<meta http-equiv="refresh" content="1; url=/nojavascript/">
Dismiss
Skip Navigation
You are reading an older version of this FlexBook® textbook: CK-12 Math Analysis Concepts Go to the latest version.

8.6: Applications of One-Sided Limits

Difficulty Level: At Grade Created by: CK-12

Early in this section, we practiced finding one-sided limits. In this lesson we will be using that skill and applying it with the rule of limits that says a function must have the same limit from each side in order to have a single limit.

That process allows us to first determine if a function has as limit, and then find the limit if it exists, even if we cannot actually determine the limit directly.

Watch This

Embedded Video:

- James Sousa: Graphing Quadratics

Guidance

When we wish to find the limit of a function f ( x ) as it approaches a point a and we cannot evaluate f ( x ) at a because it is undefined at that point, we can compute the function's one-sided limits in order to find the desired limit. If its one-sided limits are the same, then the desired limit exists and is the value of the one-sided limits. If its one-sided limits are not the same, then the desired limit does not exist. This technique is used in the examples below.

Conditions For a Limit to Exist (The relationship between one-sided and two-sided limits)
In order for the limit L of a function to exist, both of the one-sided limits must exist at x 0 and must have the same value. Mathematically,
\lim_{x \rightarrow x_0} f(x) = L if and only if \lim_{x \rightarrow x_0^-} f(x) = L and \lim_{x \rightarrow x_0^+} f(x) = L .
The One-Sided Limit
If f ( x ) approaches L as x approaches x 0 from the left and from the right, then we write
\lim_{x \rightarrow x_0^+} f(x) = L
\lim_{x \rightarrow x_0^-} f(x) = L
which reads: “the limit of f ( x ) as x approaches x_0^+ (or x_0^- ) from the right (or left) is L .

Example A

Find the limit f ( x ) as x approaches 1. That is, find \lim_{x \rightarrow 1} f(x) if

f(x) = \begin{cases}3 - x,  & x < 1 \\3x - x^2, & x > 1 \end{cases}

Solution

Remember that we are not concerned about finding the value of f ( x ) at x but rather near x . So, for x < 1 (limit from the left),

\lim_{x \rightarrow 1^{-}} f(x) = \lim_{x \rightarrow 1^{-}} (3 - x) = (3 - 1) = 2

and for x > 1 (limit from the right),

\lim_{x \rightarrow 1^+} f(x) = \lim_{x \rightarrow 1^+} (3x - x^2) = 2

Now since the limit exists and is the same on both sides, it follows that

\lim_{x \rightarrow 1} f(x) = 2

Example B

Find \lim_{x \rightarrow 2} \frac{3} {x - 2} .

Solution

From the figure below we see that f(x)=\frac{3} {x - 2} decreases without bound as x approaches 2 from the left and f(x)=\frac{3} {x - 2} increases without bound as x approaches 2 from the right.

This means that \lim_{x \rightarrow 2^-} \frac{3} {x - 2} = -\infty and \lim_{x \rightarrow 2^+} \frac{3} {x - 2} = +\infty . Since f ( x ) is unbounded (infinite) in either directions, the limit does not exist.

Example C

For an object in free fall, such as a stone falling off a cliff, the distance y ( t ) (in meters) that the object falls in t seconds is given by the kinematic equation y ( t ) = 4.9 t 2 . The object’s velocity after 2 seconds is given by v(t) = \lim_{t \rightarrow 2} \frac{y(t) - y(2)} {t - 2} .

What is the velocity of the object after 2 seconds?

Solution

The limit is 19.6 secs. The function can be plotted on a graphing tool, and at 1.999, the graph looks like this:

You can see the result of smaller values of t , by adjusting the t slider on the active graph here: https://www.desmos.com/drive/calculator/1ombivqkdl

Vocabulary

One-sided limits are limits of a function based on an approach from each direction individually.

Guided Practice

Questions

1) Find  \lim_{x \rightarrow -2} (2) .
2) Find  \lim_{x \rightarrow 0^+} (\pi) .
3) Find  \lim_{x \rightarrow 2} \frac{x^2 - 4} {x - 2} .
4) Find  \lim_{x \rightarrow 6} \frac{x - 6} {x^2 - 36} .
5) Find  \lim_{x \rightarrow 5} \sqrt{x^3 - 2x - 1} .

