# 11.9: Solving Equations Using the Pythagorean Theorem

**At Grade**Created by: CK-12

**Practice**Solving Equations Using the Pythagorean Theorem

What if you knew the lengths of two sides of a right triangle but not the third? How could you find the length of this missing side? After completing this Concept, you'll be able to use the Pythagorean Theorem to solve problems like this one where variables are involved.

### Guidance

In the previous concept, we learned about the Pythagorean theorem and how to use it to find the hypotenuse. In this concept, we will learn how to use the Pythagorean theorem to find any side of a right triangle.

#### Example A

*Determine the value of the missing side. You may assume that each triangle is a right triangle.*

**Solution**

Apply the Pythagorean Theorem.

\begin{align*}a^2+b^2 &= c^2\\
x^2+15^2 &= 21^2\\
x^2+225 &= 441\\
x^2 &= 216 \Rightarrow \\
x & =\sqrt{216}=6 \sqrt{6}\end{align*}

#### Example B

*Determine the values of the missing sides. You may assume that each triangle is a right triangle.*

**Solution**

Apply the Pythagorean Theorem.

\begin{align*}a^2+b^2 &= c^2\\
18^2+15^2 &= z^2\\
324+225 &= z\\
z^2 &= 549 \Rightarrow \\
z & =\sqrt{549}=3 \sqrt{61}\end{align*}

#### Example C

*One leg of a right triangle is 5 units longer than the other leg. The hypotenuse is one unit longer than twice the size of the short leg. Find the dimensions of the triangle.*

**Solution**

Let \begin{align*}x =\end{align*}

Then \begin{align*}x + 5 =\end{align*}

And \begin{align*}2x + 1 =\end{align*}

The sides of the triangle must satisfy the Pythagorean Theorem.

\begin{align*}\text{Therefore:} && x^2+(x+5)^2& =(2x+1)^2\\
\text{Eliminate the parentheses:} && x^2+x^2+10x+25& =4x^2+4x+1\\
\text{Move all terms to the right hand side of the equation:} && 0& =2x^2-6x-24\\
\text{Divide all terms by} \ 2: && 0& =x^2-3x-12\\
\text{Solve using the quadratic formula:} && x& =\frac{3 \pm \sqrt{9+48}}{2}=\frac{3 \pm \sqrt{57}}{2}\\
&& x& =\underline{\underline{5.27}} \ \text{or} \ x=-2.27\end{align*}

The negative solution doesn’t make sense when we are looking for a physical distance, so we can discard it. Using the positive solution, we get: **\begin{align*}\text{short leg} = 5.27, \text{long leg} = 10.27\end{align*} and \begin{align*}\text{hypotenuse} = 11.54\end{align*}.**

Watch this video for help with the Examples above.

CK-12 Foundation: The Pythagorean Theorem with Variables

### Vocabulary

- The
**Pythagorean Theorem**is a statement of how the lengths of the sides of a right triangle are related to each other. A right triangle is one that contains a 90 degree angle. The side of the triangle opposite the 90 degree angle is called the**hypotenuse**and the sides of the triangle adjacent to the 90 degree angle are called the**legs**.

- If we let \begin{align*}a\end{align*} and \begin{align*}b\end{align*} represent the legs of the right triangle and \begin{align*}c\end{align*} represent the hypotenuse then the
**Pythagorean Theorem**can be stated as:

In a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs. That is: \begin{align*}a^2+b^2=c^2\end{align*}.

### Guided Practice

*Determine the values of the missing sides. You may assume that each triangle is a right triangle.*

**Solution**

Apply the Pythagorean Theorem. \begin{align*}a^2+b^2 &= c^2\\ y^2+3^2 &= 7^2\\ y^2+9 &= 49\\ y^2 &= 40 \Rightarrow\\ y & =\sqrt{40}=2 \sqrt{10}\end{align*}

### Practice

Find the missing length of each right triangle.

- \begin{align*}a = 12, b = 16, c = ?\end{align*}
- \begin{align*}a = ?, b = 20, c = 30\end{align*}
- \begin{align*}a = 4, b = ?, c = 11\end{align*}
- \begin{align*}a = 12, b = ?, c = 37\end{align*}
- One leg of a right triangle is 4 feet less than the hypotenuse. The other leg is 12 feet. Find the lengths of the three sides of the triangle.
- One leg of a right triangle is 3 more than twice the length of the other. The hypotenuse is 3 times the length of the short leg. Find the lengths of the three legs of the triangle.
- Two sides of a right triangle are 5 units and 8 units respectively. Those sides could be the legs, or they could be one leg and the hypotenuse. What are the possible lengths of the third side?

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Hypotenuse

The hypotenuse of a right triangle is the longest side of the right triangle. It is across from the right angle.Legs of a Right Triangle

The legs of a right triangle are the two shorter sides of the right triangle. Legs are adjacent to the right angle.Pythagorean Theorem

The Pythagorean Theorem is a mathematical relationship between the sides of a right triangle, given by , where and are legs of the triangle and is the hypotenuse of the triangle.### Image Attributions

Here you'll learn how to apply the Pythagorean Theorem to find the unknown side lengths of right triangles.