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8.10: Solving Exponential Equations

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Practice Solving Exponential Equations
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"I'm thinking of a number," you tell your best friend. "The number I'm thinking of satisfies the equation 4^{x + 1} = 256 . What number are you thinking of?

Guidance

Until now, we have only solved pretty basic exponential equations, like #1 in the Review Queue above. We know that x=5 , because 2^5=32 . Ones like #4 are a little more challenging, but if we put everything into a power of 2, we can set the exponents equal to each other and solve.

8^x &= 128 \\2^{3x} &= 2^7 \\3x &= 7 \\x &= \frac{7}{3}

So, 8^{\frac{7}{3}} = 128 .

But, what happens when the power is not easily found? We must use logarithms, followed by the Power Property to solve for the exponent.

Example A

Solve 6^x=49 . Round your answer to the nearest three decimal places.

Solution: To solve this exponential equation, let’s take the logarithm of both sides. The easiest logs to use are either \ln (the natural log), or log (log, base 10). We will use the natural log.

6^x &= 49 \\\ln 6^x &= \ln 49 \\x \ln 6 &= \ln 49 \\x &= \frac{\ln 49}{\ln 6} \approx 2.172

Example B

Solve 10^{x-3}=100^{3x+11} .

Solution: Change 100 into a power of 10.

10^{x-3} &= 10^{2(3x+11)} \\x-3 &= 6x+22 \\-25 &= 5x \\-5 &= x

Example C

Solve 8^{2x-3}-4=5 .

Solution: Add 4 to both sides and then take the log of both sides.

8^{2x-3}-4 &= 5 \\8^{2x-3} &= 9 \\\log 8^{2x-3} &= \log 9 \\(2x-3)\log 8 &= \log 9 \\2x-3 &= \frac{\log 9}{\log 8} \\2x &= 3 + \frac{\log 9}{\log 8} \\x &= \frac{3}{2}+\frac{\log 9}{2 \log 8} \approx 2.56

Notice that we did not find the numeric value of \log9 or \log8 until the very end. This will ensure that we have the most accurate answer.

Intro Problem Revisit We can rewrite the equation 4^{x + 1} = 256 as 2^{2(x+1)} = 2^8 and solve for x .

2^{2(x+1)} = 2^8\\2^{2x +2} = 2^8\\2x + 2 =  8\\x = 3

Therefore, you're thinking of the number 3.

Guided Practice

Solve the following exponential equations.

1. 4^{x-8}=16

2. 2(7)^{3x+1} =48

3. \frac{2}{3} \cdot 5^{x+2}+9=21

Answers

1. Change 16 to 4^2 and set the exponents equal to each other.

4^{x-8} &= 16 \\4^{x-8} &= 4^2 \\x-8 &= 2 \\x &=10

2. Divide both sides by 2 and then take the log of both sides.

2(7)^{3x+1} &= 48 \\7^{3x+1} &= 24 \\\ln 7^{3x+1} &= \ln 24 \\(3x+1)\ln 7 &= \ln 24 \\3x+1 &= \frac{\ln 24}{\ln 7} \\3x &= -1 + \frac{\ln 24}{\ln 7} \\x &= -\frac{1}{3} + \frac{\ln 24}{3 \ln 7} \approx 0.211

3. Subtract 9 from both sides and multiply both sides by \frac{3}{2} . Then, take the log of both sides.

\frac{2}{3} \cdot 5^{x+2}+9 &= 21 \\\frac{2}{3} \cdot 5^{x+2} &= 12 \\5^{x+2} &= 18 \\(x+2)\log 5 &= \log 18 \\x &= \frac{\log 18}{\log 5}-2 \approx -0.204

Practice

Use logarithms and a calculator to solve the following equations for x . Round answers to three decimal places.

  1. 5^x = 65
  2. 7^x = 75
  3. 2^x = 90
  4. 3^{x-2} = 43
  5. 6^{x+1}+3=13
  6. 6(11^{3x-2})=216
  7. 8+13^{2x-5}=35
  8. \frac{1}{2} \cdot 7^{x-3}-5=14

Solve the following exponential equations without a calculator.

  1. 4^x=8
  2. 9^{x-2} = 27
  3. 5^{2x+1}=125
  4. 9^3=3^{4x-6}
  5. 7(2^{x-3})=56
  6. 16^x \cdot 4^{x+1}=32^{x+1}
  7. 3^{3x+5}=3 \cdot 9^{x+3}

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At Grade

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Date Created:

Mar 12, 2013

Last Modified:

Oct 28, 2014
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