Solutions

1) If a and k are real numbers, then \lim_{x\rightarrow a}k = k .
\therefore  \lim_{x \rightarrow -2} (2) = 2
2) If a and k are real numbers, then \lim_{x\rightarrow a}k = k .
\therefore \lim_{x \rightarrow 0^+} (\pi) = \pi
3) The limit is 4, as shown in the image below. The red line approaches from values above x = 2, and the green line from below. The line is undefined where they meet. This can be examined in greater detail at: https://www.desmos.com/drive/calculator/oowpxjxeu2
4) The limit is \frac{1}{12}
Interact with the graph here: https://www.desmos.com/drive/calculator/jqxhysqmwy
or make a table:
x
5
7
5.5
6.5
f(x)
1/11
1/13
2/23
2/25
5) The limit is \sqrt{114} or apx 10.667
interact with the graph here: https://www.desmos.com/drive/calculator/2ohonznchx

Practice

Based on the graph determine if a limit exists:

Determine if a limit exists:

  1. \lim_{x \to 0} \frac{4x^2}{x}
  2.  <br /> g(x)= \begin{cases} <br /> -2 ; x = - 2\\ <br /> -3x + 3 ; x \not= -2\\ <br /> \end{cases} <br />
  3. \lim_{x \to 3} \frac{-x^2 + 9}{x - 3}
  4.  <br /> g(x)= \begin{cases} <br /> 3 ; x \geq -1\\ <br /> x + 4 ; x < -1\\ <br /> \end{cases} <br />
  5. \lim_{x \to 3} \frac{4x^2 - 15x + 9}{x - 3}
  6.  <br /> h(x)= \begin{cases} <br /> -2; x \geq -1\\ <br /> -5x + 2 ; x < -1\\ <br /> \end{cases} <br />
  7. \lim_{x \to {-1}} \frac{4x^2 - 4}{x + 1}
  8.  <br /> g(x)= \begin{cases} <br /> -3 ; x > 0\\ <br /> x - 3 ; x \leq 0\\ <br /> \end{cases} <br />
  9. \lim_{x \to -4} \frac{x^2 + 5x + 4}{x + 4}
  10.  <br /> g(x)= \begin{cases} <br /> -3x - 4 ; x = 3\\ <br /> -2x - 1 ; x \not= 3\\ <br /> \end{cases} <br />
  11. \lim_{x \to -4} \frac{-3x^2 - 15x - 12}{x + 4}
  12.  <br /> g(x)= \begin{cases} <br /> 4 ; x \leq -3\\ <br /> 3 ; x > -3\\ <br /> \end{cases} <br />
  13. \lim_{x \to 2} \frac{2x^2 - 4x}{x - 2}
  14.  <br /> f(x)= \begin{cases} <br /> -3 ; x = -1\\ <br /> -2 ; x \not= -1\\ <br /> \end{cases} <br />
  15.  \lim_{x \rightarrow 3^+} \frac{3} {x - 3} .
  16. Show that \lim_{x \rightarrow 0^+} \left (\frac{1} {x} - \frac{1} {x^2}\right ) = -\infty .

Vocabulary

continuity

continuity

Continuity for a point exists when the left and right sided limits match the function evaluated at that point. For a function to be continuous, the function must be continuous at every single point in an unbroken domain.
Continuous

Continuous

Continuity for a point exists when the left and right sided limits match the function evaluated at that point. For a function to be continuous, the function must be continuous at every single point in an unbroken domain.
Jump discontinuities

Jump discontinuities

Inverse functions are functions that 'undo' each other. Formally f(x) and g(x) are inverse functions if f(g(x)) = g(f(x)) = x.
limit

limit

A limit is the value that the output of a function approaches as the input of the function approaches a given value.
one-sided limit

one-sided limit

A one-sided limit is the value that a function approaches from either the left side or the right side.
Removable discontinuities

Removable discontinuities

Removable discontinuities are also known as holes. They occur when factors can be algebraically canceled from rational functions.
Removable discontinuity

Removable discontinuity

Removable discontinuities are also known as holes. They occur when factors can be algebraically canceled from rational functions.
two-sided limit

two-sided limit

A two-sided limit is the value that a function approaches from both the left side and the right side.

Image Attributions

Description

Difficulty Level:

At Grade

Grades:

Date Created:

Nov 01, 2012

Last Modified:

Feb 26, 2015

We need you!

At the moment, we do not have exercises for Applications of One-Sided Limits.

Files can only be attached to the latest version of Modality

Reviews

Please wait...
Please wait...
Image Detail
Sizes: Medium | Original
 
MAT.ALY.816.L.1

Original text