5}}=-24\end{align*}

1. \begin{align*}x=32\end{align*}
2. \begin{align*}x=-32\end{align*}
3. \begin{align*}x=8\end{align*}

Solve the following equations. Round any decimal answers to 2 decimal places.

1. \begin{align*}2x^{\frac{3}{2}}=54\end{align*}
2. \begin{align*}3x^{\frac{1}{3}}+5=17\end{align*}
3. \begin{align*}(7x-3)^{\frac{2}{5}}=4\end{align*}
4. \begin{align*}(4x+5)^{\frac{1}{2}}=x-4\end{align*}
5. \begin{align*}x^{\frac{5}{2}}=16x^{\frac{1}{2}}\end{align*}
6. \begin{align*}(5x+7)^{\frac{3}{5}}=8\end{align*}
7. \begin{align*}5x^{\frac{2}{3}}=45\end{align*}
8. \begin{align*}(7x-8)^{\frac{2}{3}}=4(x-5)^{\frac{2}{3}}\end{align*}
9. \begin{align*}7x^{\frac{3}{7}}+9=65\end{align*}
10. \begin{align*}4997=5x^{\frac{3}{2}}-3\end{align*}
11. \begin{align*}2x^{\frac{3}{4}}=686\end{align*}
12. \begin{align*}x^3=(4x-3)^{\frac{3}{2}}\end{align*}