# 9.8: Angles Outside a Circle

**At Grade**Created by: CK-12

**Practice**Angles Outside a Circle

What if you wanted to figure out the angle at which the sun's rays hit the earth? The sun’s rays hit the earth such that the tangent rays determine when daytime and night time are. The time and Earth’s rotation determine when certain locations have sun. If the arc that is exposed to sunlight is \begin{align*}178^\circ\end{align*}

### Watch This

CK-12 Foundation: Chapter9AnglesOutsideaCircleA

Learn more about secants by watching the second half of this video.

### Guidance

An angle is considered to be outside a circle if the vertex of the angle is outside the circle and the sides are tangents or secants. There are three types of angles that are outside a circle: an angle formed by two tangents, an angle formed by a tangent and a secant, and an angle formed by two secants. Just like an angle inside or on a circle, an angle outside a circle has a specific formula, involving the intercepted arcs.

##### Investigation: Find the Measure of an Angle outside a Circle

Tools Needed: pencil, paper, ruler, compass, protractor, colored pencils (optional)

- Draw three circles and label the centers \begin{align*}A, B\end{align*}
A,B , and \begin{align*}C\end{align*}C . In \begin{align*}\bigodot A\end{align*}⨀A draw two secant rays with the same endpoint, \begin{align*}\overrightarrow{DE}\end{align*}DE−→− and \begin{align*}\overrightarrow{DF}\end{align*}DF−→− . In \begin{align*}\bigodot B\end{align*}⨀B , draw two tangent rays with the same endpoint, \begin{align*}\overrightarrow{LM}\end{align*}LM−→− and \begin{align*}\overrightarrow{LN}\end{align*}LN−→− . In \begin{align*}\bigodot C\end{align*}⨀C , draw a tangent ray and a secant ray with the same endpoint, \begin{align*}\overrightarrow{QR}\end{align*}QR−→− and \begin{align*}\overrightarrow{QS}\end{align*}QS−→ . Label the points of intersection with the circles like they are in the pictures below. - Draw in all the central angles: \begin{align*}\angle GAH, \angle EAF, \angle MBN, \angle RCT, \angle RCS\end{align*}
∠GAH,∠EAF,∠MBN,∠RCT,∠RCS . Then, find the measures of each of these angles using your protractor. Use color to differentiate. - Find \begin{align*}m \angle EDF, m \angle MLN\end{align*}
m∠EDF,m∠MLN , and \begin{align*}m \angle RQS\end{align*}m∠RQS . - Find \begin{align*}\frac{m \widehat{EF}-m \widehat{GH}}{2}, \frac{m \widehat{MPN}-m \widehat{MN}}{2}\end{align*}, and \begin{align*}\frac{m \widehat{RS}-m \widehat{RT}}{2}\end{align*}. What do you notice?

**Outside Angle Theorem:** The measure of an angle formed by two secants, two tangents, or a secant and a tangent drawn from a point outside the circle is equal to half the difference of the measures of the intercepted arcs.

#### Example A

Find the value of \begin{align*}x\end{align*}. You may assume lines that look tangent, are.

Set up an equation using the Outside Angle Theorem.

\begin{align*}\frac{(5x+10)^\circ-(3x+4)^\circ}{2} &= 30^\circ\\ (5x+10)^\circ-(3x+4)^\circ &= 60^\circ\\ 5x+10^\circ-3x-4^\circ &= 60^\circ\\ 2x+6^\circ &= 60^\circ\\ 2x &= 54^\circ\\ x &= 27^\circ\end{align*}

#### Example B

Find the value of \begin{align*}x\end{align*}.

\begin{align*}x=\frac{120^\circ - 32^\circ}{2}=\frac{88^\circ}{2}=44^\circ\end{align*}.

#### Example C

Find the value of \begin{align*}x\end{align*}.

First note that the missing arc by angle \begin{align*}x\end{align*} measures \begin{align*}32^\circ\end{align*} because the complete circle must make \begin{align*}360^\circ\end{align*}. Then, \begin{align*}x=\frac{141^\circ - 32^\circ}{2}=\frac{109^\circ}{2}=54.5^\circ\end{align*}.

Watch this video for help with the Examples above.

CK-12 Foundation: Chapter9AnglesOutsideaCircleB

#### Concept Problem Revisited

If \begin{align*}178^\circ\end{align*} of the Earth is exposed to the sun, then the angle at which the sun’s rays hit the Earth is \begin{align*}2^\circ\end{align*}. From the Outside Angle Theorem, these two angles are supplementary. From this, we also know that the other \begin{align*}182^\circ\end{align*} of the Earth is not exposed to sunlight and it is probably night time.

### Guided Practice

Find the measure of \begin{align*}x\end{align*}.

1.

2.

3.

**Answers:**

For all of the above problems we can use the Outside Angle Theorem.

1. \begin{align*}x=\frac{125^\circ-27^\circ}{2}=\frac{98^\circ}{2}=49^\circ\end{align*}

2. \begin{align*}40^\circ\end{align*} is not the intercepted arc. Be careful! The intercepted arc is \begin{align*}120^\circ\end{align*}, \begin{align*}(360^\circ-200^\circ-40^\circ)\end{align*}. Therefore, \begin{align*}x=\frac{200^\circ-120^\circ}{2}=\frac{80^\circ}{2}=40^\circ\end{align*}.

3. First, we need to find the other intercepted arc, \begin{align*}360^\circ-265^\circ=95^\circ\end{align*}. \begin{align*}x=\frac{265^\circ-95^\circ}{2}=\frac{170^\circ}{2}=85^\circ\end{align*}

### Interactive Practice

### Explore More

Find the value of the missing variable(s).

Solve for \begin{align*}x\end{align*}.

- Prove the Outside Angle Theorem

Given: Secant rays \begin{align*}\overrightarrow{AB}\end{align*} and \begin{align*}\overrightarrow{AC}\end{align*}

Prove: \begin{align*}m\angle a = \frac{1}{2} \left (m\widehat{BC}-m\widehat{DE} \right )\end{align*}

- Draw two secants that intersect:
- inside a circle.
- on a circle.
- outside a circle.

### Answers for Explore More Problems

To view the Explore More answers, open this PDF file and look for section 9.8.

central angle

An angle formed by two radii and whose vertex is at the center of the circle.chord

A line segment whose endpoints are on a circle.diameter

A chord that passes through the center of the circle. The length of a diameter is two times the length of a radius.inscribed angle

An angle with its vertex on the circle and whose sides are chords.intercepted arc

The arc that is inside an inscribed angle and whose endpoints are on the angle.point of tangency

The point where the tangent line touches the circle.Secant

The secant of an angle in a right triangle is the value found by dividing length of the hypotenuse by the length of the side adjacent the given angle. The secant ratio is the reciprocal of the cosine ratio.Tangent

The tangent of an angle in a right triangle is a value found by dividing the length of the side opposite the given angle by the length of the side adjacent to the given angle.Outside Angles Theorem

The Outside Angles Theorem states that the measure of an angle formed by two secants, two tangents, or a secant and a tangent from a point outside the circle is half the difference of the measures of the intercepted arcs.### Image Attributions

Here you'll learn how to calculate angles formed outside a circle by tangent and secant lines.

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