In 2013, the days a full moon appeared were in the following sequence (with Jan. 1 being Day 1). Write a recursive formula for the sequence.

9, 38, 67, 96, ...

Source: Moongiant

### Recursive Rule

A **recursive rule** for a sequence is a formula which tells us how to progress from one term to the next in a sequence. Generally, the variable \begin{align*}n\end{align*}

Example sequence: \begin{align*}4, 7, 11, 16, \ldots, a_{n-1}, a_n\end{align*}

In the above sequence, \begin{align*}a_1=4\end{align*}

Let's describe the pattern and write a recursive rule for the sequence: \begin{align*}9, 11, 13, 15, \ldots\end{align*}

First we need to determine what the pattern is in the sequence. If we subtract each term from the one following it, we see that there is a common difference of 29. We can therefore use \begin{align*}a_{n-1}\end{align*}

Now, let's write a recursive rule for the following sequences.

- \begin{align*}3, 9, 27, 81, \ldots\end{align*}
3,9,27,81,…

In this sequence, each term is multiplied by 3 to get the next term. We can write a recursive rule: \begin{align*}a_n=3a_{n-1}\end{align*}

- \begin{align*}1, 1, 2, 3, 5, 8, \ldots\end{align*}
1,1,2,3,5,8,…

This is a special sequence called the Fibonacci sequence. In this sequence each term is the sum of the previous two terms. We can write the recursive rule for this sequence as follows: \begin{align*}a_n=a_{n-2}+a_{n-1}\end{align*}

### Examples

#### Example 1

Earlier, you were asked to write a recursive formula for the sequence 9, 38, 67, 96, ...

First we need to determine what pattern the sequence is following. If we subtract each term from the one following it, we find that there is a common difference of 29. We can therefore use \begin{align*}a_{n-1}\end{align*}

**Write the recursive rules for the following sequences.**

#### Example 2

\begin{align*}1, 2, 4, 8, \ldots\end{align*}

In this sequence each term is double the previous term so the recursive rule is: \begin{align*}a_n=2a_{n-1}\end{align*}

#### Example 3

\begin{align*}1, -2, -5, -8, \ldots\end{align*}

This time three is subtracted each time to get the next term: \begin{align*}a_n=a_{n-1}-3\end{align*}.

#### Example 4

\begin{align*}1, 2, 4, 7, \ldots\end{align*}

This one is a little trickier to express. Try looking at each term as shown below:

\begin{align*}a_1 &=1 \\ a_2 &=a_1+1 \\ a_3 &=a_2+2 \\ a_4 &=a_3+3 \\ & \ \ \vdots \\ a_n &=a_{n-1}+(n-1)\end{align*}

### Review

Describe the pattern and write a recursive rule for the following sequences.

- \begin{align*}\frac{1}{4}, -\frac{1}{2}, 1, -2 \ldots\end{align*}
- \begin{align*}5, 11, 17, 23, \ldots\end{align*}
- \begin{align*}33, 28, 23, 18, \ldots\end{align*}
- \begin{align*}1, 4, 16, 64, \ldots\end{align*}
- \begin{align*}21, 30, 39, 48, \ldots\end{align*}
- \begin{align*}100, 75, 50, 25, \ldots\end{align*}
- \begin{align*}243, 162, 108, 72, \ldots\end{align*}
- \begin{align*}128, 96, 72, 54, \ldots\end{align*}
- \begin{align*}1, 5, 10, 16, 23, \ldots\end{align*}
- \begin{align*}0, 2, 2, 4, 6, \ldots\end{align*}
- \begin{align*}3, 5, 8, 12, \ldots\end{align*}
- \begin{align*}0, 2, 6, 12, \ldots\end{align*}
- \begin{align*}4, 9, 14, 19, \ldots\end{align*}
- \begin{align*}\frac{1}{2}, \frac{2}{3}, \frac{3}{4}, \frac{4}{5} \ldots\end{align*}
- \begin{align*}4, 5, 9, 14, 23, \ldots\end{align*}

### Answers for Review Problems

To see the Review answers, open this PDF file and look for section 11.2.