<img src="https://d5nxst8fruw4z.cloudfront.net/atrk.gif?account=iA1Pi1a8Dy00ym" style="display:none" height="1" width="1" alt="" />

# 7.1: Solve for the Unknown

Difficulty Level: At Grade Created by: CK-12

Can you use the order of operations? What's the value of a\begin{align*}a\end{align*}? In this section, we will learn to use the order of operations.

(3+5)÷2+4×6=a\begin{align*}(3 + 5) \div 2 + 4 \times 6 = a\end{align*}

### Solve for the Unknown

The order of operations tells us the correct order of evaluating math expressions. We always do parenthesis first. Then we do multiplication and division (from left to right) and finally addition and subtraction (from left to right).

In order to evaluate expressions using the order of operations, we can use the problem solving steps to help.

• First, describe what you see in the problem. What operations are there?
• Second, identify what your job is. In these problems, your job will be to solve for the unknown.
• Third, make a plan. In these problems, your plan should be to use the order of operations.
• Fourth, solve.
• Fifth, check.

#### Solving for Unknown Values

1. Figure out the value of the variable. Follow the order of operations.

8(31)+6×2=e\begin{align*}8-(3-1)+6\times 2=e\end{align*}

We can use the problem solving steps to help.

Describe: The equation has parenthesis, multiplication, addition and subtraction.

My Job: Do the operations to figure out the value of e\begin{align*}e\end{align*}.

Plan: Do the parenthesis first. Then do the multiplication. Finally, do the subtraction and addition from left to right.

Solve: First do the parenthesis: 8(31)+6×2=82+6×2\begin{align*}8-(3-1)+6\times 2=8-2+6\times 2\end{align*}

Next do the multiplication: 82+6×2=82+12\begin{align*}8-2+6\times 2=8-2+12\end{align*}
Last do the subtraction and addition: 82+12=6+12=18\begin{align*}8-2+12=6+12=18\end{align*}
e=18\begin{align*}e=18\end{align*}

Check: 8(31)+6×2=82+6×2=82+12=6+12=18\begin{align*}8-(3-1)+6\times 2=8-2+6\times 2=8-2+12=6+12=18\end{align*}

2. Figure out the value of the variable. Follow the order of operations.

(4+6)÷53÷3=a\begin{align*}(4 + 6) \div 5 - 3 \div 3 = a\end{align*}

We can use the problem solving steps to help.

Describe: The equation has parenthesis, division, addition and subtraction.

My Job: Do the operations to figure out the value of a\begin{align*}a\end{align*}.

Plan: Do the parenthesis first. Then do the division. Finally, do the subtraction and addition from left to right.

Solve: First do the parenthesis: (4+6)÷53÷3=10÷53÷3\begin{align*}(4 + 6) \div 5 - 3 \div 3 =10\div 5-3 \div 3\end{align*}

Next do the division: 10÷53÷3=21\begin{align*}10\div 5-3 \div 3=2-1\end{align*}
Last do the subtraction: 21=1\begin{align*}2-1=1\end{align*}
a=1\begin{align*}a=1\end{align*}

Check: (4+6)÷53÷3=10÷53÷3=21=1\begin{align*}(4 + 6) \div 5 - 3 \div 3 =10\div 5-3 \div 3=2-1=1\end{align*}

3. Figure out the value of the variable. Follow the order of operations.

6×7÷6+8=c\begin{align*}6 \times 7 \div 6 + 8 = c\end{align*}

We can use the problem solving steps to help.

Describe: The equation has multiplication, division and addition.

My Job: Do the operations to figure out the value of c\begin{align*}c\end{align*}.

Plan: Do the multiplication and division first from left to right. Then do the addition.

