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# Ion-Product of Water

## Explains the self-ionization of water and how it relates to pH.

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Ion-Product of Water

Source: http://commons.wikimedia.org/wiki/File:Photo-CarBattery.jpg

#### What’s inside?

At one time, you could take the little caps off the top of a car battery and check the condition of the sulfuric acid inside. If it got low, you could add more acid. But, sulfuric acid is hazardous stuff, so the batteries are now sealed to protect people. Because of the acid's dangerous nature, it is not a good idea to cut into a battery to see what it looks like – you could get acid burns.

### The Ion-Product of Water

The self-ionization of water (the process in which water ionizes to hydronium ions and hydroxide ions) occurs to a very limited extent. When two molecules of water collide, there can be a transfer of a hydrogen ion from one molecule to the other. The products are a positively charged hydronium ion and a negatively charged hydroxide ion.

H2O(l)+H2O(l)H3O+(aq)+OH(aq)\begin{align*}\text{H}_2\text{O}(l)+\text{H}_2\text{O}(l) \rightleftarrows \text{H}_3\text{O}^+(aq)+\text{OH}^-(aq)\end{align*}

We often use the simplified form of the reaction:

H2O(l)H+(aq)+OH(aq)\begin{align*}\text{H}_2\text{O}(l) \rightleftarrows \text{H}^+(aq)+\text{OH}^-(aq)\end{align*}

The equilibrium constant for the self-ionization of water is referred to as the ion-product for water and is given the symbol Kw\begin{align*}K_w\end{align*}.

Kw=[H+][OH]\begin{align*}K_w = [ \text{H}^+ ][ \text{OH}^- ]\end{align*}

The ion-product of water (Kw)\begin{align*}(K_w)\end{align*} is the mathematical product of the concentration of hydrogen ions and hydroxide ions. Note that H2O is not included in the ion-product expression because it is a pure liquid. The value of Kw\begin{align*}K_w\end{align*} is very small, in accordance with a reaction that favors the reactants. At 25°C, the experimentally determined value of Kw\begin{align*}K_w\end{align*} in pure water is 1.0 × 10-14.

Kw=[H+][OH]=1.0×1014\begin{align*}K_w=[\text{H}^+][\text{OH}^-]=1.0 \times 10^{-14}\end{align*}

In pure water, the concentrations of hydrogen and hydroxide ions are equal to one another. Pure water or any other aqueous solution in which this ratio holds is said to be neutral. To find the molarity of each ion, the square root of Kw\begin{align*}K_w\end{align*} is taken.

[H+]=[OH]=1.0×107 M\begin{align*}[\text{H}^+]=[\text{OH}^-]=1.0 \times 10^{-7} \ \text{M}\end{align*}

An acidic solution is a solution in which the concentration of hydrogen ions is greater than the concentration of hydroxide ions. For example, hydrogen chloride ionizes to produce H+ and Cl ions upon dissolving in water.

HCl(g)H+(aq)+Cl(aq)\begin{align*}\text{HCl}(g) \rightarrow \text{H}^+(aq) + \text{Cl}^-(aq)\end{align*}

This increases the concentration of H+ ions in the solution. According to LeChâtelier’s principle, the equilibrium represented by H2O(l)H+(aq)+OH(aq)\begin{align*}\text{H}_2\text{O}(l) \rightleftarrows \text{H}^+(aq)+\text{OH}^-(aq)\end{align*} is forced to the left, towards the reactant. As a result, the concentration of the hydroxide ion decreases.

A basic solution is a solution in which the concentration of hydroxide ions is greater than the concentration of hydrogen ions. Solid potassium hydroxide dissociates in water to yield potassium ions and hydroxide ions.

KOH(s)K+(aq)+OH(aq)\begin{align*}\text{KOH}(s) \rightarrow \text{K}^+(aq)+\text{OH}^-(aq)\end{align*}

The increase in concentration of the OH ions causes a decrease in the concentration of the H+ ions and the ion-product of [H+][OH] remains constant

#### Sample Problem: Use of Kw\begin{align*}K_w\end{align*} for an Aqueous Solution

Hydrochloric acid (HCl) is a strong acid, meaning it is 100% ionized in solution. What is the [H+] and the [OH] in a solution of 2.0 × 103 M HCl?

Step 1: List the known values and plan the problem.

Known

• [HCl] = 2.0 × 10-3 M
• Kw=1.0×1014\begin{align*}K_w=1.0 \times 10^{-14}\end{align*}

Unknown

• [H+] = ? M
• [OH-] = ? M

Because HCl is 100% ionized, the concentration of H+ ions in solution will be equal to the original concentration of HCl. Each HCl molecule that was originally present ionizes into one H+ ion and one Cl ion. The concentration of OH can then be determined from the [H+] and Kw\begin{align*}K_w\end{align*}.

Step 2: Solve.

[H+]Kw[OH]=2.0×103 M=[H+][OH]=1.0×1014=Kw[H+]=1.0×10142.0×103=5.0×1012 M\begin{align*}\left [ \text{H}^+ \right ]&=2.0 \times 10^{-3} \ \text{M} \\ K_w &=\left [ \text{H}^+ \right ] \left [ \text{OH}^- \right ]=1.0 \times 10^{-14} \\ \left [ \text{OH}^- \right ] &=\frac{K_w}{\left [ \text{H}^+ \right ]}=\frac{1.0 \times 10^{-14}}{2.0 \times 10^{-3}}=5.0 \times 10^{-12} \ \text{M} \end{align*}

The [H+] is much higher than the [OH] because the solution is acidic. As with other equilibrium constants, the unit for Kw\begin{align*}K_w\end{align*} is customarily omitted.

### Summary

• The self-ionization of water is described and an ionization constant for the process is stated.
• Acidic and basic solutions are defined.
• Calculations using Kw\begin{align*}K_w\end{align*} are illustrated.

### Review

1. What is an acidic solution?
2. What is a basic solution?
3. What is the [OH-] of a solution which has a [H+] of 1×105 M\begin{align*}1 \times 10^{-5} \ M\end{align*}?

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