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# 9.1: Exploring Geometric Sequences

Difficulty Level: At Grade Created by: CK-12

This activity is intended to supplement Calculus, Chapter 8, Lesson 1.

The height that a ball rebounds to after repeated bounces is an example of a geometric sequence. The top of the ball appears to be about 4.0, 2.8, 2.0, and 1.4 units. If the ratios of consecutive terms of a sequence are the same then it is a geometric sequence. The common ratio r\begin{align*}r\end{align*} for these values is about 0.7.

## Changing the Common Ratio

Explore what happens when the common ratio changes.

Start the Transfrm App. Press Y=\begin{align*}Y=\end{align*} and for Y1\begin{align*}Y1\end{align*}, enter 4A(X1)\begin{align*}4*A ^{\land} (X-1)\end{align*}.

Change your settings by pressing WINDOW and arrow right to go to SETTINGS. Set A=0.7\begin{align*}A = 0.7\end{align*} and Step= 0.1.

Graph the function by pressing ZOOM and selecting ZoomStandard. Change the value of the common ratio (A)\begin{align*}(A)\end{align*}.

1. What did you observe happens when you change the common ratio from positive to negative? Explain why this happens.

2. When the common ratio is larger than 1, explain what happens to the graph and values of y\begin{align*}y\end{align*}.

3. What r\begin{align*}r-\end{align*}values could model the heights of a ball bounce? Explain.

## Changing the Initial Value and the Common Ratio

Press Y=\begin{align*}Y=\end{align*} and change Y1\begin{align*}Y1\end{align*} to BA(X1)\begin{align*}B*A ^{\land} (X-1)\end{align*}.

Change the SETTINGS so that A=0.7\begin{align*}A = 0.7\end{align*}, the B=4\begin{align*}B = 4\end{align*} and Step=0.1\begin{align*}\text{Step} = 0.1\end{align*}.

4. Explain your observations of what happens when B\begin{align*}B\end{align*} changes. What is B\begin{align*}B\end{align*} also known as?

5. If the common ratio is less than -1, describe what occurs to the terms of the sequence.

## Extension – Partial Sum Formula

The sum of a finite geometric series can be useful for calculating funds in your bank account, the depreciation of a car, or the population growth of a city.

e.g. S6=4+8+16+32+64+128\begin{align*}S_6 = 4 + 8 + 16 + 32 + 64 + 128\end{align*}

In this example the common ratio is 2, the first term is 4, and there are 6 terms.

The general formula

Sn=a1+a2+a3++an1+an\begin{align*}S_n = a_1 + a_2 + a_3 + \ldots + a_{n-1} + a_n\end{align*}

Since an=ran1\begin{align*}a_n = r \cdot a_{n-1}\end{align*}, substituting gives

SnrSn=a1+ra1+r2a1+r3a1++rn2a1+rn1a1=ra1+r2a1+r3a1++rn1a1+rna1\begin{align*}S_n & = a_1 + r \cdot a_1 + r^2 \cdot a_1 + r^3 \cdot a_1 + \ldots + r^{n-2} \cdot a_1 + r^{n-1} \cdot a_1 \\ r \cdot S_n & = r \cdot a_1 + r^2 \cdot a_1 + r^3 \cdot a_1 + \ldots + r^{n-1} \cdot a_1 + r^{n} \cdot a_1\end{align*}

Subtracting the previous two lines

SnrSn=a1rna1\begin{align*}S_n - r \cdot S_n = a_1 - r^{n} \cdot a_1\end{align*}

Sn(1r)=a1(1rn)\begin{align*}S_n(1 - r) = a_1(1 - r^n)\end{align*} So Sn=a11rn1r\begin{align*}S_n = a_1 \cdot \frac{1-r^n}{1-r}\end{align*}

Use the formula to find the sum of the following finite geometric series.

6. Find S5\begin{align*}S_5\end{align*} for an=6(13)n1.=\begin{align*}a_n =6 \left (\frac{1}{3} \right )^{n-1}.=\end{align*}

7. 17+172+173+174+175+176=\begin{align*}\frac{1}{7} + \frac{1}{7^2} + \frac{1}{7^3} + \frac{1}{7^4} + \frac{1}{7^5} + \frac{1}{7^6} =\end{align*}

8. Find S25\begin{align*}S_{25}\end{align*} for an=2(1.01)n1\begin{align*}a_n = 2(1.01)^{n - 1}\end{align*}.

9. 6432+168+42+112+1418+116132+1641128+1256=\begin{align*}64 - 32 + 16 - 8 + 4 - 2 + 1 - \frac{1}{2} + \frac{1}{4} - \frac{1}{8} + \frac{1}{16} - \frac{1}{32} + \frac{1}{64} - \frac{1}{128} + \frac{1}{256} =\end{align*}

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Date Created:
Feb 23, 2012