# 9.13: Unknown Dimensions of Triangles

**At Grade**Created by: CK-12

^{%}

**Practice**Unknown Dimensions of Triangles

Remember the triangles in the median of the last Concept? Take a look.

If one of these triangles has an area of \begin{align*}11.25 \ ft^2\end{align*}

**To figure this out, you will need to know how to use a formula and find the missing dimension of a triangle. This Concept will teach you how to do that.**

### Guidance

Sometimes a problem will give us the area and ask us to find one of the dimensions of the triangle—either its base or its height. We simply put the information we know in for the appropriate variable in the formula and solve for the unknown measurement.

A triangle has an area of \begin{align*}44 \ m^2\end{align*}

**In this problem, we know the area and the base of the triangle. We put these numbers into the formula and solve for the height, \begin{align*}h\end{align*} h.**

\begin{align*}A & = \frac{1}{2} bh \\ 44 & = \frac{1}{2} 8h \\ 44 \div \frac{1}{2} & = 8h \\ 44(2) & = 8h \\ 88 & = 8h \\ 11 \ m & = h \end{align*}

*Remember, when you divide both sides by a fraction, you need to multiply by its reciprocal. To divide by one-half then, we multiply by 2. Keep this in mind when you use the area formula.*

By solving for \begin{align*}h\end{align*}

\begin{align*}A & = \frac{1}{2} bh \\ A & = \frac{1}{2} 8(11) \\ A & = \frac{1}{2} (88) \\ A & = 44 \ m^2\end{align*}

**We know from the problem that the area is \begin{align*}44 \ m^2\end{align*} 44 m2, so our calculation is correct.**

Now try a few of these on your own.

Given the area and one other dimension, find the missing dimension of each triangle.

#### Example A

Base = 4 inches, Area = 6 sq. inches, what is the height?

**Solution: \begin{align*}h = 3 inches\end{align*} h=3inches**

#### Example B

Base = 5 feet, Area = 7.5 sq. feet, what is the height?

**Solution: \begin{align*}h = 3 feet\end{align*} h=3feet**

#### Example C

Base = 7 meters, Area = 17.5 sq. meters, what is the height?

**Solution: \begin{align*}h = 5 meters\end{align*} h=5meters**

Here is the original problem once again.

If one of these triangles has an area of \begin{align*}11.25 \ ft^2\end{align*}

To figure this out, we can use the formula for finding the area of a triangle.

\begin{align*}A = \frac{1}{2}bh\end{align*}

Now substitute in the given values.

\begin{align*}11.25 = \frac{1}{2}4.5h\end{align*}

\begin{align*}11.25 = 2.25h\end{align*}

\begin{align*}11.25 \ div 2.25 = h\end{align*}

\begin{align*}h = 5 \ ft\end{align*}

**This is our answer.**

### Vocabulary

Here are the vocabulary words in this Concept.

- Triangle
- a figure with three sides and three angles.

- Area
- the space enclosed inside a two-dimensional figure.

- Base
- the bottom part of the triangle

- Height
- the length of the triangle from the base to the vertex

### Guided Practice

Here is one for you to try on your own.

Find the missing base of the triangle.

A triangle has an area of \begin{align*}10.5 \ sq. in\end{align*}

**Answer**

To figure this out, we can solve for the base by using the formula for area of a triangle.

\begin{align*}A = \frac{1}{2}bh\end{align*}

Now we fill in the given information.

\begin{align*}10.5 = \frac{1}{2}(6)b\end{align*}

\begin{align*}10.5 = 3b\end{align*}

\begin{align*}b = 3.5\end{align*}

**The measure of the base of the triangle is \begin{align*}3.5 \ in\end{align*}.**

### Video Review

Here is a video for review.

- This is a James Sousa video on finding the area of a triangle.

### Practice

Directions: Find the missing base or height given the area and one other dimension.

1. Area = 13.5 sq. meters, Base = 9 meters

2. Area = 21 sq. meters, Base = 7 meters

3. Area = 12 sq. meters, Base = 8 meters

4. Area = 33 sq. ft, Base = 11 feet

5. Area = 37.5 sq. ft. Base = 15 feet

6. Area = 60 sq. ft., height = 10 ft.

7. Area = 20.25 sq. in, height = 4.5 in

8. Area = 72 sq. in, height = 8 in

9. Area = 22.5 sq. feet, height = 5 feet

10. Area = 12 sq. in, height = 4 in

11. Area = 45 sq. in, height = 9 in

12. Area = 84 sq. ft, height = 12 ft

13. Area = 144 sq. in, height = 16 in

14. Area = 144.5 sq. ft, height = 17 ft.

15. Area = 123.5 sq. in, height = 19 in

Area

Area is the space within the perimeter of a two-dimensional figure.Base

The side of a triangle parallel with the bottom edge of the paper or screen is commonly called the base. The base of an isosceles triangle is the non-congruent side in the triangle.Height

The height of a triangle is the perpendicular distance from the base of the triangle to the opposite vertex of the triangle.Triangle

A triangle is a polygon with three sides and three angles.### Image Attributions

## Description

## Learning Objectives

Here you'll learn to find unknown dimensions of triangles given area and one other dimension.