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Area of Sectors and Segments

Area of parts of a circle.

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Area of Sectors and Segments

Area of Sectors and Segments

A sector of a circle is the area bounded by two radii and the arc between the endpoints of the radii. If \begin{align*}r\end{align*}r is the radius and \begin{align*}\widehat{AB}\end{align*}ABˆ is the arc bounding a sector, then the area of the sector is \begin{align*}A=\frac{m \widehat{AB}}{360^\circ} \cdot \pi r^2\end{align*}A=mABˆ360πr2.

A segment of a circle is the area of a circle that is bounded by a chord and the arc with the same endpoints as the chord. The area of a segment is \begin{align*}A_{segment}=A_{sector}-A_{\triangle ABC}\end{align*}Asegment=AsectorAABC

What if you were given a circle with two radii in which the region between those two radii was shaded? How could you find the area of that shaded region of the circle?

 

 

Examples

Example 1

The area of a sector is \begin{align*}135 \pi\end{align*}135π and the arc measure is \begin{align*}216^\circ\end{align*}216. What is the radius of the circle?

Plug in what you know to the sector area formula and solve for \begin{align*}r\end{align*}r.

\begin{align*}135 \pi &= \frac{216^\circ}{360^\circ} \cdot \pi r^2\\ 135 &= \frac{3}{5} \cdot r^2\\ \frac{5}{3} \cdot 135 &= r^2\\ 225 &= r^2 \rightarrow r=\sqrt{225}=15\end{align*}135π13553135225=216360πr2=35r2=r2=r2r=225=15

Example 2

Find the area of the shaded region. The quadrilateral is a square.

The radius of the circle is 16, which is also half of the diagonal of the square. So, the diagonal is 32 and the sides would be \begin{align*}\frac{32}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}=16 \sqrt{2}\end{align*} because each half of a square is a 45-45-90 triangle.

\begin{align*}A_{circle} &= 16^2 \pi =256 \pi\\ A_{square} &= \left(16 \sqrt{2} \right)^2 = 256 \cdot 2=512\end{align*}

The area of the shaded region is \begin{align*}256 \pi -512 \approx 292.25\end{align*}

Example 3

Find the area of the blue sector. Leave your answer in terms of \begin{align*}\pi\end{align*}.

In the picture, the central angle that corresponds with the sector is \begin{align*}60^\circ\end{align*}. \begin{align*}60^\circ\end{align*} is \begin{align*}\frac{1}{6}\end{align*} of \begin{align*}360^\circ\end{align*}, so this sector is \begin{align*}\frac{1}{6}\end{align*} of the total area. \begin{align*}area \ of \ blue \ sector=\frac{1}{6} \cdot \pi 8^2=\frac{32}{3} \pi\end{align*}

Example 4

The area of a sector is \begin{align*}8\pi\end{align*} and the radius of the circle is 12. What is the central angle?

Plug in what you know to the sector area formula and then solve for the central angle, which we will call \begin{align*}x\end{align*}.

\begin{align*}8 \pi &= \frac{x}{360^\circ} \cdot \pi 12^2\\ 8 \pi & =\frac{x}{360^\circ} \cdot 144 \pi\\ 8 &= \frac{2x}{5^\circ}\\ x &= 8 \cdot \frac{5^\circ}{2}=20^\circ\end{align*}

Example 5

Find the area of the blue segment below.

The area of the segment is the area of the sector minus the area of the isosceles triangle made by the radii. If we split the isosceles triangle in half, each half is a 30-60-90 triangle, where the radius is the hypotenuse. The height of \begin{align*}\triangle ABC\end{align*} is 12 and the base is \begin{align*}2 \left(12 \sqrt{3}\right)=24 \sqrt{3}\end{align*}.

\begin{align*}A_{sector} &= \frac{120}{360} \pi \cdot 24^2 && A_\triangle =\frac{1}{2} \left(24 \sqrt{3} \right)(12)\\ &= 192 \pi && \quad \ =144 \sqrt{3}\end{align*}

The area of the segment is \begin{align*}A=192 \pi - 144 \sqrt{3} \approx 353.8\end{align*} units.

Review

Find the area of the blue sector or segment in \begin{align*}\bigodot A\end{align*}. Leave your answers in terms of \begin{align*}\pi\end{align*}. Round any decimal answers to the nearest hundredth.

Find the radius of the circle. Leave your answer in terms of \begin{align*}\pi\end{align*}.

Find the central angle of each blue sector. Round any decimal answers to the nearest tenth.

  1. Find the area of the sector in \begin{align*}\bigodot A\end{align*}. Leave your answer in terms of \begin{align*}\pi\end{align*}.
  2. Find the area of the equilateral triangle.
  3. Find the area of the segment. Round your answer to the nearest hundredth.
  4. Find the area of the sector in \begin{align*}\bigodot A\end{align*}. Leave your answer in terms of \begin{align*}\pi\end{align*}.
  5. Find the area of the right triangle.
  6. Find the area of the segment. Round your answer to the nearest hundredth.

Review (Answers)

To see the Review answers, open this PDF file and look for section 10.11. 

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Vocabulary

chord

A line segment whose endpoints are on a circle.

circle

The set of all points that are the same distance away from a specific point, called the center.

diameter

A chord that passes through the center of the circle. The length of a diameter is two times the length of a radius.

pi

(or \pi) The ratio of the circumference of a circle to its diameter.

radius

The distance from the center to the outer rim of a circle.

Arc

An arc is a section of the circumference of a circle.

arc length

In calculus, arc length is the length of a plane function curve over an interval.

radian

A radian is a unit of angle that is equal to the angle created at the center of a circle whose arc is equal in length to the radius.

Scale Factor

A scale factor is a ratio of the scale to the original or actual dimension written in simplest form.

Sector

A sector of a circle is a portion of a circle contained between two radii of the circle. Sectors can be measured in degrees.

Sector of a Circle

A sector of a circle is the area bounded by two radii and the arc between the endpoints of the radii.

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