# 6.3: Multi-Step Inequalities

**At Grade**Created by: CK-12

**Practice**Multi-Step Inequalities

What if you had an inequality with an unknown variable on both sides like \begin{align*}2(x - 2) > 3x - 5\end{align*}

### Watch This

CK-12 Foundation: 0603S Solving Multi-Step Inequalities (H264)

### Try This

For additional practice solving inequalities, try the online game at http://www.aaamath.com/equ725x7.htm#section2. If you’re having a hard time with multi-step inequalities, the video at http://www.schooltube.com/video/aa66df49e0af4f85a5e9/MultiStep-Inequalities will walk you through a few.

### Guidance

In the last two sections, we considered very simple inequalities which required one step to obtain the solution. However, most inequalities require several steps to arrive at the solution. As with solving equations, we must use the order of operations to find the correct solution. In addition, remember that **when we multiply or divide the inequality by a negative number, the direction of the inequality changes.**

The general procedure for solving multi-step inequalities is almost exactly like the procedure for solving multi-step equations:

- Clear parentheses on both sides of the inequality and collect like terms.
- Add or subtract terms so the variable is on one side and the constant is on the other side of the inequality sign.
- Multiply and divide by whatever constants are attached to the variable. Remember to change the direction of the inequality if you multiply or divide by a negative number.

#### Example A

*Solve the inequality \begin{align*}\frac{9x}{5}-7 \ge -3x + 12\end{align*} 9x5−7≥−3x+12 and graph the solution set.*

**Solution**

Original problem: \begin{align*}\frac{9x}{5}-7 \ge -3x+12\end{align*}

Add \begin{align*}3x\end{align*}

Simplify: \begin{align*}\frac{24x}{5}-7 \ge 12\end{align*}

Add 7 to both sides: \begin{align*}\frac{24x}{5}-7+7 \ge 12+7\end{align*}

Simplify: \begin{align*}\frac{24x}{5} \ge 19\end{align*}

Multiply 5 to both sides: \begin{align*}5 \cdot \frac{24x}{5} \ge 5 \cdot 19\end{align*}

Simplify: \begin{align*}24x \ge 95\end{align*}

Divide both sides by 24: \begin{align*}\frac{24x}{24} \ge \frac{95}{24}\end{align*}

Simplify: \begin{align*}x \ge \frac{95}{24}\end{align*}**Answer**

Graph:

#### Example B

*Solve the inequality \begin{align*}-25x + 12 \le -10x - 12\end{align*} −25x+12≤−10x−12 and graph the solution set.*

**Solution:**

Original problem: \begin{align*}-25x+12 \le -10x-12\end{align*}

Add \begin{align*}10x\end{align*}

Simplify: \begin{align*}-15x+12 \le -12\end{align*}

Subtract 12: \begin{align*}-15x+12-12\le -12-12\end{align*}

Simplify: \begin{align*}-15x \le -24\end{align*}

Divide both sides by -15: \begin{align*}\frac{-15x}{-15} \ge \frac{-24}{-15}\end{align*} *flip the inequality sign*

Simplify: \begin{align*}x \ge \frac{8}{5}\end{align*} **Answer**

Graph:

#### Example C

*Solve the inequality \begin{align*}4x-2(3x-9) \le -4(2x-9)\end{align*}.*

**Solution:**

Original problem: \begin{align*}4x-2(3x-9) \le -4(2x-9)\end{align*}

Simplify parentheses: \begin{align*}4x-6x+18 \le -8x+36\end{align*}

Collect like terms: \begin{align*}-2x+18 \le -8x+36\end{align*}

Add \begin{align*}8x\end{align*} to both sides: \begin{align*}-2x+8x+18 \le -8x+8x+36\end{align*}

Simplify: \begin{align*}6x+18 \le 36\end{align*}

Subtract 18: \begin{align*}6x+18-18 \le 36-18\end{align*}

Simplify: \begin{align*}6x \le 18\end{align*}

Divide both sides by 6: \begin{align*}\frac{6x}{6} \le \frac{18}{6}\end{align*}

Simplify: \begin{align*}x \le 3\end{align*} **Answer**

Watch this video for help with the Examples above.

CK-12 Foundation: Solving Multi-Step Inequalities

### Vocabulary

- The answer to an
**inequality**is usually an**interval of values**. - Solving inequalities works just like solving an equation. To solve, we isolate the variable on one side of the equation.
- When multiplying or dividing both sides of an inequality by a negative number, you need to
.*reverse the inequality*

### Guided Practice

*Solve the inequality \begin{align*}\frac{5x-1}{4} > -2(x+5)\end{align*}.*

**Solution:**

Original problem: \begin{align*}\frac{5x-1}{4} > -2(x+5)\end{align*}

Simplify parenthesis: \begin{align*}\frac{5x-1}{4} > -2x-10\end{align*}

Multiply both sides by 4: \begin{align*}4 \cdot \frac{5x-1}{4} > 4 (-2x-10)\end{align*}

Simplify: \begin{align*}5x-1 > -8x-40\end{align*}

Add \begin{align*}8x\end{align*} to both sides: \begin{align*}5x + 8x - 1 >- 8x + 8x - 40\end{align*}

Simplify: \begin{align*}13x-1>-40\end{align*}

Add 1 to both sides: \begin{align*}13x-1+1>-40+1\end{align*}

Simplify: \begin{align*}13x > -39\end{align*}

Divide both sides by 13: \begin{align*}\frac{13x}{13} > -\frac{39}{13}\end{align*}

Simplify: \begin{align*}x>-3\end{align*} **Answer**

### Practice

Solve each multi-step inequality.

- \begin{align*}3x-5<x+3\end{align*}
- \begin{align*}x-5 > 2x+3\end{align*}
- \begin{align*}2(x-3) \le 3x-2\end{align*}
- \begin{align*}3(x+1) \ge 2x+5\end{align*}
- \begin{align*}2(x-9) \ge -1(4x+7)\end{align*}
- \begin{align*}\frac{x}{3} < x+7\end{align*}
- \begin{align*}\frac{x}{4} < 2x-21\end{align*}
- \begin{align*}\frac{3(x-4)}{12} \le \frac{2x}{3}\end{align*}
- \begin{align*}2 \left ( \frac{x}{4} + 3\right ) > 6(x-1)\end{align*}
- \begin{align*}9x+4 \le -2 \left ( x+\frac{1}{2} \right )\end{align*}

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### Image Attributions

Here you'll learn how to solve inequalities that require several steps to arrive at the solution. You'll also graph their solution set.