# 11.1: Pressure in Fluids

Difficulty Level: At Grade Created by: CK-12
Estimated7 minsto complete
%
Progress
Practice Pressure in Fluids

MEMORY METER
This indicates how strong in your memory this concept is
Progress
Estimated7 minsto complete
%
Estimated7 minsto complete
%
MEMORY METER
This indicates how strong in your memory this concept is

This is the Russian ocean submersible “Mir.” Submersibles like this are necessary for research or work at great depths in the ocean because of the massive pressure. This craft can operate as deep as 6000 meters below the surface. The pressure at 6000 meters below the ocean surface exceeds 8500 pounds per square inch.

### Pressure in Fluids

Pressure is defined as force per unit area, where the force \begin{align*}F\end{align*} is understood to be acting perpendicular to the surface area, \begin{align*}A\end{align*}.

\begin{align*}Pressure=P=\frac{F}{A}\end{align*}

The SI unit for pressure is N/m2. This unit is also known as a pascal (Pa): 1 Pa = 1 N/m2.

\begin{align*}P=\frac{F}{A}=\frac{784 \ \text{N}}{0.0500 \ \text{m}^2}=15,700 \ \text{Pa}\end{align*}

It has been determined experimentally that a fluid exerts pressure equally in all directions.  In the sketch below, from any given point below the surface of the fluid, the pressure in all directions is the same. The fluid exerts the same pressure upward from this point as it does downward.

We can calculate how the pressure of a fluid varies with depth, assuming the fluid has uniform density.

Consider a gigantic tub filled with water as shown below. A column of water with a cross-sectional area of 1.00 m2 is designated. If we multiply the cross-sectional area by the height of the column, we get the volume of water in this column. We can then multiply this volume by the density of water, 1000. kg/m3, and get the mass of water in the column. We then multiply this mass by the acceleration due to gravity, \begin{align*}g\end{align*}, to get the weight of the water in this column.

\begin{align*}F_{\text{weight}}=(\text{area})(\text{height})(\rho)(g)\end{align*}

The pressure exerted by this force would be exerted over the area at the bottom of the column.

\begin{align*}P=\frac{F}{A}=\frac{\rho gh A}{A}=\rho g h\end{align*}

Therefore, the pressure of a column of fluid is proportional to the density of the fluid and to the height of the column of fluid above the level. This is the pressure due to the fluid itself. If an external pressure is exerted at the surface, this must also be taken into account.

Example Problem: The surface of the water in a storage tank is 30.0 m above a water faucet in the kitchen of a house. Calculate the water pressure at the faucet.

Solution: The pressure of the atmosphere acts equally at the surface of the water in the storage tank and on the water leaving the faucet – so it will have no effect. The pressure caused by the column of water will be:

\begin{align*}P=\rho gh=(1000.\ kg/m^3)(9.80 \ m/s^2)(30.0 \ m)=294, 000 \ Pa\end{align*}

#### Summary

• Pressure is defined as force per unit area, \begin{align*}P=\frac{F}{A}\end{align*}.
• The SI unit for pressure is N/m2 which has been named pascal (Pa).
• It has been determined experimentally that a fluid exerts pressure equally in all directions.
• The pressure of a column of fluid is proportional to the density of the fluid and to the height of the column of fluid above the level, \begin{align*}P=\rho gh\end{align*}.
• The average pressure of the atmosphere at sea level is 1.013 × 105 Pa, or 101.3 kPa.

#### Practice

The following video explains fluid pressure. Use this resource to answer the three questions that follow.

1. Why do the streams of water at the bottom of the bottle go the farthest?
2. Why does water stop flowing out of the top hole even before the water level falls below it?

1. Calculate the pressure produced by a force of 800. N acting on an area of  2.00 m2.
2. A swimming pool of width 9.0 m and length 24.0 m is filled with water to a depth of 3.0 m. Calculate pressure on the bottom of the pool due to the water.
3. What is the pressure on the side wall of the pool at the junction with the bottom of the pool in the previous problem?

#### Review

1. If you push the head of a nail against your skin and then push the point of the same nail against your skin with the same force, the point of the nail may pierce your skin while the head of the nail will not. Considering that the forces are the same, what causes the difference?
2. A brick of gold is 10.0 cm wide, 10.0 cm high, and 20.0 cm long. The density of gold is 19.3 g/cm3. What pressure does the brick exert on the table if the brick is resting on its side? What pressure does the brick exert on the table if it is resting on its end?
3. What is the total force and the pressure on the bottom of a swimming pool 8.0 m by 15.0 m whose uniform depth is 2.0 m?

### Notes/Highlights Having trouble? Report an issue.

Color Highlighted Text Notes

Show Hide Details
Description
Difficulty Level:
Authors:
Tags: