**Cross products** are related to **dot products** in a number of ways. Both are vector calculations, both are related not only to the magnitude of each vector, but also to the relative directions of both vectors.

Dot products in a sense calculate the *joined* force of two vectors in a given direction, and so are greatest when the vectors are parallel. Cross products, however, are greatest when the vectors are perpendicular... what then do they calculate?

### Watch This

**'The video below is a well presented description of how to calculate cross-products. If you would like a deeper understanding of the difference between "Dot Products" and "Cross Products", take a look at:**

### Guidance

Whereas a dot product of two vectors produces a scalar value; the **cross product** of the same two vectors produces a vector quantity having a direction perpendicular to the original two vectors.

The cross product of two vector quantities is another vector whose magnitude varies as the angle between the two original vectors changes. The cross product is sometimes referred to as the *vector product* of two vectors. The magnitude of the cross product represents the area of the parallelogram whose sides are defined by the two vectors, as shown in the figure below. Therefore, the maximum value for the cross product occurs when the two vectors are perpendicular to one another, but when the two vectors are parallel to one another the magnitude of the cross product is equal to zero.

The algebraic form of the cross product equation is more complicated than that for the dot product. For two 3D vectors and ,

Another way to describe the process is to say that the cross product is the multiplication of one vector by the component of the other vector which is perpendicular to the first vector. In the diagram below are two vectors, ** A** and

**. A perpendicular line has been drawn radially outward from**

*B***towards**

*B***to create a right triangle with**

*A***as the hypotenuse.**

*A*

The component of which is perpendicular to is given by *A* sin *θ* so the magnitude of the cross product can be written as

The direction of the cross product is perpendicular to the plane defined by the two crossed vectors. For example, the cross product of two vectors in the x-y plane will be parallel to the z-axis. This still leaves two possible directions for the cross product, though: either or .

We use a **right-hand-rule** to indicate the direction of the cross product. Position the thumb and index finger of your right hand with the first vector along your thumb and the second vector along your index finger. Your middle finger, when extended perpendicular to your palm, will indicate the direction of the cross product of the two vectors.

As you can see in the diagram above, is along (coming up out of the page) while is along (going down into the page) and

*The Normal Vector*

We can use the cross product and the definition of the unit vector to determine the direction which is perpendicular to a plane.

In general, we can define a normal vector, , which has a unity magnitude (i.e. magnitude equal to one) and which is perpendicular to a plane occupied by a pair of vectors, **U** and **V**.

#### Example A

Calculate the cross product of the two vectors shown below.

*Solution:*

Use the components of the two vectors to determine the cross product.

Since these two vectors are both in the x-y plane, their own z-components are both equal to 0 and the vector product will be parallel to the z axis.

We can check our answer using the sine version of the cross product, but first we need to know the angle between the two vectors. We can use the dot product to find θ, following the procedure in the first Example in the previous section. First use the components to find the dot product.

Then find the magnitudes of the two vectors:

Then use these magnitudes with the cosine version of the dot product to find θ.

Now use the sine of this angle and the two magnitudes to determine the cross product:

This is the same answer that we obtained from the component notation, which is good. We use the right-hand rule to determine the direction of the vector product. If you place your thumb along vector **A** and your forefinger along vector **B**, your middle finger will point along and

#### Example B

The diagram shows two vectors **A** and **B** which define a plane passing through the origin. Use these two vectors to determine the normal vector to this plane. and

*Solution:*

The normal vector is defined by

In this case, we obtain

Use the component version of the cross-product equation to find the components of

Next, calculate the magnitude of the cross product,

#### Example C

Determine the cross product for the two vectors and . Then use the cross product to determine the angle between the two vectors.

*Solution:*

One of the two ways to determine the magnitude of the cross product of two vectors uses the components of the two vectors:

Now we can use the cross product and the second definition of the cross product to determine the angle between the two vectors.

We need to calculate the magnitudes of the vectors and of the cross product.

We can use the dot product of the two vectors to check our solution.

This answer matches our value from the cross product to within rounding variations. -->

### Guided Practice

1) Determine the magnitude of the cross product of the two vectors shown below.

2) A plane passing through the origin is defined by the two vectors, and . Determine the equation of a unit vector representing a direction perpendicular to this plane.

3) Determine the area of a parallelogram whose sides are defined by the vectors and , lengths measured in centimeters.

4) Determine the cross product of the two vectors and

5) Determine the equation for the unit vector perpendicular to the plane defined by the two vectors and

6) Determine the area of the parallelogram whose sides are defined by and , lengths measured in millimeters.

7) Determine the magnitude of the cross-product of these two vectors.

*Answers*

1) First we need to identify the components of the two vectors by using the information given on the graph. In this case, and

- As we can see by the components, this vector has a magnitude of 4.5 units and lies in the –z direction. We can also use the right-hand-rule to see the direction of the cross product. As shown in the figure below, if we align the right thumb with vector MN and the right fore-finger with vector KL, the palm and extended middle-finger point in the –z direction.

2) To solve this problem we need to use the definition of the normal vector , the component form of the definition of the cross product,

- . In this case, we obtain
- We also need to know the magnitude of this cross product
- Now we can determine the normal vector

3) The area of the parallelogram whose sides are defined by a pair of vectors is equal to the magnitude of the cross product of the two vectors, . First we need to find the cross product of the two vectors:

- Since the lengths of the two vectors were measured in centimeters, the area of the parallelogram is 2013 cm
^{2}measured to the nearest square centimeter.

4)

5) The cross product of two vectors is always perpendicular to the plane defined by the two vectors.

- The magnitude of this vector is given by
- Then divide the cross-product by its magnitude to obtain the unit vector.

6) The area of the parallelogram whose sides are defined by a pair of vectors is equal to the magnitude of the cross product of the two vectors, . First we need to find the cross product of the two vectors:

- Since the lengths of the two vectors were measured in centimeters, the area of the parallelogram is 2202 cm
^{2}measured to the nearest square centimeter. - 7) Since we know the magnitudes of the two vectors and the angle between them, we can use the angle-version of the cross-product equation to determine the magnitude of the cross-product:

Since these two vectors lie in the x-y plane, the direction of the cross-product will be parallel to the z-axis.

### Explore More

Calculate the cross products:

- Vectors c = and a =
- Vectors v = and u =
- Vectors f = and s =
- Vectors j = and t =
- Vectors r = and v =
- Vectors e = and a =
- Vectors j = and h =
- Vectors a = and g =
- Vectors j = and m =
- What is the cross product of and
- Find a vector orthogonal to both and
- Vectors and What is the area of the parallelogram formed by having y and f as adjacent sides?
- What is the area of the parallelogram formed by having and as adjacent sides?
- What is the cross product between and ?
- Vectors and What is the cross product between g and y?
- A boat is sailing on a bearing of 89° east of north at 564 feet per min. A tail wind is adding to the plane's velocity and blowing 78° west of north at 25 feet per min. Determine the actual speed of the plane in mph.
- A plane is flying on a bearing of 77° east of south at 606 mph. A tail wind is adding to the plane's velocity and blowing 33° west of south at 80 mph. Determine the direction of the plane.

### Answers for Explore More Problems

To view the Explore More answers, open this PDF file and look for section 5.6.