6.12: Linear Inequalities in Two Variables
What if you were given a linear inequality like
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CK12 Foundation: 0612S Linear Inequalities in Two Variables (H264)
Guidance
The general procedure for graphing inequalities in two variables is as follows:
 Rewrite the inequality in slopeintercept form:
y=mx+b . Writing the inequality in this form lets you know the direction of the inequality.  Graph the line of the equation
y=mx+b using your favorite method (plotting two points, using slope andy− intercept, usingy− intercept and another point, or whatever is easiest). Draw the line as a dashed line if the equals sign is not included and a solid line if the equals sign is included.  Shade the half plane above the line if the inequality is “greater than.” Shade the half plane under the line if the inequality is “less than.”
Example A
Graph the inequality
Solution
The inequality is already written in slopeintercept form, so it’s easy to graph. First we graph the line
Example B
Graph the inequality
Solution
First we need to rewrite the inequality in slopeintercept form:
Notice that the inequality sign changed direction because we divided by a negative number.
To graph the equation, we can make a table of values:



2 

0 

2 

After graphing the line, we shade the plane below the line because the inequality in slopeintercept form is less than. The line is dashed because the inequality does not include an equals sign.
Solve RealWorld Problems Using Linear Inequalities
In this section, we see how linear inequalities can be used to solve realworld applications.
Example C
A retailer sells two types of coffee beans. One type costs $9 per pound and the other type costs $7 per pound. Find all the possible amounts of the two different coffee beans that can be mixed together to get a quantity of coffee beans costing $8.50 or less.
Solution
Let
Let
The cost of a pound of coffee blend is given by
We are looking for the mixtures that cost $8.50 or less. We write the inequality
Since this inequality is in standard form, it’s easiest to graph it by finding the
Now we have to figure out which side of the line to shade. In
The other method, which works for any linear inequality in any form, is to plug a random point into the inequality and see if it makes the inequality true. Any point that’s not on the line will do; the point (0, 0) is usually the most convenient.
In this case, plugging in 0 for
Notice also that in this graph we show only the first quadrant of the coordinate plane. That’s because weight values in the real world are always nonnegative, so points outside the first quadrant don’t represent realworld solutions to this problem.
Watch this video for help with the Examples above.
CK12 Foundation: Linear Inequalities in Two Variables
Vocabulary
 For a strict inequality, we draw a dashed line to show that the points in the line are not part of the solution. For an inequality that includes the equals sign, we draw a solid line to show that the points on the line are part of the solution.
 The solution to a linear inequality includes all the points in one half of the plane. We can tell which half by looking at the inequality sign:
> The solution set is the half plane above the line.
< The solution set is the half plane below the line.
Guided Practice
Julius has a job as an appliance salesman. He earns a commission of $60 for each washing machine he sells and $130 for each refrigerator he sells. How many washing machines and refrigerators must Julius sell in order to make $1000 or more in commissions?
Solution
Let
Let
The total commission is
We’re looking for a total commission of $1000 or more, so we write the inequality
Once again, we can do this most easily by finding the
We draw a solid line connecting those points, and shade above the line because the inequality is “greater than.” We can check this by plugging in the point (0, 0): selling 0 washing machines and 0 refrigerators would give Julius a commission of $0, which is not greater than or equal to $1000, so the point (0, 0) is not part of the solution; instead, we want to shade the side of the line that does not include it.
Notice also that we show only the first quadrant of the coordinate plane, because Julius’s commission should be nonnegative.
Practice
Graph the following inequalities on the coordinate plane.

y≤4x+3 
y>−x2−6 
3x−4y≥12 
x+7y<5 
6x+5y>1  \begin{align*}y+5 \le 4x+10\end{align*}
 \begin{align*}x\frac{1}{2}y \ge 5\end{align*}
 \begin{align*}6x+y < 20\end{align*}
 \begin{align*}30x+5y < 100\end{align*}
 Remember what you learned in the last chapter about families of lines.
 What do the graphs of \begin{align*}y > x+2\end{align*} and \begin{align*}y < x+5\end{align*} have in common?
 What do you think the graph of \begin{align*}x+2 < y < x+5\end{align*} would look like?
 How would the answer to problem 6 change if you subtracted 2 from the righthand side of the inequality?
 How would the answer to problem 7 change if you added 12 to the righthand side?
 How would the answer to problem 8 change if you flipped the inequality sign?
 A phone company charges 50 cents per minute during the daytime and 10 cents per minute at night. How many daytime minutes and nighttime minutes could you use in one week if you wanted to pay less than $20?
 Suppose you are graphing the inequality \begin{align*}y > 5x\end{align*}.
 Why can’t you plug in the point (0, 0) to tell you which side of the line to shade?
 What happens if you do plug it in?
 Try plugging in the point (0, 1) instead. Now which side of the line should you shade?
 A theater wants to take in at least $2000 for a certain matinee. Children’s tickets cost $5 each and adult tickets cost $10 each.
 If \begin{align*}x\end{align*} represents the number of adult tickets sold and \begin{align*}y\end{align*} represents the number of children’s tickets, write an inequality describing the number of tickets that will allow the theater to meet their minimum take.
 If 100 children’s tickets and 100 adult tickets have already been sold, what inequality describes how many more tickets of both types the theater needs to sell?
 If the theater has only 300 seats (so only 100 are still available), what inequality describes the maximum number of additional tickets of both types the theater can sell?
Texas Instruments Resources
In the CK12 Texas Instruments Algebra I FlexBook, there are graphing calculator activities designed to supplement the objectives for some of the lessons in this chapter. See http://www.ck12.org/flexr/chapter/9616.
Cartesian Plane
The Cartesian plane is a grid formed by a horizontal number line and a vertical number line that cross at the (0, 0) point, called the origin.Linear Inequality
Linear inequalities are inequalities that can be written in one of the following four forms: , or .SlopeIntercept Form
The slopeintercept form of a line is where is the slope and is the intercept.Image Attributions
Here you'll learn how to graph linear inequalities in two variables of the form @$\begin{align*}y > mx + b\end{align*}@$ or @$\begin{align*}y < mx + b\end{align*}@$. You'll also solve realworld problems involving such inequalities.
Concept Nodes:
Cartesian Plane
The Cartesian plane is a grid formed by a horizontal number line and a vertical number line that cross at the (0, 0) point, called the origin.Linear Inequality
Linear inequalities are inequalities that can be written in one of the following four forms: , or .SlopeIntercept Form
The slopeintercept form of a line is where is the slope and is the intercept.