7.4: Similarity by SSS and SAS
Learning Objectives
 Use SSS and SAS to determine whether triangles are similar.
 Apply SSS and SAS to solve realworld situations.
Review Queue

 What are the congruent angles? List each pair.
 Write the similarity statement.
 If \begin{align*}AB = 8, BD = 20\end{align*}
AB=8,BD=20 , and \begin{align*}BC = 25\end{align*}, find \begin{align*}BE\end{align*}.
 Solve the following proportions.
 \begin{align*}\frac{6}{8} = \frac{21}{x}\end{align*}
 \begin{align*}\frac{x+2}{6} = \frac{2x1}{15}\end{align*}
Know What? Recall from Chapter 2, that the game of pool relies heavily on angles. In Section 2.5, we discovered that \begin{align*}m \angle 1 = m \angle 2\end{align*}.
You decide to hit the cue ball so it follows the yellow path to the right. Are the two triangles similar?
Link for an interactive game of pool: http://www.coolmathgames.com/0poolgeometry/index.html
SSS for Similar Triangles
If you do not know any angle measures, can you say two triangles are similar?
Investigation 72: SSS Similarity
Tools Needed: ruler, compass, protractor, paper, pencil
1. Using Investigation 42, construct a triangle with sides 6 cm, 8 cm, and 10 cm.
2. Construct a second triangle with sides 9 cm, 12 cm, and 15 cm.
3. Using your protractor, measure the angles in both triangles. What do you notice?
4. Line up the corresponding sides. Write down the ratios of these sides. What happens?
To see an animated construction of this, click: http://www.mathsisfun.com/geometry/constructrulercompass1.html
From #3, you should notice that the angles in the two triangles are equal. Second, the sides are all in the same proportion, \begin{align*}\frac{6}{9} = \frac{8}{12} = \frac{10}{15}\end{align*}.
SSS Similarity Theorem: If the corresponding sides of two triangles are proportional, then the two triangles are similar.
If \begin{align*}\frac{AB}{YZ} = \frac{BC}{ZX} = \frac{AC}{XY}\end{align*}, then \begin{align*}\triangle ABC \sim \triangle YZX\end{align*}.
Example 1: Determine if any of the triangles below are similar.
Solution: Compare two triangles at a time.
\begin{align*}\triangle ABC\end{align*} and \begin{align*}\triangle DEF\end{align*}: \begin{align*}\frac{20}{15} = \frac{22}{16} = \frac{24}{18}\end{align*}
Reduce each fraction to see if they are equal. \begin{align*}\frac{20}{15} = \frac{4}{3}, \frac{22}{16} = \frac{11}{8}\end{align*}, and \begin{align*}\frac{24}{18} = \frac{4}{3}\end{align*}.
\begin{align*}\frac{4}{3} \neq \frac{11}{8}, \triangle ABC\end{align*} and \begin{align*}\triangle DEF\end{align*} are not similar.
\begin{align*}\triangle DEF\end{align*} and \begin{align*}\triangle GHI\end{align*}: \begin{align*}\frac{15}{30} = \frac{16}{33} = \frac{18}{36}\end{align*}
\begin{align*}\frac{15}{30} = \frac{1}{2}, \frac{16}{33} = \frac{16}{33}\end{align*}, and \begin{align*}\frac{18}{36} = \frac{1}{2}\end{align*}. \begin{align*}\frac{1}{2} \neq \frac{16}{33}, \triangle DEF\end{align*} is not similar to \begin{align*}\triangle GHI\end{align*}.
\begin{align*}\triangle ABC\end{align*} and \begin{align*}\triangle GHI\end{align*}: \begin{align*}\frac{20}{30} = \frac{22}{33} = \frac{24}{36}\end{align*}
\begin{align*}\frac{20}{30} = \frac{2}{3}, \frac{22}{33} = \frac{2}{3}\end{align*}, and \begin{align*}\frac{24}{36} = \frac{2}{3}\end{align*}. All three ratios reduce to \begin{align*}\frac{2}{3}\end{align*}, \begin{align*}\triangle ABC \sim \triangle GIH\end{align*}.
Example 2: Algebra Connection Find \begin{align*}x\end{align*} and \begin{align*}y\end{align*}, such that \begin{align*}\triangle ABC \sim \triangle DEF\end{align*}.
Solution: According to the similarity statement, the corresponding sides are: \begin{align*}\frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF}\end{align*}. Substituting in what we know, we have \begin{align*}\frac{9}{6} = \frac{4x1}{10} = \frac{18}{y}\end{align*}.
\begin{align*}\frac{9}{6} &= \frac{4x1}{10} && \quad \ \frac{9}{6} = \frac{18}{y}\\ 9(10) &= 6(4x1) && \quad 9y =18(6)\\ 90 &= 24x6 && \quad 9y = 108\\ 96 &= 24x && \quad \ y = 12\\ x &= 4\end{align*}
SAS for Similar Triangles
SAS is the last way to show two triangles are similar.
Investigation 73: SAS Similarity
Tools Needed: paper, pencil, ruler, protractor, compass
1. Using Investigation 43, construct a triangle with sides 6 cm and 4 cm and the included angle is \begin{align*}45^{\circ}\end{align*}.
2. Repeat Step 1 and construct another triangle with sides 12 cm and 8 cm and the included angle is \begin{align*}45^{\circ}\end{align*}.
