What if you were told that a scale model of a python is in the ratio of 1:24? If the model measures 0.75 feet long, how long is the real python? After completing this Concept, you'll be able to solve problems like this one by using a proportion.

### Watch This

First watch this video.

Now watch this video.

James Sousa: Applications of Proportions

Finally, watch this video.

James Sousa: Using Similar Triangles to Determine Unknown Values

### Guidance

A
**
proportion
**
is two ratios that are set equal to each other. Usually the ratios in proportions are written in fraction form. An example of a proportion is
\begin{align*}\frac{2}{x}={5}{10}\end{align*}
. To solve a proportion, you need to
**
cross-multiply.
**
The
**
Cross-Multiplication Theorem
**
, which allows us to solve proportions using this method, states that if
@$\begin{align*}a, b, c,\end{align*}@$
and
@$\begin{align*}d\end{align*}@$
are real numbers, with
@$\begin{align*}b \neq 0\end{align*}@$
and
@$\begin{align*}d \neq 0\end{align*}@$
and if
@$\begin{align*}\frac{a}{b} = \frac{c}{d}\end{align*}@$
, then
@$\begin{align*}ad=bc\end{align*}@$
. Cross-multiplying allows us to get rid of the fractions in our equation. The Cross-Multiplication Theorem has several sub-theorems, called
**
corollaries.
**

**
Corollary #1:
**
If
@$\begin{align*}a, b, c,\end{align*}@$
and
@$\begin{align*}d\end{align*}@$
are nonzero and
@$\begin{align*}\frac{a}{b} = \frac{c}{d}\end{align*}@$
, then
@$\begin{align*}\frac{a}{c} = \frac{b}{d}\end{align*}@$
.
**
Switch
**
@$\begin{align*}b\end{align*}@$

**@$\begin{align*}c\end{align*}@$ .**

*and*
**
Corollary #2:
**
If
@$\begin{align*}a, b, c,\end{align*}@$
and
@$\begin{align*}d\end{align*}@$
are nonzero and
@$\begin{align*}\frac{a}{b} = \frac{c}{d}\end{align*}@$
, then
@$\begin{align*}\frac{d}{b} = \frac{c}{a}\end{align*}@$
.
**
Switch
**
@$\begin{align*}a\end{align*}@$

**@$\begin{align*}d\end{align*}@$ .**

*and*
**
Corollary #3:
**
If
@$\begin{align*}a, b, c,\end{align*}@$
and
@$\begin{align*}d\end{align*}@$
are nonzero and
@$\begin{align*}\frac{a}{b} = \frac{c}{d}\end{align*}@$
, then
@$\begin{align*}\frac{b}{a} = \frac{c}{d}\end{align*}@$
.
**
Flip each ratio upside down.
**

**
Corollary #4:
**
If
@$\begin{align*}a, b, c,\end{align*}@$
and
@$\begin{align*}d\end{align*}@$
are nonzero and
@$\begin{align*}\frac{a}{b} = \frac{c}{d}\end{align*}@$
, then
@$\begin{align*}\frac{a+b}{b} = \frac{c+d}{d}\end{align*}@$
.

**
Corollary #5:
**
If
@$\begin{align*}a, b, c,\end{align*}@$
and
@$\begin{align*}d\end{align*}@$
are nonzero and
@$\begin{align*}\frac{a}{b} = \frac{c}{d}\end{align*}@$
, then
@$\begin{align*}\frac{a-b}{b} = \frac{c-d}{d}\end{align*}@$
.

#### Example A

Solve the proportions.

a) @$\begin{align*}\frac{4}{5} = \frac{x}{30}\end{align*}@$

b) @$\begin{align*}\frac{y+1}{8} = \frac{5}{20}\end{align*}@$

c) @$\begin{align*}\frac{6}{5} = \frac{2x+4}{x-2}\end{align*}@$

Remember, to solve a proportion, you need to
**
cross-multiply.
**

a)

b)

c)

#### Example B

Your parents have an architect’s drawing of their home. On the paper, the house’s dimensions are 36 in by 30 in. If the shorter length of the house is actually 50 feet, what is the longer length?

To solve, first set up a proportion. If the shorter length is 50 feet, then it lines up with 30 in, the shorter length of the paper dimensions.

