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5.6: Comparing Angles and Sides in Triangles

Difficulty Level: At Grade Created by: CK-12
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Practice Comparing Angles and Sides in Triangles
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What if two mountain bikers leave from the same parking lot and head in opposite directions on two different trails? The first rider goes 8 miles due west, then rides due south for 15 miles. The second rider goes 6 miles due east, then changes direction and rides 20\begin{align*}20^\circ\end{align*} east of due north for 17 miles. Both riders have been traveling for 23 miles, but which one is further from the parking lot? After completing this Concept, you will be able to compare triangles in order to answer questions like this one.

Guidance

Look at the triangle below. The sides of the triangle are given. Can you determine which angle is the largest? As you might guess, the largest angle will be opposite 18 because it is the longest side. Similarly, the smallest angle will be opposite the shortest side, 7. Therefore, the angle measure in the middle will be opposite 13.

Theorem: If one side of a triangle is longer than another side, then the angle opposite the longer side will be larger than the angle opposite the shorter side.

Converse: If one angle in a triangle is larger than another angle in a triangle, then the side opposite the larger angle will be longer than the side opposite the smaller angle.

Proof of Theorem:

Given: AC>AB\begin{align*}AC > AB\end{align*}

Prove: mABC>mC\begin{align*}m \angle ABC > m \angle C\end{align*}

Statement Reason
1. AC>AB\begin{align*}AC > AB\end{align*} Given
2. Locate point P\begin{align*}P\end{align*} such that AB=AP\begin{align*}AB = AP\end{align*} Ruler Postulate
3. ABP\begin{align*}\triangle ABP\end{align*} is an isosceles triangle Definition of an isosceles triangle
4. m1=m3\begin{align*}m \angle 1 = m \angle 3\end{align*} Base Angles Theorem
5. m3=m2+mC\begin{align*}m \angle 3 = m \angle 2 + m \angle C\end{align*} Exterior Angle Theorem
6. m1=m2+mC\begin{align*}m \angle 1 = m \angle 2 + m \angle C\end{align*} Substitution PoE
7. mABC=m1+m2\begin{align*}m \angle ABC = m \angle 1 + m \angle 2\end{align*} Angle Addition Postulate
8. mABC=m2+m2+mC\begin{align*}m \angle ABC = m \angle 2 + m \angle 2 + m \angle C\end{align*} Substitution PoE
9. mABC>mC\begin{align*}m \angle ABC > m \angle C\end{align*} Definition of “greater than” (from step 8)

We have two congruent triangles ABC\begin{align*}\triangle ABC\end{align*} and DEF\begin{align*}\triangle DEF\end{align*}, marked below:

Therefore, if AB=DE\begin{align*}AB = DE\end{align*} and BC=EF\begin{align*}BC = EF\end{align*} and mB>mE\begin{align*}m \angle B >m \angle E\end{align*}, then AC>DF\begin{align*}AC > DF\end{align*}. Now, let’s adjust mB>mE\begin{align*}m \angle B >m \angle E\end{align*}. Would that make AC>DF\begin{align*}AC > DF\end{align*}? Yes. See the picture below.

The SAS Inequality Theorem (Hinge Theorem): If two sides of a triangle are congruent to two sides of another triangle, but the included angle of one triangle has greater measure than the included angle of the other triangle, then the third side of the first triangle is longer than the third side of the second triangle.

SSS Inequality Theorem (also called the Converse of the Hinge Theorem): If two sides of a triangle are congruent to two sides of another triangle, but the third side of the first triangle is longer than the third side of the second triangle, then the included angle of the first triangle is greater in measure than the included angle of the second triangle.

Example A

List the sides in order, from shortest to longest.

First, we need to find mA\begin{align*}m \angle A\end{align*}. From the Triangle Sum Theorem, mA+86+27=180\begin{align*}m \angle A + 86^\circ + 27^\circ = 180^\circ\end{align*}. So, mA=67\begin{align*}m \angle A = 67^\circ\end{align*}. Therefore, we can conclude that the longest side is opposite the largest angle. 86\begin{align*}86^\circ\end{align*} is the largest angle, so AC\begin{align*}AC\end{align*} is the longest side. The next largest angle is 67\begin{align*}67^\circ\end{align*}, so BC\begin{align*}BC\end{align*} would be the next longest side. 27\begin{align*}27^\circ\end{align*} is the smallest angle, so AB\begin{align*}AB\end{align*} is the shortest side. In order from shortest to longest, the answer is: AB,BC,AC\begin{align*}AB, BC, AC\end{align*}.

Example B

List the angles in order, from largest to smallest.

Just like with the sides, the largest angle is opposite the longest side. The longest side is BC\begin{align*}BC\end{align*}, so the largest angle is A\begin{align*}\angle A\end{align*}. Next would be B\begin{align*}\angle B\end{align*} and finally A\begin{align*}\angle A\end{align*} is the smallest angle.

Example C

List the sides in order, from least to greatest.

Let’s start with DCE\begin{align*}\triangle DCE\end{align*}. The missing angle is 55\begin{align*}55^\circ\end{align*}. Therefore the sides, in order are CE,CD\begin{align*}CE, CD\end{align*}, and DE\begin{align*}DE\end{align*}. For BCD\begin{align*}\triangle BCD\end{align*}, the missing angle is 43\begin{align*}43^\circ\end{align*}. The order of the sides is BD,CD\begin{align*}BD, CD\end{align*}, and BC\begin{align*}BC\end{align*}. By the SAS Inequality Theorem, we know that BC>DE\begin{align*}BC > DE\end{align*}, so the order of all the sides would be: BD=CE,CD,DE,BC\begin{align*}BD = CE, CD, DE, BC\end{align*}.

