3.11: Chapter Test
Difficulty Level: At Grade
Created by: CK12
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f(x)=4x−8 is a function. Find
f(−3)  Find ‘
x ’ iff(x)=28  Is the following graph a function? Why or why not?
 What are the domain and range of the above graph?
 Find
 What are the coordinates of the points plotted on the following Cartesian plane?
 The cost of renting the ice surface at the local arena is shown in the table below.
Time (hr)  0  1  2  3  4 

Cost ($)  $200  $250  $300  $350  $400 
(a) Write a linear function to represent the cost of renting the ice surface.
(b) Draw a graph to represent the problem. Label the axis to match the problem.
(c) Write a suitable domain and range for the problem.

 If the graph of
y=x2 undergoes a vertical stretch of23 , what will be they− values for the graph?  Write a mapping rule for the equation
−12(y−6)=(x+7)2 .  For the above mapping rule, create a table of values.
 If the graph of
 Answer the following questions with respect to this graph.
 What is the vertex of the graph? ____________________
 Does the graph have a max value or a min. value? __________Of what? __________
 What is the equation of the axis of symmetry? ____________________
 What is the domain of the graph? ____________________
 What is the range of the graph? ____________________
 For the function
6x+3y−24=0 , determine thex andy− intercepts algebraically. Use the intercepts to draw the graph.  For the following graph, list the transformations of
y=x2 and write the equation to describe the graph.
Answers to Test

f(x)=4x−8
(a)
(b)
(c) The graph is not a function. A vertical line drawn through the graph will intersect it in more than one place.
(d) domain:
range:
 The coordinates of the plotted points are:
A(3,4);B(2,−4);C(−1,−3);D(−2,5);E(−6,1)  The cost of renting the ice surface is modeled by the function
c=50t+200 where ‘c ’ is the cost in dollars and ‘t ’ is the time in hours. 
domain:
{tt≥0,t ε R}
range:
{cc≥200,c ε R}  The
y− values are 1, 4, 9. If the graph undergoes a vertical stretch of23 , the newy− values will be23(1)=23;23(4)=83=223;23(9)=6 . 
−12(y−6)=(x+7)2 Mapping Rule:(x,y)→(x−7,−2y+6)  Table of Values:
 The cost of renting the ice surface is modeled by the function





10  9  12 
2  9  4  2 
1  8  1  4 
0  7  0  6 
1  6  1  4 
2  5  4  2 
3  4  9  12 

 Vertex (4, 3)
 a maximum value of 3

x=−4 
D={xx ε R} 
R={yy≤3,y ε R}
 The transformations of
y=x2 are:VR→NO; VS→12; VT→−5; HT→+3 The equation to model the graph is12(y+5)=(x−3)2
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Date Created:
Jan 16, 2013
Last Modified:
Jan 14, 2015
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