<img src="https://d5nxst8fruw4z.cloudfront.net/atrk.gif?account=iA1Pi1a8Dy00ym" style="display:none" height="1" width="1" alt="" />

# Perpendicular Lines in the Coordinate Plane

## Lines with opposite sign, reciprocal slopes that intersect at right angles.

Estimated6 minsto complete
%
Progress
Practice Perpendicular Lines in the Coordinate Plane

MEMORY METER
This indicates how strong in your memory this concept is
Progress
Estimated6 minsto complete
%
Perpendicular Lines in the Coordinate Plane

### Perpendicular Lines in the Coordinate Plane

Perpendicular lines are two lines that intersect at a 90\begin{align*}90^\circ\end{align*}, or right, angle. In the coordinate plane, that would look like this:

If we take a closer look at these two lines, the slope of one is -4 and the other is 14\begin{align*}\frac{1}{4}\end{align*}.

This can be generalized to any pair of perpendicular lines in the coordinate plane. The slopes of perpendicular lines are opposite reciprocals of each other.

What if you were given two perpendicular lines in the coordinate plane? What could you say about their slopes?

### Examples

#### Example 1

Find the slope of the line that is perpendicular to this line: y=23x5\begin{align*}y = -\frac{2}{3}x-5\end{align*}.

m=23\begin{align*}m = -\frac{2}{3}\end{align*}, take the reciprocal and change the sign, m=32\begin{align*}m_\perp=\frac{3}{2}\end{align*}.

#### Example 2

Find the slope of the line that is perpendicular to this line: y=x+2\begin{align*}y=x+2\end{align*}.

Because there is no number in front of x\begin{align*}x\end{align*}, the slope is 1. The reciprocal of 1 is 1, so the only thing to do is make it negative, m=1\begin{align*}m_\perp= -1\end{align*}.

#### Example 3

Find the equation of the line that is perpendicular to y=13x+4\begin{align*}y=-\frac{1}{3}x+4\end{align*} and passes through (9, -5).

First, the slope is the opposite reciprocal of 13\begin{align*}-\frac{1}{3}\end{align*}. So, m=3\begin{align*}m = 3\end{align*}. Plug in 9 for x\begin{align*}x\end{align*} and -5 for y\begin{align*}y\end{align*} to solve for the new y\begin{align*}y-\end{align*}intercept (b)\begin{align*}(b)\end{align*}.

5532=3(9)+b=27+b=b\begin{align*}-5 & = 3(9)+b\\ -5 & = 27+b\\ -32 & = b\end{align*}

Therefore, the equation of the perpendicular line is y=3x32\begin{align*}y=3x-32\end{align*}.

#### Example 4

Graph 3x4y=8\begin{align*}3x-4y=8\end{align*} and 4x+3y=15\begin{align*}4x+3y=15\end{align*}. Determine if they are perpendicular.

First, we have to change each equation into slope-intercept form. In other words, we need to solve each equation for y\begin{align*}y\end{align*}.

3x4y4yy=8=3x+8=34x24x+3y=153y=4x+15y=43x+5\begin{align*}3x-4y & = 8 && 4x+3y = 15\\ -4y & = -3x+8 && 3y = -4x + 15\\ y & = \frac{3}{4}x-2 && y = -\frac{4}{3}x+5\end{align*}

Now that the lines are in slope-intercept form (also called y\begin{align*}y-\end{align*}intercept form), we can tell they are perpendicular because their slopes are opposite reciprocals.

#### Example 5

Find the equation of the line that is perpendicular to the line y=2x+7\begin{align*}y=2x+7\end{align*} and goes through the point (2, -2).

The perpendicular line goes through (2, -2), but the slope is 12\begin{align*}-\frac{1}{2}\end{align*} because we need to take the opposite reciprocal of 2\begin{align*}2\end{align*}.

y221=12x+b=12(2)+b=1+b=b\begin{align*}y & = -\frac{1}{2}x+b\\ -2 & = -\frac{1}{2}(2) + b\\ -2 & = -1+b\\ -1 & =b\end{align*}

The equation is y=12x1\begin{align*}y = -\frac{1}{2}x-1\end{align*}.

### Review

Determine if each pair of lines are perpendicular. Then, graph each pair on the same set of axes.

1. y=2x+3\begin{align*}y=-2x+3\end{align*} and y=12x+3\begin{align*}y = \frac{1}{2}x+3\end{align*}
2. y=3x+1\begin{align*}y=-3x+1\end{align*} and y=3x1\begin{align*}y=3x-1\end{align*}
3. 2x3y=6\begin{align*}2x-3y=6\end{align*} and 3x+2y=6\begin{align*}3x+2y=6\end{align*}
4. x3y=3\begin{align*}x-3y=-3\end{align*} and x+3y=9\begin{align*}x+3y=9\end{align*}

Determine the equation of the line that is perpendicular to the given line, through the given point.

1. y=x1; (6,2)\begin{align*}y=x-1; \ (-6, 2)\end{align*}
2. y=3x+4; (9,7)\begin{align*}y=3x+4; \ (9, -7)\end{align*}
3. 5x2y=6; (5,5)\begin{align*}5x-2y= 6; \ (5, 5)\end{align*}
4. y=4; (1,3)\begin{align*}y = 4; \ (-1, 3)\end{align*}

Find the equations of the two lines in each graph below. Then, determine if the two lines are perpendicular.

For the line and point below, find a perpendicular line through the given point.

To see the Review answers, open this PDF file and look for section 3.9.

### Notes/Highlights Having trouble? Report an issue.

Color Highlighted Text Notes

### Vocabulary Language: English Spanish

TermDefinition
perpendicular Two lines that intersect at a $90^\circ$, or right, angle. The slopes of perpendicular lines are opposite reciprocals of each other.

### Explore More

Sign in to explore more, including practice questions and solutions for Perpendicular Lines in the Coordinate Plane.