@$$\begin{align*}\frac{30}{36} = \frac{50}{x} \longrightarrow \ 30x &=1800\\ x &=60 \quad \quad \text{The longer length is 60 feet.}\end{align*}@$$

#### Example C

Suppose we have the proportion @$\begin{align*}\frac{2}{5} = \frac{14}{35}\end{align*}@$ . Write three true proportions that follow.

First of all, we know this is a true proportion because you would multiply @$\begin{align*}\frac{2}{5}\end{align*}@$ by @$\begin{align*}\frac{7}{7}\end{align*}@$ to get @$\begin{align*}\frac{14}{35}\end{align*}@$ . Using the first three corollaries:

- @$\begin{align*}\frac{2}{14} = \frac{5}{35}\end{align*}@$
- @$\begin{align*}\frac{35}{5} = \frac{14}{2}\end{align*}@$
- @$\begin{align*}\frac{5}{2} = \frac{35}{14}\end{align*}@$

-->

### Guided Practice

1. In the picture, @$\begin{align*}\frac{AB}{XY} = \frac{BC}{YZ} = \frac{AC}{XZ}\end{align*}@$ .

Find the measures of @$\begin{align*}AC\end{align*}@$ and @$\begin{align*}XY\end{align*}@$ .

2. In the picture, @$\begin{align*}\frac{ED}{AD} = \frac{BC}{AC}\end{align*}@$ . Find @$\begin{align*}y\end{align*}@$ .

3. In the picture, @$\begin{align*}\frac{AB}{BE} = \frac{AC}{CD}\end{align*}@$ . Find @$\begin{align*}BE\end{align*}@$ .

**
Answers:
**

1. Plug in the lengths of the sides we know.

2. Substitute in the lengths of the sides we know.

@$$\begin{align*}\frac{6}{y} = \frac{8}{12+8} \ \longrightarrow \ 8y &= 6(20)\\ y &= 15\end{align*}@$$

3. Substitute in the lengths of the sides we know.

@$$\begin{align*}\frac{12}{BE} = \frac{20}{25} \ \longrightarrow \ {20(BE)} & = 12(25)\\ BE & = 15\end{align*}@$$

### Explore More

Solve each proportion.

- @$\begin{align*}\frac{x}{10} = \frac{42}{35}\end{align*}@$
- @$\begin{align*}\frac{x}{x-2} = \frac{5}{7}\end{align*}@$
- @$\begin{align*}\frac{6}{9} = \frac{y}{24}\end{align*}@$
- @$\begin{align*}\frac{x}{9} = \frac{16}{x}\end{align*}@$
- @$\begin{align*}\frac{y-3}{8} = \frac{y+6}{5}\end{align*}@$
- @$\begin{align*}\frac{20}{z+5} = \frac{16}{7}\end{align*}@$
- Shawna drove 245 miles and used 8.2 gallons of gas. At the same rate, if she drove 416 miles, how many gallons of gas will she need? Round to the nearest tenth.
- The president, vice-president, and financial officer of a company divide the profits is a 4:3:2 ratio. If the company made $1,800,000 last year, how much did each person receive?

Given the true proportion, @$\begin{align*}\frac{10}{6}= \frac{15}{d} = \frac{x}{y}\end{align*}@$ and @$\begin{align*}d, x,\end{align*}@$ and @$\begin{align*}y\end{align*}@$ are nonzero, determine if the following proportions are also true.

- @$\begin{align*}\frac{10}{y} = \frac{x}{6}\end{align*}@$
- @$\begin{align*}\frac{15}{10} = \frac{d}{6}\end{align*}@$
- @$\begin{align*}\frac{6+10}{10} = \frac{y+x}{x}\end{align*}@$
- @$\begin{align*}\frac{15}{x} = \frac{y}{d}\end{align*}@$

For questions 13-16, @$\begin{align*}\frac{AE}{ED} = \frac{BC}{CD}\end{align*}@$ and @$\begin{align*}\frac{ED}{AD} = \frac{CD}{DB} = \frac{EC}{AB}\end{align*}@$ .

- Find @$\begin{align*}DB\end{align*}@$ .
- Find @$\begin{align*}EC\end{align*}@$ .
- Find @$\begin{align*}CB\end{align*}@$ .
- Find @$\begin{align*}AD\end{align*}@$ .