Watch this video for help with the Examples above.

Concept Problem Revisited

Even though the two sets of lengths are not equal, they both add up to 23. Therefore, the second rider is further away from the parking lot because 110>90\begin{align*}110^\circ> 90^\circ\end{align*}.

Vocabulary

The Triangle Sum Theorem states that the three angles in a triangle always add up to 180\begin{align*}180^\circ\end{align*}. The median in a triangle connects the midpoint of one side to the opposite vertex. An isosceles triangle is a triangle with at least two congruent sides.

Guided Practice

1. If XM¯¯¯¯¯¯\begin{align*}\overline{XM}\end{align*} is a median of XYZ\begin{align*}\triangle XYZ\end{align*} and XY>XZ\begin{align*}XY > XZ\end{align*}, what can we say about m1\begin{align*}m \angle 1\end{align*} and m2\begin{align*}m \angle 2\end{align*}?

2. List the sides of the two triangles in order, from least to greatest.

3. Below is isosceles triangle ABC\begin{align*}\triangle ABC\end{align*}. List everything you can about the triangle and why.

1. By the definition of a median, M\begin{align*}M\end{align*} is the midpoint of YZ¯¯¯¯¯\begin{align*}\overline{YZ}\end{align*}. This means that YM=MZ\begin{align*}YM = MZ\end{align*}. MX=MX\begin{align*}MX = MX\end{align*} by the Reflexive Property and we know that XY>XZ\begin{align*}XY > XZ\end{align*}. Therefore, we can use the SSS Inequality Theorem to conclude that m1>m2\begin{align*}m \angle 1 >m \angle 2\end{align*}.

2. Here we have no congruent sides or angles. So, let’s look at each triangle separately. Start with XYZ\begin{align*}\triangle XYZ\end{align*}. First the missing angle is 42\begin{align*}42^\circ\end{align*}. The order of the sides is YZ,XY\begin{align*}YZ, XY\end{align*}, and XZ\begin{align*}XZ\end{align*}. For WXZ\begin{align*}\triangle WXZ\end{align*}, the missing angle is 55\begin{align*}55^\circ\end{align*}. The order of these sides is XZ,WZ\begin{align*}XZ, WZ\end{align*}, and WX\begin{align*}WX\end{align*}. Because the longest side in XYZ\begin{align*}\triangle XYZ\end{align*} is the shortest side in WXZ\begin{align*}\triangle WXZ\end{align*}, we can put all the sides together in one list: YZ,XY,XZ,WZ,WX\begin{align*}YZ, XY, XZ, WZ, WX\end{align*}.

3. AB=BC\begin{align*}AB = BC\end{align*} because it is given, mA=mC\begin{align*}m \angle A = m \angle C\end{align*} by the Base Angle Theorem, and AD<DC\begin{align*}AD < DC\end{align*} because mABD<mCBD\begin{align*}m \angle ABD < m \angle CBD\end{align*} and the SAS Triangle Inequality Theorem.

Practice

For questions 1-3, list the sides in order from shortest to longest.

For questions 4-6, list the angles from largest to smallest.

1. Compare m1\begin{align*}m \angle 1\end{align*} and m2\begin{align*}m \angle 2\end{align*}.
2. List the sides from shortest to longest.
3. Compare m1\begin{align*}m \angle 1\end{align*} and m2\begin{align*}m \angle 2\end{align*}. What can you say about m3\begin{align*}m \angle 3\end{align*} and m4\begin{align*}m \angle 4\end{align*}?

In questions 10-12, compare the measures of a\begin{align*}a\end{align*} and b\begin{align*}b\end{align*}.

In questions 13 and 14, list the measures of the sides in order from least to greatest

In questions 15 and 16 is the conclusion true or false?

1. Conclusion: mC<mB<mA\begin{align*}m \angle C < m \angle B < m \angle A\end{align*}
2. Conclusion: AB<DC\begin{align*}AB < DC\end{align*}
3. If AB¯¯¯¯¯\begin{align*}\overline{AB}\end{align*} is a median of CAT\begin{align*}\triangle CAT\end{align*} and CA>AT\begin{align*}CA>AT\end{align*}, explain why ABT\begin{align*}\angle ABT\end{align*} is acute. You may wish to draw a diagram.

Vocabulary Language: English

SAS Inequality Theorem

SAS Inequality Theorem

The SAS Inequality Theorem states that if two sides of a triangle are congruent to two sides of another triangle, but the included angle of one triangle has greater measure than the included angle of the other triangle, then the third side of the first triangle is longer than the third side of the second triangle.
SSS Inequality Theorem

SSS Inequality Theorem

The SSS Inequality Theorem states that if two sides of a triangle are congruent to two sides of another triangle, but the third side of the first triangle is longer than the third side of the second triangle, then the included angle of the first triangle's two congruent sides is greater in measure than the included angle of the second triangle's two congruent sides.
Triangle Sum Theorem

Triangle Sum Theorem

The Triangle Sum Theorem states that the three interior angles of any triangle add up to 180 degrees.

Jul 17, 2012

Feb 26, 2015