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# Area of a Circle

## Pi times the radius squared.

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Area of a Circle

Angelica’s dad is buying a round swimming pool for the yard. The brochure says diameter=24 ft\begin{align*}\text{diameter} = 24 \ ft\end{align*}. What square footage of the yard will the pool cover?

In this concept, you will learn how to find the area of a circle.

### Guidance

A circle is a set of connected points equidistant from a center point. The diameter is the distance across the center of the circle and the radius is the distance from the center of the circle to the edge.

The number pi, π\begin{align*}\pi\end{align*}, is the ratio of the diameter to the circumference. We use 3.14 to represent pi in operations. You can find the area of a circle by taking the measurement of the radius, squaring it and multiplying it by pi. Here is the formula: A=πr2\begin{align*}A = \pi r^2\end{align*}.

Let’s look at an example.

What is the area of the circle below?

First, write the formula.

A=πr2

Next, substitute in what you know.

A=(3.14)(12)2

Then, following the order of operations, figure out the exponent first and then multiply.

AA==(3.14)(144)452.16 sq cm

The answer is A=452.16 sq.cm\begin{align*}A = 452.16 \ sq. cm\end{align*}.

Sometimes, you will be given a problem with the diameter and not the radius. When this happens, you can divide the measurement of the diameter by two and then use the formula.

### Guided Practice

Some students have formed a circle to play dodge ball. The radius of the circle is 21 feet. What is the area of their dodge ball circle?

First, write the formula.

A=πr2

Next, substitute in what you know.

A=(3.14)(21)2

Then, following the order of operations, figure out the exponent first and then multiply.

AA==(3.14)(441)1,384.74 sq.ft.

The answer is A=1,384.74 sq.ft\begin{align*}A = 1, 384.74 \ sq. ft\end{align*}.

### Examples

#### Example 1

Find the area of a circle with a radius of 9 inches.

First, write the formula.

A=πr2

Next, substitute in what you know.

A=(3.14)(9)2

Then, following the order of operations, figure out the exponent first and then multiply.

AA==(3.14)(81)254.34 sq.in

The answer is A=254.34 sq.in\begin{align*}A = 254.34 \ sq. in\end{align*}.

#### Example 2

Find the area of a circle with a radius of 11 inches.

First, write the formula.

A=πr2

Next, substitute in what you know.

A=(3.14)(11)2

Then, following the order of operations, figure out the exponent first and then multiply.

AA==(3.14)(121)379.94 sq.in.

The answer is A=379.94 sq.in\begin{align*}A = 379.94 \ sq. in\end{align*}.

#### Example 3

Find the area of a circle that has a diameter of 8 feet.

First, recognize that you have been given a diameter and divide by 2 to get the radius.

rrr===d2824 feet

Next, substitute this value, along with pi, into the formula for the area of a circle.

A=πr2

Next, substitute in what you know.

A=(3.14)(4)2

Then, following the order of operations, figure out the exponent first and then multiply.

AA==(3.14)(16)50.24 sq.ft.

The answer is A=50.24 sq.ft\begin{align*}A = 50.24 \ sq. ft\end{align*}.

Remember Angelica and the 24-foot diameter pool?

She wants to know how many square feet of ground it would cover.

First, recognize that you have been given a diameter and divide by 2 to get the radius.

rrr===d224212 feet

Next, substitute this value, along with pi, into the formula for the area of a circle.

A=πr2

Next, substitute in what you know.

A=(3.14)(12)2

Then, following the order of operations, figure out the exponent first and then multiply.

AA==(3.14)(144)452.16 sq.ft.

The answer is A=452.16 sq.ft\begin{align*}A = 452.16 \ sq. ft\end{align*}. The round swimming pool will cover \begin{align*}452.16 \ sq. ft.\end{align*} of Drayton’s backyard.

### Explore More

Find the area of each circle given the radius or diameter. Round to the nearest hundredth when necessary.

1. \begin{align*}r = 3 \ in\end{align*}

2. \begin{align*}r = 5 \ in\end{align*}

3. \begin{align*}r = 4 \ ft\end{align*}

4. \begin{align*}r = 7 \ m\end{align*}

5. \begin{align*} r = 6 \ cm\end{align*}

6. \begin{align*}r = 3.5 \ in\end{align*}

7. \begin{align*}d = 16 \ in\end{align*}

8. \begin{align*}d = 14 \ cm\end{align*}

9. \begin{align*}d = 20 \ in\end{align*}

10. \begin{align*}d = 15 \ m\end{align*}

11. \begin{align*}d = 22 \ cm\end{align*}

12. \begin{align*}d = 24 \ mm\end{align*}

13. \begin{align*}d = 48 \ in\end{align*}

14. \begin{align*}r = 16.5 \ in\end{align*}

15. \begin{align*}r = 25.75 \ in\end{align*}

### Vocabulary Language: English

$\pi$

$\pi$

$\pi$ (Pi) is the ratio of the circumference of a circle to its diameter. It is an irrational number that is approximately equal to 3.14.
Area

Area

Area is the space within the perimeter of a two-dimensional figure.
Diameter

Diameter

Diameter is the measure of the distance across the center of a circle. The diameter is equal to twice the measure of the radius.
Pi

Pi

$\pi$ (Pi) is the ratio of the circumference of a circle to its diameter. It is an irrational number that is approximately equal to 3.14.

The radius of a circle is the distance from the center of the circle to the edge of the circle.
Squaring

Squaring

Squaring a number is multiplying the number by itself. The exponent 2 is used to show squaring.