You probably remember when you first learned to use the quadratic formula in algebra and you ended up with a negative number under the root symbol. Chances are good that your instructor simply said something like "If you get a negative number under the root, there are no real answers, since there is no such thing as the root of a negative!"
Now that you are familiar with imaginary numbers, you can probably see that although it would have been an easy assumption at the time that "no real answers" just meant "no answers at all," that isn't true. "No real answers" may well mean that there ARE some "unreal" or imaginary answers.
Quadratic Formula and Complex Sums
The Quadratic Formula and the Discriminant
If ax^{2} + bx + c = 0
then
Recall that b^{2}  4ac is called the discriminant.
If b^{2}  4ac > 0 then there are two unequal real solutions.

If b^{2}  4ac = 0 then there are two equal real solutions.

If b^{2}  4ac < 0 then there are two unequal complex solutions.


Sums and Differences of Complex Numbers
When adding (or subtracting) two or more complex numbers the fastest method is to add (or subtract) the real components to obtain the sum of the real numbers, and then separately add (or subtract) the imaginary coefficients to obtain the sum of the imaginary numbers, e.g.:
(a + bi) + (c + di) = [a + c] + [b + d]i
Examples
Example 1
Combine the complex numbers using addition or subtraction.
(5+3i)+(6−8i)
Applying the commutative property:
(3−2i)−(2−4i)
Distribute the negative:
(6)+(4−3i)
The imaginary coefficient in the first term is 0, so applying commutative property gives:
Example 2
Given:
 Use the discriminant to predict the nature of the roots.
Since
 Use the quadratic formula to solve and identify the roots.
 Express the roots as complex numbers in standard form.
Example 3
(Graphing calculator exercise)
A graphing calculator can perform operations with complex numbers. Press mode. Scroll down and select
Add or subtract the complex numbers using a graphing calculator:
(4−5i)−(3+2i)
(3−7i)+(2+i)
(−2i)+(2+6i)

(16−−64−−−−√)+(7−−81−−−−√)
Example 4
Subtract the complex numbers.
(9+7i)−(6+3i)
(18+−81−−−−√)−(18−−64−−−−√)
Example 5
Solve the equations and express them as complex numbers.
18x2−2x+24=0
1245x2=1425x−1115
Review
Add the complex numbers.
(4+4i)+(3+6i)  \begin{align*}(4 + 8i) + (8 + 8i)\end{align*}
 \begin{align*}20 \sqrt{100} + \sqrt{9}\end{align*}
 \begin{align*}3 \sqrt{121} + 15 \sqrt{81}\end{align*}
 \begin{align*}25\sqrt{9} + 23\sqrt{196}\end{align*}
Subtract the complex numbers.
 \begin{align*}(9 + 8i)  (8 + 5i)\end{align*}
 \begin{align*}(6  8i)  (12 + 9i)\end{align*}
 \begin{align*}5 \sqrt{49}  16 \sqrt{1}\end{align*}
 \begin{align*}22 \sqrt{144}  9\sqrt{4}\end{align*}
 \begin{align*}27 \sqrt {196}  \sqrt{1}\end{align*}
Solve each equation and express the result as a complex number.
 \begin{align*}12x\frac{4}{5}x = 3\frac{1}{5}x^2 + 16\end{align*}
 \begin{align*}3x^2  6x + 15 = 0\end{align*}
 \begin{align*}8x^2  5x + 11 = 0\end{align*}
 \begin{align*}34\frac{1}{2}x^2  23x + 19\frac{1}{6} = 0\end{align*}
 \begin{align*}36x^2  18x + 6 = 27\end{align*}
 When the sum of 4 + 8i and 2  9i is graphed, in which quadrant does it lie?
 If \begin{align*}z_1 = 3 + 2i\end{align*} and \begin{align*}z_2 = 4  3i\end{align*}, in which quadrant does the graph of \begin{align*}(z_2  z_1)\end{align*} lie?
 On a graph, if point A represents \begin{align*}2  3i\end{align*} and point B represents \begin{align*}2  5i\end{align*}, which quadrant contains \begin{align*}A  B\end{align*} ?
 Find the sum of \begin{align*}(3 + 4i)\end{align*} and \begin{align*}(4  7i)\end{align*} and graph the result
 Graph the difference of \begin{align*}( 4 + 7i)\end{align*} and \begin{align*}(2  3i)\end{align*}
Review (Answers)
To see the Review answers, open this PDF file and look for section 4.6.