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Balancing Redox Reactions: Oxidation Number Change Method

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Balancing Redox Reactions: Oxidation Number Change Method

Sulfuric acid is one of the most produced chemicals in the United States

Sulfuric acid – useful but hazardous

Sulfuric acid is produced in extremely large quantities in the United States (about 40 million tons/year). This material is manufactured by oxidizing sulfur to form sulfur trioxide. The SO 3 is then dissolved in water to form the sulfuric acid. Most of the sulfuric acid produced is used in fertilizers. This acid is also found in lead-acid car batteries.

Balancing Redox Reactions: Oxidation-Number-Change Method

One way to balance redox reactions is by keeping track of the electron transfer using the oxidation numbers of each of the atoms. For the oxidation-number-change method , start with the unbalanced skeleton equation. The example below is for the reaction of iron(III) oxide with carbon monoxide. This reaction is one that takes place in a blast furnace during the processing of iron ore into metallic iron (see Figure below ):

\text{Fe}_2\text{O}_3(s)+\text{CO}(g) \rightarrow \text{Fe}(s)+\text{CO}_2(g)

Step 1: Assign oxidation numbers to each of the atoms in the equation and write the numbers above the atom.

\overset{\underset{\mathrm{+3}}{}}{\text{Fe}_2} \overset{\underset{\mathrm{-2}}{}}{\text{O}_3}(s) + \overset{\underset{\mathrm{+2}}{}}{\text{C}} \overset{\underset{\mathrm{-2}}{}}{\text{O}}(g) \rightarrow \overset{\underset{\mathrm{0}}{}}{\text{Fe}}(s) + \overset{\underset{\mathrm{+4}}{}}{\text{C}}\overset{\underset{\mathrm{-2}}{}}{\text{O}_2}(g)

Step 2: Identify the atoms that are oxidized and those that are reduced . In the above equation, the carbon atom is being oxidized since its oxidation increases from +2 to +4. The iron atom is being reduced since its oxidation number decreases from +3 to 0.

Step 3: Use a line to connect the atoms that are undergoing a change in oxidation number. On the line, write the oxidation-number change.

Walkthrough of connecting atoms that are oxidized or reduced in a redox reaction

The carbon atom’s oxidation number increases by 2, while the iron atom’s oxidation number decreases by 3. As written, the number of electrons lost does not equal the number of electrons gained. In a balanced redox equation, these must be equal. So, the increase in oxidation number of one atom must be made equal to the decrease in oxidation number of the other.

Step 4: Use coefficients to make the total increase in oxidation number equal to the total decrease in oxidation number . In this case, the least common multiple of 2 and 3 is 6. So the oxidation-number increase should be multiplied by 3, while the oxidation-number decrease should be multiplied by 2. The coefficient is also applied to the formulas in the equation. So a 3 is placed in front of the CO and in front of the CO 2 . A 2 is placed in front of the Fe on the right side of the equation. The Fe 2 O 3 does not require a coefficient because the subscript of 2 after the Fe indicates that there are already two iron atoms.

Walkthrough of balancing the atoms being reduced or oxidized

Step 5: Check the balancing for both atoms and charge. Occasionally, a coefficient may need to be placed in front of a molecular formula that was not involved in the redox process. In the current example, the equation is now balanced.

\text{Fe}_2\text{O}_3(s)+3\text{CO}(g) \rightarrow 2\text{Fe}(s)+3\text{CO}_2(g)

Blast furnaces reduce Iron 3+ into iron metal using carbon monoxide

A blast furnace is where iron ore is processed and turned into iron metal. First, air is blown through a mixture of iron ore and coke (carbon). The carbon monoxide produced reduces the Fe 3+ ions in the iron ore to metallic iron.

Summary

  • The oxidation number-change method of balancing redox equations is described.

Practice

Balance the equations at the link below:

http://www.mpcfaculty.net/mark_bishop/redox_balance_oxidation_exercise.htm

Review

Questions

  1. Why is it important to assign oxidation numbers to all the atoms in the equation?
  2. What are we really balancing using this method?
  3. What do we adjust to make electrons gained equal electrons lost?

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