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# Linear Pairs

## Two adjacent angles that form a straight line.

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Susan has taken a keen interest in Geometry and wants to expand her knowledge of angles. While looking through a magazine she saw the following picture:

Susan knew the angles had a relationship but she couldn’t remember what they were called or how she could use the information to figure out the size of the angles.

How can Susan use the given measures of the angles to find the measure of each angle in degrees?

In this concept, you will learn to identify adjacent and vertical angles.

When two straight lines intersect each other, four angles are created such that the point of intersection is the vertex for each angle. If two of the angles have a common vertex and share a common side they are called adjacent angles. The adjacent angles formed by two intersecting lines are supplementary which means the sum of their measures is 180\begin{align*}180^\circ\end{align*}.

2\begin{align*}\angle 2 \end{align*} and 4\begin{align*}\angle 4\end{align*} are adjacent angles. The angles are next to each other, have common vertex and share the common side. m2+m4=180\begin{align*}m \angle 2 + m \angle 4 = 180^\circ\end{align*}

These are not the only adjacent angles formed by the intersection of the lines. The remaining pairs of adjacent angles are shown below:

When two lines intersect, vertical angles, which are non-adjacent angles are also formed. There are two pairs of vertical angles. These angles also have a common vertex but never share a common side. The vertical angles are opposite each other and are equal in measure.

There are two pair of vertical angles:

1\begin{align*}\angle 1\end{align*} and 2\begin{align*}\angle 2\end{align*}3\begin{align*}\angle 3 \end{align*} and 4\begin{align*}\angle 4\end{align*}. The m1=m2\begin{align*}m \angle 1 = m \angle 2 \end{align*} and m3=m4\begin{align*}\ m \angle 3 = m \angle 4\end{align*}.

Let’s apply all this information about angles to a problem.

Using the following diagram, calculate the measures of the remaining three angles.

First, state the relationship between JKL\begin{align*}\angle JKL\end{align*} and one other angle.

JKL\begin{align*}\angle JKL\end{align*} and LKN\begin{align*}\angle LKN\end{align*} are adjacent angles.

Next, use this relationship to calculate the measure of LKN\begin{align*}\angle LKN\end{align*}.

mJKL+mLKN=180\begin{align*}m \angle JKL + m \angle LKN = 180^\circ\end{align*}

Next, substitute 43\begin{align*}43^\circ\end{align*}, for the measure of JKL\begin{align*}\angle JKL\end{align*} in the equation.

mJKL+mLKN43+mLKN==180180\begin{align*}\begin{array}{rcl} m \angle JKL + m \angle LKN &=& 180^\circ \\ 43^\circ + m \angle LKN &=& 180^\circ \end{array}\end{align*}

Next, subtract 43\begin{align*}43^\circ\end{align*} from both sides of the equation to solve for mMKN\begin{align*}m \angle MKN\end{align*}.

43+mLKN4343+mLKNmLKN===18018043137\begin{align*}\begin{array}{rcl} 43^\circ + m \angle LKN &=& 180^\circ \\ 43^\circ - 43^\circ + m \angle LKN &=& 180^\circ - 43^\circ \\ {\color{red} m \angle LKN} &{\color{red}=}& {\color{red}137^\circ} \end{array}\end{align*}

First, state another relationship between JKL\begin{align*}\angle JKL\end{align*} and another angle.

JKL\begin{align*}\angle JKL\end{align*} and MKN\begin{align*}\angle MKN\end{align*} are vertical angles.

Next, use this relationship to calculate the measure of MKN\begin{align*} \angle MKN\end{align*}.

mJKL=mMKN\begin{align*}m \angle JKL = m \angle MKN \end{align*}

Next, substitute 43\begin{align*}43^\circ\end{align*}, for the measure of JKL\begin{align*} \angle JKL\end{align*} in the equation.

mJKL43==mMKNmMKN\begin{align*}\begin{array}{rcl} m \angle JKL &=& m \angle MKN \\ {\color{red}43^\circ} & {\color{red}=}& {\color{red} m \angle MKN} \end{array}\end{align*}

First, state the relationship between the remaining angle and one other angle.

LKN\begin{align*}\angle LKN\end{align*} and JKM\begin{align*} \angle JKM\end{align*} are vertical angles.

Next, use this relationship to calculate the measure of JKM\begin{align*}\angle JKM\end{align*}.

mLKN=mJKM\begin{align*}m \angle LKN = m \angle JKM\end{align*}

Next, substitute 137\begin{align*}137^\circ\end{align*}, for the measure of LKN\begin{align*}\angle LKN\end{align*} in the equation.

mLKN137==mJKMmJKM\begin{align*}\begin{array}{rcl} m \angle LKN &=& m \angle JKM \\ {\color{red}137^\circ} &{\color{red}=}& {\color{red}m \angle JKM} \end{array}\end{align*}

### Examples

#### Example 1

Earlier, you were given a problem about Susan and her interest in Geometry.

She needs to figure out the measure of two equal angles.

