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22.3: Oxidizing and Reducing Agents

Difficulty Level: At Grade Created by: CK-12
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Practice Oxidizing and Reducing Agents

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Where do we get oxygen for breathing?

Life on planet Earth is a complicated and well-organized set of processes. Animals are designed to breathe oxygen and plants are designed to produce oxygen. Photosynthesis is the means by which we get the oxygen we need for life. Light striking a plant pigment known as chlorophyll initiates a complex series of reactions, many of which involve redox processes complete with movement of electrons. In this series of reactions, water is converted to oxygen gas, and we have something to sustain our lives.

Oxidizing and Reducing Agents

The reaction below is a redox reaction that produces zinc sulfide:

\begin{align*}\text{Zn} + \text{S} \rightarrow \text{ZnS}\end{align*}

The half-reactions can be written:

\begin{align*}& \text{Oxidation:} \quad \text{Zn} \rightarrow \text{Zn}^{2+}+2e^- \\ & \text{Reduction:} \quad \text{S}+2e^- \rightarrow \text{S}^{2-} \end{align*}

In the reaction above, the zinc is being oxidized by losing electrons. However, there must be another substance present that gains those electrons and in this case that is the sulfur. In other words, the sulfur is causing the zinc to be oxidized. Sulfur is called the oxidizing agent. The zinc causes the sulfur to gain electrons and become reduced and so the zinc is called the reducing agent. The oxidizing agent is a substance that causes oxidation by accepting electrons. The reducing agent is a substance that causes reduction by losing electrons. The simplest way to think of this is that the oxidizing agent is the substance that is reduced, while the reducing agent is the substance that is oxidized. The sample problem below shows how to analyze a redox reaction.

Sample Problem: Oxidation-Reduction Reactions

When chlorine gas is bubbled into a solution of sodium bromide, a reaction occurs which produces aqueous sodium chloride and bromine. Determine what is being oxidized and what is being reduced. Identify the oxidizing and reducing agents.

\begin{align*}\text{Cl}_2(g)+2\text{NaBr}(aq) \rightarrow 2\text{NaCl}(aq)+\text{Br}_2(l)\end{align*}

Step 1: Plan the problem.

Break the reaction down into a net ionic equation and then into half-reactions. The substance that loses electrons is being oxidized and is the reducing agent. The substance that gains electrons is being reduced and is the oxidizing agent.

Step 2: Solve.

\begin{align*}\text{Cl}_2(g)+ \cancel{2\text{Na}^+(aq)}+2\text{Br}^-(aq) & \rightarrow \cancel{2\text{Na}^+(aq)}+2\text{Cl}^-(aq)+\text{Br}_2(l) \\ \text{Cl}_2(g)+2\text{Br}^-(aq) & \rightarrow 2\text{Cl}^-(aq)+\text{Br}_2(l) \qquad (\text{net ionic reaction})\end{align*}

\begin{align*}& \text{Oxidation:} \quad \text{Cl}_2(g)+2e^-(aq) \rightarrow 2\text{Cl}^-(aq) \\ & \text{Reduction:} \quad 2\text{Br}^-(aq) \rightarrow \text{Br}_2 (l) + 2e^-\end{align*}

The Cl2 is being reduced and is the oxidizing agent. The Br is being oxidized and is the reducing agent.

Review

1. Define oxidizing agent.
2. Define reducing agent.
3. How does identifying the common ions help in the solution of a redox problem?

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