# Basic Exponential Functions

## Functions where the input variable is found in the exponent.

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Basic Exponential Functions

Can solving an exponential function predict the future? Can exponential functions be a fast track to wealth?

As a matter of fact, yes! Successful entrepreneurs all over the world know the value of modeling population and economic growth and decay. By constructing an accurate exponential equation to model the past and present growth of a particular area of the country, state, or even town, the ideal location for a new business to thrive can be predicted.

Some things cannot be modeled of course, such as natural disasters and the like, but often a few well educated guesses make the difference between stunning success and dismal failure in the business world.

### Basic Exponential Functions

In this lesson you will learn about exponential functions, a family of functions different from the other function families because the variable x is in the exponent. For example, the functions f(x) = 2x and g(x) = 100(2)5x are exponential functions.

#### Evaluating Exponential Functions

Consider the function f(x) = 2x. When we input a value for x, we find the function value by raising 2 to the exponent of x. For example, if x = 3, we have f(3) = 23 = 8.

If we choose larger values of x, we will get larger function values, as the function values will be larger powers of 2. For example, f(10) = 210 = 1,024.

If we choose smaller values of x, we will quickly end up with fractions. For instance, if x = 0, we have f(0) = 20 = 1. If x = -3, we have \begin{align*}f(-3)=2^{-3}=\left( \tfrac{1}{2} \right)^{3}=\tfrac{1}{8}\end{align*}. If we choose smaller and smaller x values, the function values will be smaller and smaller fractions. For example, if x = -10, we have \begin{align*}f(-10)=2^{-10}=\left( \tfrac{1}{2} \right)^{10}=\tfrac{1}{1024}\end{align*}. Notice that none of the x values we choose will result in a function value of "0", because the numerator of the fraction will always be 1. This tells us that while the domain of this function is the set of all real numbers, the range is limited to the set of positive real numbers.

In general, if we have a function of the form f(x) = ax, where a is a positive real number, the domain of the function is the set of all real numbers, and the range is limited to the set of positive real numbers. This restricted domain will result in a specific shape of the graph.

#### Solving Exponential Equations

Solving an exponential equation means determining the value of x for a given function value. The solution to the equation 2x = 8 is the value of x that makes the equation a true statement, therefore x = 3, since 23 = 8.

### Examples

#### Example 1

Solve for x: 3 (2x + 1) = 24.

We can solve this equation by writing both sides of the equation as a power of 2:

\begin{align*}3(2^{x + 1}) = 24\end{align*}
\begin{align*}\frac{3(2^{x + 1})} {3} = \frac{24} {3}\end{align*}
\begin{align*}2^{x + 1} = 8\end{align*}
\begin{align*}2^{x + 1} = 2^3\end{align*}

To solve the equation now, recall a property of exponents: if bx = by, then x = y. That is, if two powers of the same base are equal, the exponents must be equal. This property tells us how to solve:

\begin{align*}2^{x + 1} = 2^3\end{align*}
\begin{align*}\Rightarrow x + 1 = 3 \end{align*}
\begin{align*} \,\! x = 2 \end{align*}

#### Example 2

For the function g(x) = 3x, find g(2), g(4), g(0), g(-2), g(-4).

\begin{align*}g(2) = 3^2 = 9\end{align*}

\begin{align*}g(4) = 3^4 = 81\end{align*}

\begin{align*}g(0) = 3^0 = 1\end{align*}

\begin{align*}g(-2) = 3^{-2} = \frac{1} {3^2} = \frac{1} {9}\end{align*}

\begin{align*}g(-4) = 3^{-4} = \frac{1} {3^4} = \frac{1} {81}\end{align*}

The values of the function g(x) = 3x behave much like those of f(x) = 2x: if we choose larger values, we get larger and larger function values. If x = 0, the function value is 1. And, if we choose smaller and smaller x values, the function values will be smaller and smaller fractions. Also, the range of g(x) is limited to positive values.

#### Example 3

Use a graphing utility to solve each equation.

1. 23x - 1 = 7

Graph the function y = 23x - 1 and find the point where the graph intersects the horizontal line y = 7. The solution is x ≈ 1.27.

1. 6-4x = 28x - 5

Graph the functions y = 6-4x and y = 28x - 5 and find their intersection point.

The solution is approximately x ≈ 0.27. (Your graphing calculator should show 9 digits: 0.272630365.)

#### Example 4

Graph \begin{align*}f(x) = 2^x\end{align*} by creating a value table.

First, create a table showing values for x and f(x):

x f(x)
(-3) 1/8
(-2) 1/4
(-1) 1/2
0 1
1 2
2 4
3 8

Observe that \begin{align*}f\end{align*} is increasing and one-to-one. Also, \begin{align*}f\end{align*} is strictly positive and the range of \begin{align*}a^x\end{align*} is \begin{align*}(0, \infty)\end{align*}. Finally, it is important to notice that \begin{align*}f(0) = 1\end{align*} and \begin{align*}f(1) = 2\end{align*}.

