# 10.3: Area and Perimeter of Triangles

**At Grade**Created by: CK-12

**Practice**Area and Perimeter of Triangles

What if you wanted to find the area of a triangle? How does this relate to the area of a parallelogram? After completing this Concept, you'll be able to answer questions like these.

### Watch This

CK-12 Foundation: Chapter10AreaandPerimeterofTrianglesA

Brightstorm: Area of Triangles

### Guidance

If we take parallelogram and cut it in half, along a diagonal, we would have two congruent triangles. Therefore, the formula for the area of a triangle is the same as the formula for area of a parallelogram, but cut in half.

The **area of a triangle** is \begin{align*}A=\frac{1}{2} bh\end{align*}

#### Example A

Find the area of the triangle.

This is an obtuse triangle. To find the area, we need to find the height of the triangle. We are given the two sides of the small right triangle, where the hypotenuse is also the short side of the obtuse triangle. From these values, we see that the height is 4 because this is a 3-4-5 right triangle. The area is \begin{align*}A=\frac{1}{2} (4)(7)=14 \ units^2\end{align*}

#### Example B

Find the perimeter of the triangle from Example A.

To find the perimeter, we would need to find the longest side of the obtuse triangle. If we used the dotted lines in the picture, we would see that the longest side is also the hypotenuse of the right triangle with legs 4 and 10. Use the Pythagorean Theorem.

\begin{align*}4^2+10^2 &= c^2\\
16+100 &= c^2\\
c &= \sqrt{116} \approx 10.77 \qquad \text{The perimeter is} \ 7 + 5 + 10. 77 = 22.77 \ units\end{align*}

#### Example C

Find the area of a triangle with base of length 28 cm and height of 15 cm.

The area is \begin{align*}\frac{1}{2}(28)(15)=210 \ cm^2\end{align*}

Watch this video for help with the Examples above.

CK-12 Foundation: Chapter10AreaandPerimeterofTrianglesB

### Vocabulary

** Perimeter** is the distance around a shape. The perimeter of any figure must have a unit of measurement attached to it. If no specific units are given (feet, inches, centimeters, etc), write “units.”

**is the amount of space inside a figure. Area is measured in square units.**

*Area*### Guided Practice

Use the triangle to answer the following questions.

- Find the height of the triangle.
- Find the perimeter.
- Find the area.

**Answers:**

1. Use the Pythagorean Theorem to find the height.

\begin{align*} 8^2+h^2&=17^2\\ h^2&=225\\ h&=15 \ in\end{align*}

2. We need to find the hypotenuse. Use the Pythagorean Theorem again.

\begin{align*} (8+24)^2+15^2&=h^2\\ h^2&=1249\\ h&\approx 35.3 \ in\end{align*}

The perimeter is \begin{align*}24+35.3+17 \approx 76.3 \ in\end{align*}

3. The area is \begin{align*}\frac{1}{2}(24)(15)=180 \ in^2\end{align*}

### Practice

Use the triangle to answer the following questions.

- Find the height of the triangle by using the geometric mean.
- Find the perimeter.
- Find the area.

Find the area of the following shape.

- What is the height of a triangle with area \begin{align*}144 \ m^2\end{align*}
144 m2 and a base of 24 m?

For problems 6 and 7 find the height and area of the equilateral triangle with the given perimeter.

- Perimeter 18 units.
- Perimeter 30 units.
- Generalize your results from problems 6 and 7 into a formula to find the height and area of an equilateral triangle with side length \begin{align*}x\end{align*}
x .

Find the area of each triangle.

- Find the area of a triangle with a base of 10 in and a height of 12 in.
- Find the area of a triangle with a base of 5 in and a height of 3 in.
- An equilateral triangle with a height of \begin{align*}6\sqrt{3}\end{align*}
63√ units. - A 45-45-90 triangle with a hypotenuse of \begin{align*}5\sqrt{2}\end{align*}
52√ units. - A 45-45-90 triangle with a leg of 12 units.
- A 30-60-90 triangle with a hypotenuse of 24 units.
- A 30-60-90 triangle with a short leg of 5 units.

### Notes/Highlights Having trouble? Report an issue.

Color | Highlighted Text | Notes | |
---|---|---|---|

Please Sign In to create your own Highlights / Notes | |||

Show More |

Term | Definition |
---|---|

Area |
Area is the space within the perimeter of a two-dimensional figure. |

Perimeter |
Perimeter is the distance around a two-dimensional figure. |

Perpendicular |
Perpendicular lines are lines that intersect at a angle. The product of the slopes of two perpendicular lines is -1. |

Right Angle |
A right angle is an angle equal to 90 degrees. |

Right Triangle |
A right triangle is a triangle with one 90 degree angle. |

Area of a Parallelogram |
The area of a parallelogram is equal to the base multiplied by the height: A = bh. The height of a parallelogram is always perpendicular to the base (the sides are not the height). |

Area of a Triangle |
The area of a triangle is half the area of a parallelogram. Hence the formula: . |

### Image Attributions

Here you'll learn how to calculate the area and perimeter of a triangle and how the area of triangles relates to the area of parallelograms.