9.7: Extension: Writing and Graphing the Equations of Circles
Learning Objectives
 Graph a circle.
 Find the equation of a circle in the \begin{align*}xy\end{align*}
x−y plane.  Find the radius and center, given the equation of a circle and vice versa.
 Find the equation of a circle, given the center and a point on the circle.
Graphing a Circle in the Coordinate Plane
Recall that the definition of a circle is the set of all points that are the same distance from the center. This definition can be used to find an equation of a circle in the coordinate plane.
Let’s start with the circle centered at (0, 0). If \begin{align*}(x, y)\end{align*}
Example 1: Graph \begin{align*}x^2+y^2=9\end{align*}
Solution: The center is (0, 0). It’s radius is the square root of 9, or 3. Plot the center, and then go out 3 units in every direction and connect them to form a circle.
The center does not always have to be on (0, 0). If it is not, then we label the center \begin{align*}(h, k)\end{align*}
\begin{align*}r=\sqrt{(xh)^2+(yk)^2}\end{align*}
If you square both sides of this equation, then we would have the standard equation of a circle.
Standard Equation of a Circle: The standard equation of a circle with center \begin{align*}(h, k)\end{align*}
Example 2: Find the center and radius of the following circles.
a) \begin{align*}(x3)^2+(y1)^2=25\end{align*}
b) \begin{align*}(x+2)^2+(y5)^2=49\end{align*}
Solution:
a) Rewrite the equation as \begin{align*}(x3)^2+(y1)^2=5^2\end{align*}
b) Rewrite the equation as \begin{align*}(x(2))^2+(y5)^2=7^2\end{align*}
When finding the center of a circle always take the opposite sign of what the value is in the equation.
Example 3: Find the equation of the circle below.
Solution: First locate the center. Draw in the horizontal and vertical diameters to see where they intersect.
From this, we see that the center is (3, 3). If we count the units from the center to the circle on either of these diameters, we find \begin{align*}r = 6\end{align*}
Finding the Equation of a Circle
Example 4: Determine if the following points are on \begin{align*}(x+1)^2+(y5)^2=50\end{align*}
a) (8, 3)
b) (2, 2)
Solution: Plug in the points for \begin{align*}x\end{align*}
a) \begin{align*}(8+1)^2+(35)^2=50\!\\
9^2+(8)^2=50\!\\
81+64 \ne 50\end{align*}
(8, 3) is not on the circle
b) \begin{align*}(2+1)^2+(25)^2=50\!\\
(1)^2+(7)^2=50\!\\
1+49=50\end{align*}
(2, 2) is on the circle
Example 5: Find the equation of the circle with center (4, 1) and passes through (1, 2).
Solution: First plug in the center to the standard equation.
\begin{align*}(x4)^2+(y(1))^2&=r^2 \\
(x4)^2+(y+1)^2&=r^2\end{align*}
Now, plug in (1, 2) for \begin{align*}x\end{align*}
\begin{align*}(14)^2+(2+1)^2&=r^2\\
(5)^2+(3)^2&=r^2\\
25+9&=r^2\\
34&=r^2\end{align*}
Substituting in 34 for \begin{align*}r^2\end{align*}
Review Questions
 Questions 14 are similar to Examples 1 and 2.
 Questions 58 are similar to Example 3.
 Questions 911 are similar to Example 4.
 Questions 1215 are similar to Example 5.
Find the center and radius of each circle. Then, graph each circle.

\begin{align*}(x+5)^2+(y3)^2=16\end{align*}
(x+5)2+(y−3)2=16 
\begin{align*}x^2+(y+8)^2=4\end{align*}
x2+(y+8)2=4 
\begin{align*}(x7)^2+(y10)^2=20\end{align*}
(x−7)2+(y−10)2=20  \begin{align*}(x+2)^2+y^2=8\end{align*}
Find the equation of the circles below.
 Is (7, 3) on \begin{align*}(x+1)^2+(y6)^2=45\end{align*}?
 Is (9, 1) on \begin{align*}(x2)^2+(y2)^2=60\end{align*}?
 Is (4, 3) on \begin{align*}(x+3)^2+(y3)^2=37\end{align*}?
 Is (5, 3) on \begin{align*}(x+1)^2+(y6)^2=45\end{align*}?
Find the equation of the circle with the given center and point on the circle.
 center: (2, 3), point: (4, 1)
 center: (10, 0), point: (5, 2)
 center: (3, 8), point: (7, 2)
 center: (6, 6), point: (9, 4)
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