# 6.2: Linear Inequalities

**At Grade**Created by: CK-12

**Practice**Linear Inequalities

What if you had an inequality with an unknown variable like \begin{align*}x - 12 > -5\end{align*}? How could you isolate the variable to find its value? After completing this Concept, you'll be able to solve one-step inequalities like this one.

### Watch This

CK-12 Foundation: 0602S Solving One-Step Inequalities (H264)

### Guidance

To solve an inequality we must isolate the variable on one side of the inequality sign. To isolate the variable, we use the same basic techniques used in solving equations.

We can solve some inequalities by adding or subtracting a constant from one side of the inequality.

#### Example A

*Solve the inequality and graph the solution set.*

\begin{align*}x-3<10\end{align*}

**Solution**

Starting inequality: \begin{align*}x-3 < 10\end{align*}

Add **3** to both sides of the inequality: \begin{align*}x - 3 + 3 < 10 + 3\end{align*}

Simplify: \begin{align*}x < 13\end{align*}

#### Example B

*Solve the inequality and graph the solution set.*

\begin{align*}x-20 \le 14\end{align*}

**Solution:**

Starting inequality: \begin{align*}x - 20 \le 14\end{align*}

Add **20** to both sides of the inequality: \begin{align*}x - 20 + 20 \le 14 + 20\end{align*}

Simplify: \begin{align*}x \le 34\end{align*}

**Solving Inequalities Using Multiplication and Division**

We can also solve inequalities by multiplying or dividing both sides by a constant. For example, to solve the inequality \begin{align*}5x<3\end{align*}, we would divide both sides by 5 to get \begin{align*}x < \frac{3}{5}\end{align*}.

However, something different happens when we multiply or divide by a negative number. We know, for example, that 5 is greater than 3. But if we multiply both sides of the inequality \begin{align*}5>3\end{align*} by -2, we get \begin{align*}-10 > -6\end{align*}. And we know that’s not true; -10 is less than -6.

This happens whenever we multiply or divide an inequality by a negative number, and so we have to flip the sign around to make the inequality true. For example, to multiply \begin{align*}2 < 4\end{align*} by -3, first we multiply the 2 and the 4 each by -3, and then we change the < sign to a > sign, so we end up with \begin{align*}-6 > -12\end{align*}.

The same principle applies when the inequality contains variables.

#### Example C

*Solve the inequality.*

\begin{align*}4x < 24\end{align*}

**Solution:**

Original problem: \begin{align*}4x < 24\end{align*}

Divide both sides by 4: \begin{align*}\frac{4x}{4} < \frac{24}{4}\end{align*}

Simplify: \begin{align*}x < 6\end{align*}

#### Example D

*Solve the inequality.*

\begin{align*}-5x \le 21\end{align*}

**Solution:**

Original problem: \begin{align*}-5x \le 21\end{align*}

Divide both sides by -5 : \begin{align*}\frac{-5x}{-5} \ge \frac{21}{-5}\end{align*} *Flip the inequality sign.*

Simplify: \begin{align*}x \ge -\frac{21}{5}\end{align*}

Watch this video for help with the Examples above.

CK-12 Foundation: Solving One-Step Inequalities

### Vocabulary

- The answer to an
**inequality**is usually an**interval of values**. - Solving inequalities works just like solving an equation. To solve, we isolate the variable on one side of the equation.
- When multiplying or dividing both sides of an inequality by a negative number, you need to
.*reverse the inequality*

### Guided Practice

*Solve each inequality.*

a) \begin{align*}x+8 \le -7\end{align*}

b) \begin{align*}x+4 > 13\end{align*}

c) \begin{align*}\frac{x}{25} < \frac{3}{2}\end{align*}

d) \begin{align*}\frac{x}{-7} \ge 9\end{align*}

**Solutions:**

a) Starting inequality: \begin{align*}x+8 \le -7\end{align*}

Subtract **8** from both sides of the inequality: \begin{align*}x + 8 - 8 \le -7 - 8\end{align*}

Simplify: \begin{align*}x\le -15\end{align*}

b) Starting inequality: \begin{align*}x+4 > 13\end{align*}

Subtract **4** from both sides of the inequality: \begin{align*}x + 4 - 4 > 13 - 4\end{align*}

Simplify: \begin{align*}x > 9\end{align*}

c) Original problem: \begin{align*}\frac{x}{25} < \frac{3}{2}\end{align*}

Multiply both sides by 25: \begin{align*}25 \cdot \frac{x}{25} < \frac{3}{2} \cdot 25\end{align*}

Simplify: \begin{align*}x < \frac{75}{2}\end{align*} or \begin{align*}x < 37.5\end{align*}

d) Original problem: \begin{align*}\frac{x}{-7} \ge 9\end{align*}

Multiply both sides by -7: \begin{align*}-7 \cdot \frac{x}{-7} \le 9 \cdot (-7)\end{align*} *Flip the inequality sign.*

Simplify: \begin{align*}x \le -63\end{align*}

### Practice

For 1-8, solve each inequality and graph the solution on the number line.

- \begin{align*}x-5 < 35\end{align*}
- \begin{align*}x+15 \ge -60\end{align*}
- \begin{align*}x-2 \le 1\end{align*}
- \begin{align*}x-8 > -20\end{align*}
- \begin{align*}x+11>13\end{align*}
- \begin{align*}x+65<100\end{align*}
- \begin{align*}x-32 \le 0\end{align*}
- \begin{align*}x+68 \ge 75\end{align*}

For 9-11, solve each inequality. Write the solution as an inequality and graph it.

- \begin{align*}3x \le 6\end{align*}
- \begin{align*}\frac{x}{5} > -\frac{3}{10}\end{align*}
- \begin{align*}-10x>250\end{align*}
- \begin{align*}\frac{x}{-7} \ge -5\end{align*}

### Notes/Highlights Having trouble? Report an issue.

Color | Highlighted Text | Notes | |
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Show More |

Term | Definition |
---|---|

distributive property |
The distributive property states that the product of an expression and a sum is equal to the sum of the products of the expression and each term in the sum. For example, . |

Linear Inequality |
Linear inequalities are inequalities that can be written in one of the following four forms: , or . |

### Image Attributions

Here you'll learn how to solve inequalities by isolating the variable on one side of the inequality sign. You'll also learn how to graph their solution set.