The graph looks like this:

#### Example 5

Graph \begin{align*}g(x) = (\frac{1}{2})^x\end{align*} and explain how it relates to the graph of \begin{align*}f(x) = 2^x\end{align*} from Example 4.

To graph \begin{align*}g(x) = (\frac{1}{2})^x\end{align*} first consider how it compares to \begin{align*}f(x) = 2^x\end{align*} from Example 4:

At first, it looks like a completely new function, but consider:

\begin{align*}(\frac{1}{2})^x = \frac{1}{2^x} = 2^{-x}\end{align*}

Since \begin{align*}2^x\end{align*} is the inverse of \begin{align*}2^{-x}\end{align*} (which could also be written as \begin{align*}g(x) = f(-x)\end{align*}) the graph of \begin{align*}g\end{align*} is just the reflection of the graph of \begin{align*}f\end{align*} across the y-axis!

The graph below shows \begin{align*}f(x) = 2^x\end{align*} in blue and \begin{align*}g(x) = (\frac{1}{2})^x\end{align*} in red:

#### Example 6

Solve the equation 56x + 10 = 25x - 1.

Use the technique explained in the lesson:

56x + 10 = 25x - 1

56x + 10 = (52)x - 1

56x + 10 = 52x - 2

\begin{align*}\Rightarrow\end{align*} 6x + 10 = 2x - 2

4x + 10 = -2

4x = -12

x = -3

### Review

1. Describe an exponential function, and give an example.
2. What is an exponential function with increasing outputs known as?
3. What is an exponential function with outputs that decrease known as?

Evaluate each function at the given value.

1. \begin{align*}f(x) = \frac{1}{3}\cdot6^x\end{align*} at x = 2
2. \begin{align*}f(n) = 10\cdot2^n\end{align*} at n = 5
3. \begin{align*}g(x) = \frac{1}{5}\cdot(\frac{1}{3})^x\end{align*} at x = 3
4. Look at the graph below of the exponential function \begin{align*}g(x) = a^x\end{align*}. Find \begin{align*}a\end{align*}

Sketch the graph of each exponential function and explicitly evaluate each function for at least four values of x:

1. \begin{align*}f(x) = \pi^x\end{align*}
2. \begin{align*}f(x) = (\frac{2}{3})^{-x}\end{align*}
3. \begin{align*}f(x) = 2^{x+4} -2\end{align*}
4. Find the average rate of change of \begin{align*}f(x) = 2^x\end{align*} from \begin{align*}x = 3\end{align*} to \begin{align*}x = 6\end{align*}. Draw a graph that illustrates your answer

HINT for problems 12 - 14:

\begin{align*}A = P (1+\frac{r}{n})^{nt}\end{align*} where:

A = ending Amount
P = Principal (beginning amount)
r = interest rate (as a decimal value - NOT as a percentage!)
n = number of compoundings per period (commonly one year)
t = time (the number of periods/years)
1. If you invest $28,000 in an account that gets 10% annual interest compounded quarterly, how much would you have in 15 years? 2. If you invested a penny on Jan 1, 1776 at 12% interest compounded daily, how much would you have on Jan 1, 2013 ? 3. How much would you need to invest to get$20,000 in 3 years at an annual interest rate of 6.5% compounded monthly?
4. The half-life of element -137m is 2.552 minutes. How much of an 10 gram sample would be left after 8 minutes?
5. The half – life of carbon 14 is 5,730 years. How much of a 100 gram sample would be left after 25,000 years ?
6. Sketch and use the graphs of \begin{align*}f(x) = (\frac{1}{3})^x\end{align*} and \begin{align*}p(x) = (\frac{1}{4})^x\end{align*} to graph the inequality \begin{align*}(\frac{1}{3})^x \leq g(x) \leq (\frac{1}{4})^x\end{align*}

To see the Review answers, open this PDF file and look for section 3.3.

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### Vocabulary Language: English

TermDefinition
$e$ $e$ is an irrational number that is approximately equal to 2.71828. As $n \rightarrow \infty, \left(1+ \frac{1}{n}\right)^n \rightarrow e$.
Average rate of change The average rate of change of a function is the change in $y$ coordinates of a function, divided by the change in $x$ coordinates.
e $e$ is an irrational number that is approximately equal to 2.71828. As $n \rightarrow \infty, \left(1+ \frac{1}{n}\right)^n \rightarrow e$.
Exponential Decay Function An exponential decay function is a specific type of exponential function that has the form $y=ab^x$, where $a>0$ and $0.
Exponential Function An exponential function is a function whose variable is in the exponent. The general form is $y=a \cdot b^{x-h}+k$.
Exponential growth Exponential growth occurs when a quantity increases by the same proportion in each given time period.
Exponential Growth Function An exponential growth function is a specific type of exponential function that has the form $y=ab^x$, where $h=k=0, a>0,$ and $b>1$.
Function families Function families are groups of functions with similarities that make them easier to graph when you are familiar with the parent function, the most basic example of the form.
Function Family Function families are groups of functions with similarities that make them easier to graph when you are familiar with the parent function, the most basic example of the form.
Half-life Half-life refers to the time required for a radioactive material to decay to one-half of its initial concentration.