# 4.1: Trigonometric Identities

**At Grade**Created by: CK-12

*This activity is intended to supplement Trigonometry, Chapter 3, Lesson 1.*

##
Problem 1 – Proving cos2θ+sin2θ=1 .

Choose the **VERITRIG** program and select **PROVE ID 1**. Label the triangle with **Text** tool.

To prove:

- Apply the Pythagorean Theorem to the right triangle:
- Define the right triangle trig ratios for the triangle in terms of sine and cosine:
- Substitute
x=cosθ andy=sinθ into your equation from step 1:

##
Problem 2 - Proving sec2θ=1+tan2θ .

Select **PROVE ID 2**. Label the smaller triangle.

For the large triangle, the length of its base is 1. Let

Using our similar triangles, we can now set up proportional ratios. First, let’s start by stating what we know: the ratio of the hypotenuse to the base is

And the ratio of the two sides of the small and large triangles:

- Cross multiply and state what
X andY are equal to:

- Now substitute these values into the Pythagorean Theorem:

## Problem 3 – Numerical verification

Now that we have proved the two identities using our algebra skills, it is always nice to use the power of the calculator lists to numerically verify the two identities.

Select **NUM EXPLORE**. Trace to see the

- As you move the cursor around the circle, state what patterns you notice between the
x− andy− values.

These values are stored in the lists of the calculator with the angle measurements in

- What would you type into the top of a list (a formula) to numerically verify this Pythagorean Identity?
- Enter this in to the top of
L4 . State your results:

Again, to numerically verify

- What would you type into the top of a list to numerically verify this Pythagorean Identity?
- Enter these in to the top of
L5 andL6 . State your results: - Explain why you cannot verify this identity numerically using the lists of the calculator.
- What alternative method can you use to verify the identity?

## Problem 4 – Verifying trig identities using graphing

Verify the identity

You can check any identity with this method.

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