The two given angles are opposite each other. These angles are vertical angles.

Susan can use the fact that vertical angles are equal in measure to calculate the measure of these angles.

First, write the relation between the two vertical angles such that 1=(2x9)\begin{align*} \angle 1 = (2x - 9)^\circ\end{align*} and 2=(x+39)\begin{align*}\angle 2 = (x+39)^\circ \end{align*}.

m1=m2\begin{align*}m \angle 1 = m \angle 2\end{align*}

Next, substitute the values for each angle into the equation.

(2x9)=(x+39)\begin{align*}(2x - 9)^\circ = (x+39)^\circ\end{align*}

Next, clear the parenthesis by multiplying both sides of the equation by one.

2x9=x+39\begin{align*}2x - 9^\circ = x+39^\circ\end{align*}

Next, add 9 to both sides of the equation to group the constants on one side of the equation.

2x92x9+92x===x+39x+39+9x+48\begin{align*}\begin{array}{rcl} 2x - 9^\circ &=& x+39^\circ \\ 2x - 9^\circ + 9^\circ &=& x + 39^\circ + 9^\circ \\ 2x &=& x+ 48^\circ \end{array}\end{align*}

Next, subtract ‘x\begin{align*}x\end{align*} from both sides of the equation to group the variables on one side of the equation.

2x2xxx===x+48xx+4848\begin{align*}\begin{array}{rcl} 2x &=& x+ 48^\circ \\ 2x - x &=& x - x + 48^\circ \\ x &=& 48^\circ \end{array}\end{align*}

Use the value of the variable to calculate the measure of 1\begin{align*}\angle 1\end{align*} and 2\begin{align*}\angle 2\end{align*}.

1111====(2x9) and 2=(x+39)(2(48)9) and 2=(48+39)(969) and 2=(48+39)87 and 2=87\begin{align*}\begin{array}{rcl} \angle 1 &=& (2x - 9)^\circ \ \text{and} \ \angle 2 = (x + 39)^\circ \\ \angle 1 &=& (2(48) - 9)^\circ \ \text{and} \ \angle 2 = (48 + 39)^\circ \\ \angle 1 &=& (96 - 9)^\circ \ \text{and} \ \angle 2 = (48 + 39)^\circ \\ \angle 1 &=& 87^\circ \ \text{and} \ \angle 2 = 87^\circ \end{array}\end{align*}

The measures of the two vertical angles are equal.

Using the following diagram, calculate the measures of the remaining three angles.

First, state the relationship between 4\begin{align*} \angle 4\end{align*} and one other angle.

4\begin{align*}\angle 4\end{align*} and 2\begin{align*}\angle 2\end{align*} are vertical angles.

Next, use this relationship to calculate the measure of \begin{align*}\angle 2\end{align*}.

\begin{align*}m \angle 4 = m \angle 2\end{align*}

Next, substitute \begin{align*}118^\circ \end{align*}, for the measure of \begin{align*}\angle 4\end{align*} in the equation.

\begin{align*}\begin{array}{rcl} m \angle 4 &=& m \angle 2 \\ {\color{red}118^\circ} &{\color{red}=}& {\color{red}m \angle 2} \end{array}\end{align*}

First, state another relationship between \begin{align*}\angle 4 \end{align*} and another angle.

\begin{align*}\angle 4\end{align*} and \begin{align*}\angle 1 \end{align*} are adjacent angles.

Next, use this relationship to calculate the measure of \begin{align*} \angle 1 \end{align*}.

\begin{align*}m \angle 4 + m \angle 1 = 180^\circ\end{align*}

Next, substitute \begin{align*}118^\circ\end{align*}, for the measure of \begin{align*}\angle 4\end{align*} in the equation.

\begin{align*}\begin{array}{rcl} m \angle 4 + m \angle 1 &=& 180^\circ \\ 118^\circ + m \angle 1 &=& 180^\circ \end{array}\end{align*}

Next, subtract \begin{align*}118^\circ\end{align*} from both sides of the equation to solve for \begin{align*}m \angle 1 \end{align*}.

\begin{align*}\begin{array}{rcl} 118^\circ + m \angle 1 &=& 180^\circ \\ 118^\circ - 118^\circ + m \angle 1 &=& 180^\circ - 118^\circ \\ {\color{red}m \angle 1} & {\color{red}=} & {\color{red} 62^\circ} \end{array}\end{align*}

First, state the relationship between the remaining angle and one other angle.

\begin{align*}\angle 1\end{align*} and \begin{align*}\angle 3\end{align*} are vertical angles.

Next, use this relationship to calculate the measure of \begin{align*}\angle 3\end{align*}.

\begin{align*}m \angle 1 = m \angle 3\end{align*}

Next, substitute \begin{align*}62^\circ\end{align*}, for the measure of \begin{align*}\angle 1 \end{align*} in the equation.

\begin{align*}\begin{array}{rcl} m \angle 1 &=& m \angle 3 \\ {\color{red}62^\circ} &{\color{red}=}& {\color{red}m \angle 3} \end{array}\end{align*}

#### Example 2

Using the following diagram, calculate the measures of the remaining three angles.