3. Measure the other two angles in both triangles. What do you notice?
4. Measure the third side in each triangle. Make a ratio. Is this ratio the same as the ratios of the sides you were given?
SAS Similarity Theorem: If two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar.
If \begin{align*}\frac{AB}{XY} = \frac{AC}{XZ}\end{align*} and \begin{align*}\angle A \cong \angle X\end{align*}, then \begin{align*}\triangle ABC \sim \triangle XYZ\end{align*}.
Example 3: Are the two triangles similar? How do you know?
Solution: \begin{align*}\angle B \cong \angle Z\end{align*} because they are both right angles and \begin{align*}\frac{10}{15} = \frac{24}{36}\end{align*}. So, \begin{align*}\frac{AB}{XZ} = \frac{BC}{ZY}\end{align*} and \begin{align*}\triangle ABC \sim \triangle XZY\end{align*} by SAS.
Example 4: Are there any similar triangles? How do you know?
Solution: \begin{align*}\angle A\end{align*} is shared by \begin{align*}\triangle EAB\end{align*} and \begin{align*}\triangle DAC\end{align*}, so it is congruent to itself. Let’s see if \begin{align*}\frac{AE}{AD} = \frac{AB}{AC}\end{align*}.
\begin{align*}\frac{9}{9+3} &= \frac{12}{12+5}\\ \frac{9}{12} &= \frac{3}{4} \neq \frac{12}{17} && \text {The two triangles are} \ not \ \text{similar.}\end{align*}
Example 5: From Example 4, what should \begin{align*}BC\end{align*} equal for \begin{align*}\triangle EAB \sim \triangle DAC\end{align*}?
Solution: The proportion we ended up with was \begin{align*}\frac{9}{12} = \frac{3}{4} \neq \frac{12}{17}\end{align*}. \begin{align*}AC\end{align*} needs to equal 16, so that \begin{align*}\frac{12}{16} = \frac{3}{4}\end{align*}. \begin{align*}AC = AB + BC\end{align*} and \begin{align*}16 = 12 + BC\end{align*}. \begin{align*}BC\end{align*} should equal 4.
Know What? Revisited Yes, the two triangles are similar because they both have a right angle and, from early in this text learned that \begin{align*}m \angle 1 = m \angle 2\end{align*}.
Review Questions
 Questions 15 are vocabulary.
 Questions 618 are similar to Examples 1, 3, and 4 and review.
 Questions 1924 are similar to Examples 3 and 4.
 Questions 2528 are similar to Example 2.
 Questions 29 and 30 are a review of the last section.
Fill in the blanks.
 Two triangles are similar if two angles in each triangle are _____________.
 If all three sides in one triangle are __________________ to the three sides in another, then the two triangles are similar.
 Two triangles are congruent if the corresponding sides are _____________.
 Two triangles are similar if the corresponding sides are _____________.
 If two sides in one triangle are _________________ to two sides in another and the ________________ angles are _________________, then the triangles are ______________.
Use the following diagram for questions 68. The diagram is to scale.
 Are the two triangles similar? Explain your answer.
 Are the two triangles congruent? Explain your answer.
 What is the scale factor for the two triangles?
Fill in the blanks in the statements below. Use the diagram to the left.
 \begin{align*}\triangle ABC \sim \triangle\end{align*}_____
 \begin{align*}\frac{AB}{?} = \frac{BC}{?} = \frac{AC}{?}\end{align*}
 If \begin{align*}\triangle ABC\end{align*} had an altitude, \begin{align*}AG = 10\end{align*}, what would be the length of altitude \begin{align*}\overline{DH}\end{align*}?
 Find the perimeter of \begin{align*}\triangle ABC\end{align*} and \begin{align*}\triangle DEF\end{align*}. Find the ratio of the perimeters.
Use the diagram to the right for questions 1318.
 \begin{align*}\triangle ABC \sim \triangle\end{align*}_____
 Why are the two triangles similar?
 Find \begin{align*}ED\end{align*}.
 \begin{align*}\frac{BD}{?} = \frac{?}{BC} = \frac{DE}{?}\end{align*}
 Is \begin{align*}\frac{AD}{DB} = \frac{CE}{EB}\end{align*} true?
 Is \begin{align*}\frac{AD}{DB} = \frac{AC}{DE}\end{align*} true?
Determine if the following triangles are similar. If so, write the similarity theorem and statement.
Algebra Connection Find the value of the missing variable(s) that makes the two triangles similar.
 At a certain time of day, a building casts a 25 ft shadow. At the same time of day, a 6 ft tall stop sign casts a 15 ft shadow. How tall is the building?
 A child who is 42 inches tall is standing next to the stop sign in #21. How long is her shadow?
Review Queue Answer
 \begin{align*}\angle A \cong \angle D, \angle E \cong \angle C\end{align*}
 \begin{align*}\triangle ABE \sim \triangle DBC\end{align*}
 \begin{align*}BE = 10\end{align*}
 \begin{align*}\frac{6}{8} = \frac{21}{x}, x=28\end{align*}
 \begin{align*}{\;} \ 15(x+2) = 6(2x1)\!\\ {\;} \ 15x+30 = 12x6\!\\ {\;} \quad \quad \ \ \ 3x = 36\!\\ {\;} \quad \quad \ \ \ \ x = 12\end{align*}
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