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# Area and Perimeter of Triangles

## Area is half the base times the height while the perimeter is the sum of the sides.

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Practice Area and Perimeter of Triangles
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Area or Perimeter of Triangles and Quadrilaterals

For both a rhombus and a kite, area can be found if you know the lengths of the diagonals. What is special about the diagonals of these shapes?

#### Watch This

Watch the portions of this video having to do with triangles and quadrilaterals.

http://www.youtube.com/watch?v=ZASBmoylCPc James Sousa: Area and Perimeter Formulas

#### Guidance

Perimeter is the distance around a shape. To find the perimeter of any two dimensional shape, find the sum of the lengths of all the sides.

Area is the number of square units it takes to cover a two dimensional shape. The most basic shape to find the area of is a rectangle. The area of a rectangle is base times height.

AreaRectangle=bh\begin{align*}Area_{Rectangle}=bh\end{align*}

By dissection, a parallelogram can be turned into a rectangle.

Therefore, the area of a parallelogram is also base times height.

AreaParallelogram=bh\begin{align*}Area_{Parallelogram}=bh\end{align*}

You can think of any triangle as half a parallelogram. If you rotate a triangle 180\begin{align*}180^\circ\end{align*} about the midpoint of one of its sides, the original triangle and the new triangle will be a parallelogram.

Therefore, the area of a triangle is base times height divided by two. Remember that any of the three sides can be the base. Also remember that the height must be perpendicular to the base and extend to the highest point of the triangle.

AreaTriangle=bh2=12bh\begin{align*}{Area}_{Triangle}=\frac{bh}{2}=\frac{1}{2}bh\end{align*}

These and other area formulas that are good to know are shown below.

 Shape Area Formula Picture Rectangle A=bh\begin{align*}A=bh\end{align*} Parallelogram A=bh\begin{align*}A=bh\end{align*} Triangle A=bh2\begin{align*}A=\frac{bh}{2}\end{align*} Trapezoid A=(b1+b2)h2\begin{align*}A=\frac{(b_1+b_2)h}{2}\end{align*} Rhombus A=bh\begin{align*}A=bh\end{align*} or A=d1d22\begin{align*}A=\frac{d_1d_2}{2}\end{align*} Kite A=d1d22\begin{align*}A=\frac{d_1d_2}{2}\end{align*} Square A=s2\begin{align*}A=s^2\end{align*}

Example A

Derive the formula for the area of a trapezoid.

Solution: A trapezoid can be thought of as half a parallelogram by rotating it 180\begin{align*}180^\circ\end{align*} about the midpoint of one of its non-parallel sides.

The base of this parallelogram is b1+b2\begin{align*}b_1+b_2\end{align*} and the height is h\begin{align*}h\end{align*}. The area of the parallelogram is (b1+b2)h\begin{align*}(b_1+b_2)h\end{align*}. Therefore, the area of the trapezoid is (b1+b2)h2\begin{align*}\frac{(b_1+b_2)h}{2}\end{align*}.

Example B

Find the area of the trapezoid.

Solution: b1=6\begin{align*}b_1=6\end{align*}, b2=10\begin{align*}b_2=10\end{align*}, h=8\begin{align*}h=8\end{align*}.

Area=(6+10)82=(16)82=64 units2\begin{align*}Area=\frac{(6+10)8}{2}=\frac{(16)8}{2}=64 \ units^2\end{align*}

Example C

Find the area and perimeter of a square with side length 10 inches.

Solution: Perimeter is the distance around the shape. A square has four congruent sides, so each side is 10 inches. The perimeter is 40 in.

Area is the number of square units it takes to cover the shape. The area is 102=100 in2\begin{align*}10^2=100 \ in^2\end{align*}.

Concept Problem Revisited

The diagonals of both rhombuses and kites are perpendicular. This means that when the shapes are broken down into triangles, one diagonal can be the base of the triangle and a portion of the other diagonal will be the height.

#### Vocabulary

Perimeter is the distance around a shape.

Area is the number of square units it takes to cover a two dimensional shape.