First, state the relationship between \begin{align*} \angle 1 \end{align*} and one other angle.

\begin{align*}\angle 1\end{align*} and \begin{align*}\angle 3\end{align*} are vertical angles.

Next, use this relationship to calculate the measure of \begin{align*}\angle 3\end{align*}.

\begin{align*}m \angle 1 = m \angle 3\end{align*}

Next, substitute \begin{align*}40^\circ\end{align*}, for the measure of \begin{align*}\angle 1\end{align*} in the equation.

\begin{align*}\begin{array}{rcl} m \angle 1 &=& m \angle 3 \\ {\color{red}40^\circ} &{\color{red}=}& {\color{red}m \angle 3} \end{array}\end{align*}

First, state another relationship between \begin{align*}\angle 1\end{align*} and another angle.

\begin{align*}\angle 1\end{align*} and \begin{align*}\angle 4\end{align*} are adjacent angles.

Next, use this relationship to calculate the measure of \begin{align*}\angle 4\end{align*}.

\begin{align*}m \angle 1 + m \angle 4 = 180^\circ\end{align*}

Next, substitute \begin{align*}40^\circ\end{align*}, for the measure of \begin{align*}\angle 1\end{align*} in the equation.

\begin{align*}\begin{array}{rcl} m \angle 1 + m \angle 4 &=& 180^\circ \\ 40^\circ + m \angle 4 &=& 180^\circ \end{array}\end{align*}

Next, subtract \begin{align*}40^\circ\end{align*} from both sides of the equation to solve for \begin{align*}m \angle 4\end{align*}.

\begin{align*}\begin{array}{rcl} 40^\circ + m \angle 4 &=& 180^\circ \\ 40^\circ - 40^\circ + m \angle 4 &=& 180^\circ - 40^\circ \\ {\color{red}m \angle 4} &{\color{red}=}&{\color{red}140^\circ} \end{array}\end{align*}

First, state the relationship between the remaining angle and one other angle.

\begin{align*}\angle 4\end{align*} and \begin{align*}\angle 2\end{align*} are vertical angles.

Next, use this relationship to calculate the measure of \begin{align*}\angle 3\end{align*}.

\begin{align*}m \angle 4 = m \angle 2\end{align*}

Next, substitute \begin{align*}140^\circ\end{align*}, for the measure of \begin{align*}\angle 4\end{align*} in the equation.

\begin{align*}\begin{array}{rcl} m \angle 4 &=& m \angle 2 \\ {\color{red}140^\circ} &{\color{red}=}& {\color{red}m \angle 2} \end{array}\end{align*}

### Review

Identify whether each angle pair can be classified as adjacent angles or vertical angles or neither.

1. \begin{align*}\angle INK\end{align*} and \begin{align*} \angle MNL\end{align*}

2. \begin{align*}\angle INJ \end{align*} and \begin{align*}\angle NJK\end{align*}

3. \begin{align*} \angle MNL\end{align*} and \begin{align*} \angle LNK\end{align*}

4. \begin{align*}\angle JNL\end{align*} and \begin{align*}\angle INM\end{align*}

5. \begin{align*}\angle INM \end{align*} and \begin{align*}\angle KNL\end{align*}

6. If \begin{align*}m \angle INJ = 63^\circ\end{align*} then \begin{align*}m \angle MNL = \underline{\;\;\;\;\;\;\;\;\;\;\;\; ^\circ}\end{align*}.

Use this diagram to answer the following questions.

7. True or False. \begin{align*}\angle 1\end{align*} and \begin{align*}\angle 2\end{align*} are adjacent angles.

8. What is the measure of \begin{align*} \angle 1\end{align*} ?

9. What is the measure of \begin{align*}\angle 2\end{align*} ?

10. What is the relationship between \begin{align*}\angle 2\end{align*} and the angle opposite it?

11. True or False. Adjacent angles 1 and 2 form a straight line with a value of \begin{align*}180^\circ\end{align*}

Answer true or false for each question.

12. Supplementary angles are also vertical angles.

13. Vertical angles have the same measure.

14. Adjacent angles always have a sum of \begin{align*}180^\circ\end{align*}.

15. Adjacent angles are also vertical angles.

16. Adjacent angles are formed when lines intersect.

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Color Highlighted Text Notes

### Vocabulary Language: English

TermDefinition
Adjacent Angles Two angles are adjacent if they share a side and vertex. The word 'adjacent' means 'beside' or 'next-to'.
Angle A geometric figure formed by two rays that connect at a single point or vertex.
Diagram A diagram is a drawing used to represent a mathematical problem.
Intersecting lines Intersecting lines are lines that cross or meet at some point.
linear pair Two angles form a linear pair if they are supplementary and adjacent.
Vertical Angles Vertical angles are a pair of opposite angles created by intersecting lines.

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