Solve: First do the multiplication and division: 6×7÷6+8=42÷6+8=7+8\begin{align*}6 \times 7 \div 6 + 8=42 \div 6+8=7+8\end{align*}

Last do the addition: 7+8=15\begin{align*}7+8=15\end{align*}
c=15\begin{align*}c=15\end{align*}

Check: 6×7÷6+8=42÷6+8=7+8=15\begin{align*}6 \times 7 \div 6 + 8=42 \div 6 +8=7+8=15\end{align*}

#### Earlier Problem Revisited

(3+5)÷2+4×6=a\begin{align*}(3 + 5) \div 2 + 4 \times 6 = a\end{align*}

We can use the problem solving steps to help.

Describe: The equation has parenthesis, division, multiplication and addition.

My Job: Do the operations to figure out the value of a\begin{align*}a\end{align*}.

Plan: Do the parenthesis first. Then, do the multiplication and division from left to right. Finally do the addition.

Solve: First do the parenthesis: (3+5)÷2+4×6=8÷2+4×6\begin{align*}(3 + 5) \div 2 + 4 \times 6=8 \div 2 +4 \times 6\end{align*}

Next do the multiplication and division from left to right: 8÷2+4×6=4+24\begin{align*}8 \div 2 +4 \times 6=4+24\end{align*}
Last do the addition: 4+24=28\begin{align*}4+24=28\end{align*}
a=28\begin{align*}a=28\end{align*}

Check: (3+5)÷2+4×6=8÷2+4×6=4+24=28\begin{align*}(3 + 5) \div 2 + 4 \times 6=8 \div 2 +4 \times 6 = 4+24=28\end{align*}

### Vocabulary

Order of operations tell us the correct order of evaluating math expressions. We always do Parenthesis first. Then we do multiplication and division (from left to right) and finally addition and subtraction (from left to right).

### Examples

Figure out the value of the variables. Follow the order of operations.

#### Example 1

(102)÷2+5×3=b\begin{align*}(10 - 2) \div 2 + 5 \times 3 = b\end{align*}

b=19\begin{align*}b = 19\end{align*}

#### Example 2

4+(9+6)÷3=d\begin{align*}4 + (9 + 6) \div 3 = d\end{align*}

d=9\begin{align*}d = 9\end{align*}

#### Example 3

12+2×3÷6+(74)=q\begin{align*}12 + 2 \times 3 \div 6 + (7 - 4) = q\end{align*}

q=16\begin{align*}q = 16\end{align*}

### Review

Figure out the value of the variables. Follow the order of operations.

1. 4×(62)÷2×3=t\begin{align*}4 \times (6 - 2) \div 2 \times 3 = t\end{align*}
2. 2×(111)÷2=g\begin{align*}2 \times (11 - 1) \div 2 = g\end{align*}
3. 3×(124)(52)=m\begin{align*}3 \times (12 - 4) - (5 - 2) = m\end{align*}
4. 6×(7+3)÷4×2=n\begin{align*}6 \times (7 + 3) \div 4 \times 2 = n\end{align*}
5. 3×(52)(32)=p\begin{align*}3 \times (5-2) - (3 -2) = p\end{align*}
6. 2×(6+1)÷2×3=q\begin{align*}2 \times (6+1) \div 2 \times 3 = q\end{align*}
7. 5×(41)+3×8=r\begin{align*}5 \times (4-1) + 3 \times 8 = r\end{align*}
8. 8×(54)÷2×5=s\begin{align*}8 \times (5-4) \div 2 \times 5 = s\end{align*}
9. 7×(73)÷2+1=u\begin{align*}7 \times (7 - 3) \div 2 + 1 = u\end{align*}
10. 5×(3+4)+2×3=w\begin{align*}5 \times (3+4) + 2 \times 3 = w\end{align*}

### Notes/Highlights Having trouble? Report an issue.

Color Highlighted Text Notes

Show Hide Details
Description
Difficulty Level:
Tags:
Date Created:
Jan 18, 2013
Mar 23, 2016

# We need you!

At the moment, we do not have exercises for Solve for the Unknown.

Save or share your relevant files like activites, homework and worksheet.
To add resources, you must be the owner of the Modality. Click Customize to make your own copy.