#### Guided Practice

1. The diagonals of a rhombus bisect each other. This means that they cut each other in half. The diagonals are also perpendicular. Derive the area formula for a rhombus A=d1d22\begin{align*}A=\frac{d_1d_2}{2}\end{align*}.

2. True or false: To find the area of a parallelogram you just multiply the lengths of two adjacent sides.

3. Explain why the formula A=bh\begin{align*}A=bh\end{align*} works to find the area of a rhombus.

1. The diagonals divide the rhombus into four triangles. For each of the triangles, the base and height are d12\begin{align*}\frac{d_1}{2}\end{align*} and d22\begin{align*}\frac{d_2}{2}\end{align*}. Therefore, the area of each triangle is (d12)(d22)2=d1d28\begin{align*}\frac{\left(\frac{d_1}{2} \right) \left(\frac{d_2}{2} \right)}{2}=\frac{d_1d_2}{8}\end{align*}. The rhombus is made up of four triangles with the same area. The area of the rhombus is 4(d1d28)=d1d22\begin{align*}4 \left(\frac{d_1d_2}{8} \right)=\frac{d_1d_2}{2}\end{align*}.

2. False. The base and height need to be perpendicular. In a generic parallelogram, two adjacent sides will not be perpendicular.

3. A=bh\begin{align*}A=bh\end{align*} is the formula for the area for any parallelogram. Since a rhombus is a parallelogram, this area formula works for a rhombus.

#### Practice

1. Find the area and perimeter of a rectangle with a length of 12 inches and a width of 15 inches.

2. Find the area and perimeter of a right triangle with legs 3 cm and 4 cm and hypotenuse 5 cm.

3. Find the area of a trapezoid with bases 4 cm and 12 cm and height 9 cm.

4. The perimeter of a rectangle is 150 cm. The length is 4 times more than the width. What is the length of the rectangle?

5. The area of a triangle is 30 cm2\begin{align*}30 \ cm^2 \end{align*}. The base is twice as long as the height. What is the height of the triangle?

6. The perimeter of a right triangle is 24 in. The area is 24 in2\begin{align*}24 \ in^2\end{align*}. The hypotenuse is 4 inches longer than the base. What are the lengths of the sides of the triangle?

7. Why is it necessary to use square units (such as in2\begin{align*}in^2\end{align*}) when referring to area?

8. Why don't you use square units when referring to perimeter?

9. When finding the area of a trapezoid, does it matter which sides you label as b1\begin{align*}b_1\end{align*} and b2\begin{align*}b_2\end{align*}?

10. Find the area of a square with a diagonal of 12 in.

11. Explain in your own words why you divide by two in the formula for the area of a triangle.

12. Explain in your own words why you divide by two in the formula for the area of a trapezoid.

13. Find the area of a kite with diagonals 10 cm and 18 cm.

14. Derive the formula A=s2\begin{align*}A=s^2\end{align*} for the area of a square.

15. The diagonals of a kite are perpendicular and one diagonal bisects the other diagonal. Derive the formula \begin{align*}A=\frac{d_1d_2}{2}\end{align*} for the area of a kite.

### Vocabulary Language: English

Area

Area

Area is the space within the perimeter of a two-dimensional figure.
Perimeter

Perimeter

Perimeter is the distance around a two-dimensional figure.
Perpendicular

Perpendicular

Perpendicular lines are lines that intersect at a $90^{\circ}$ angle. The product of the slopes of two perpendicular lines is -1.
Right Angle

Right Angle

A right angle is an angle equal to 90 degrees.
Right Triangle

Right Triangle

A right triangle is a triangle with one 90 degree angle.
Area of a Parallelogram

Area of a Parallelogram

The area of a parallelogram is equal to the base multiplied by the height: A = bh. The height of a parallelogram is always perpendicular to the base (the sides are not the height).
Area of a Triangle

Area of a Triangle

The area of a triangle is half the area of a parallelogram. Hence the formula: $A = \frac{1}{2}bh \text{ or } A = \frac{bh}{2}$.