Do you know the area of a circle is? Well to think about this, let's look once again at the small round table at Jillian's house.

In an earlier Concept, you learned how to measure around the edge of the circumference using the diameter or the radius. The diameter of this table is 4 feet.

Now, you are going to learn how to measure the flat top of the circle. The space inside the circumference of a circle is known as the area of the circle.

Given the diameter, what is the area of this table?

**This Concept is all about calculating area. By the end of it, you will know how to solve this problem.**

### Guidance

In an earlier Concept, you learned about the parts of a circle and about finding the circumference of a circle. This Concept is going to focus on the inside of the circle. The inside of a circle is called the ** area** of the circle.

**What is the area of a circle?**

Remember back to working with quadrilaterals? The area of the quadrilateral is the surface or space inside the quadrilateral. Well, the area of a circle is the same thing. It is the area inside the circle that we are measuring.

In this picture, the area of the circle is yellow. **How do you measure the area of a circle?**

To figure out the area of a circle, we are going to need a couple of different measurements. The first one is pi. We will need to use the numerical value for ** pi, or 3.14**, to represent the ratio between the diameter and the circumference.

The next measurement we need to use is ** the radius**. Remember that the radius is the distance from the center of a circle to the edge, or is 1/2 of the circle's diameter.

We calculate the area of a circle by multiplying the radius squared (multiplied by itself) by pi (3.14).

Here is the formula.

\begin{align*}A = \pi r^2\end{align*}

*Find the area of the circle.*

**Next, we use our formula and the given information.**

\begin{align*}A & = \pi r^2\\ A & = (3.14)(3^2)\\ A & = (3.14)(9)\\ A & = 28.26 \ mm^2\end{align*}

**What about if you have been given the diameter and not the radius?**

If you have been given the diameter and not the radius, you can still figure out the area of the circle. *You start by dividing the measure of the diameter in half since the radius is one-half the measure of the diameter.*

**Then you use the formula and solve for area.**

Notice that the diameter is 6 inches. We can divide this in half to find the radius.

6 \begin{align*}\div\end{align*} 2 \begin{align*}=\end{align*} 3 inches \begin{align*}=\end{align*} radius

**Next, we substitute the given values into the formula and solve for the area of the circle.**

\begin{align*}A & = \pi r^2\\ A & = (3.14)(3^2)\\ A & = (3.14)(9)\\ A & = 28.26 \ in^2\end{align*}

Now it’s time for you to try a few on your own. Find the area of the circle using the given radius or diameter.

#### Example A

\begin{align*}r = 12 \ cm\end{align*}

**Solution: 452.16 sq. cm.**

#### Example B

\begin{align*}r = 18 \ cm\end{align*}

**Solution: 1017.36 sq. cm**

#### Example C

\begin{align*}d = 14 \ in\end{align*}

**Solution: 153.86 sq. in.**

Now let's go back to the original problem from the beginning of this Concept.

Do you know the area of a circle is? Well to think about this, let's look once again at the small round table at Jillian's house.

In an earlier Concept, you learned how to measure around the edge of the circumference using the diameter or the radius. The diameter of this table is 4 feet.

Now, you are going to learn how to measure the flat top of the circle. The space inside the circumference of a circle is known as the area of the circle.

Given the diameter, what is the area of this table?

If you have been given the diameter and not the radius, you can still figure out the area of the circle. You start by dividing the measure of the diameter in half since the radius is one-half the measure of the diameter.

The diameter of the table is 4 feet, so the radius is 2 feet.

**Then you use the formula and solve for area.**

**Next, we substitute the given values into the formula and solve for the area of the circle.**

\begin{align*}A & = \pi r^2\\ A & = (3.14)(2^2)\\ A & = (3.14)(4)\\ A & = 12.56 \ ft^2\end{align*}

**This is our answer.**

### Vocabulary

Here are the vocabulary words in this Concept.

- Area
- the surface or space of the figure inside the perimeter.

- Radius
- the measure of the distance halfway across a circle.

- Diameter
- the measure of the distance across a circle

- Squaring
- uses the exponent 2 to show that a number is being multiplied by itself. \begin{align*}3^2 = 3 \times 3\end{align*}

- Pi
- the ratio of the diameter to the circumference. The numerical value of pi is 3.14.

### Guided Practice

Here is one for you to try on your own.

The diameter of a circle is 13 feet. What is the area of the circle?

**Answer**

To work on this problem, we must first divide the diameter in half to find the radius.

\begin{align*}13 \div 2 = 6.5\end{align*}

The radius is 6.5 feet.

Next, we substitute the given values into the formula for area and solve.

\begin{align*}A & = \pi r^2\\ A & = (3.14)(6.5^2)\\ A & = (3.14)(42.25)\\ A & = 132.665 \ ft^2\end{align*}

Next, we can round up the nearest hundredth.

**The answer is 132.67 sq. feet.**

### Video Review

Here are videos for review.

Khan Academy, Area of a Circle

James Sousa, Example of Determining the Area of a Circle

### Practice

Directions: Find the area of the following circles given the radius.

1. \begin{align*}r = 4 \ in\end{align*}

2. \begin{align*}r = 5 \ cm\end{align*}

3. \begin{align*}r = 8 \ in\end{align*}

4. \begin{align*}r = 2 \ cm\end{align*}

5. \begin{align*}r = 7 \ m\end{align*}

6. \begin{align*}r = 9 \ in\end{align*}

7. \begin{align*}r = 10 \ ft\end{align*}

8. \begin{align*}r = 11 \ cm\end{align*}

9. \begin{align*}r = 20 \ ft\end{align*}

10. \begin{align*}r = 30 \ miles\end{align*}

Directions: Find the area of the following circles given the diameter.

11. \begin{align*}d = 10 \ in\end{align*}

12. \begin{align*}d = 12 \ m\end{align*}

13. \begin{align*}d = 14 \ cm\end{align*}

14. \begin{align*}d = 16 \ ft\end{align*}

15. \begin{align*}d = 18 \ in\end{align*}

16. \begin{align*}d = 22 \ ft\end{align*}

17. \begin{align*}d = 24 \ cm\end{align*}

18. \begin{align*}d = 28 \ m\end{align*}

19. \begin{align*}d = 30 \ m\end{align*}

20. \begin{align*}d = 36 \ ft\end{align*}