What if you wanted to find the center of rotation and angle of rotation for the arrows in the international recycling symbol below? It is three arrows rotated around a point. Let’s assume that the arrow on the top is the preimage and the other two are its images. Find the center of rotation and the angle of rotation for each image.

### Rotations

A **transformation** is an operation that moves, flips, or changes a figure to create a new figure. A **rigid transformation** is a transformation that preserves size and shape. The rigid transformations are: translations, reflections, and rotations (discussed here). The new figure created by a transformation is called the **image**. The original figure is called the **preimage**. Another word for a rigid transformation is an **isometry**. Rigid transformations are also called **congruence transformations**. If the preimage is \begin{align*}A\end{align*}

A **rotation** is a transformation by which a figure is turned around a fixed point to create an image. The **center of rotation** is the fixed point that a figure is rotated around. Lines can be drawn from the preimage to the center of rotation, and from the center of rotation to the image. The angle formed by these lines is the **angle of rotation.**

In this Lesson, our center of rotation will always be the **origin.** Rotations can also be clockwise or counterclockwise. We will only do **counterclockwise** rotations, to go along with the way the quadrants are numbered.

#### Investigation: Drawing a Rotation of \begin{align*}100^\circ\end{align*}100∘

Tools Needed: pencil, paper, protractor, ruler

- Draw \begin{align*}\triangle ABC\end{align*}
△ABC and a point \begin{align*}R\end{align*}R outside the circle. - Draw the line segment \begin{align*}\overline{RB}\end{align*}
RB¯¯¯¯¯¯¯¯ . - Take your protractor, place the center on \begin{align*}R\end{align*}
R and the initial side on \begin{align*}\overline{RB}\end{align*}RB¯¯¯¯¯¯¯¯ . Mark a \begin{align*}100^\circ\end{align*}100∘ angle. - Find \begin{align*}B'\end{align*}
B′ such that \begin{align*}RB = RB'\end{align*}RB=RB′ . - Repeat steps 2-4 with points \begin{align*}A\end{align*}
A and \begin{align*}C\end{align*}C . - Connect \begin{align*}A', B',\end{align*}
A′,B′, and \begin{align*}C'\end{align*}C′ to form \begin{align*}\triangle A'B'C'\end{align*}△A′B′C′ .

This is the process you would follow to rotate any figure \begin{align*}100^\circ\end{align*}

#### Common Rotations

**Rotation of \begin{align*}180^\circ\end{align*}**If \begin{align*}(x, y)\end{align*}180∘ :(x,y) is rotated \begin{align*}180^\circ\end{align*}180∘ around the origin, then the image will be \begin{align*}(-x, -y)\end{align*}(−x,−y) .**Rotation of \begin{align*}90^\circ\end{align*}**If \begin{align*}(x, y)\end{align*}90∘ :(x,y) is rotated \begin{align*}90^\circ\end{align*}90∘ around the origin, then the image will be \begin{align*}(-y, x)\end{align*}(−y,x) .**Rotation of \begin{align*}270^\circ\end{align*}**If \begin{align*}(x, y)\end{align*}270∘ :(x,y) is rotated \begin{align*}270^\circ\end{align*}270∘ around the origin, then the image will be \begin{align*}(y, -x)\end{align*}(y,−x) .

While we can rotate any image any amount of degrees, only \begin{align*}90^\circ, 180^\circ\end{align*}

#### Rotating a Triangle

Rotate \begin{align*}\triangle ABC\end{align*}

It is very helpful to graph the triangle. If \begin{align*}A\end{align*}** left** of the origin and 4 units

**The vertices are:**

*down.*\begin{align*}A(7,4) \rightarrow A'(-7,-4)\\
B(6,1) \rightarrow B'(-6,-1)\\
C(3,1) \rightarrow C'(-3,-1)\end{align*}

#### Rotating a Line Segment

Rotate \begin{align*}\overline{ST} \ 90^\circ\end{align*}

Using the \begin{align*}90^\circ\end{align*}

#### Finding Coordinates After a Rotation

Find the coordinates of \begin{align*}ABCD\end{align*}

Using the rule, we have:

\begin{align*}(x,y) & \rightarrow (y,-x)\\
A(-4,5) & \rightarrow A'(5,4)\\
B(1,2) & \rightarrow B'(2,-1)\\
C(-6,-2) & \rightarrow C'(-2,6)\\
D(-8,3) & \rightarrow D'(3,8)\end{align*}

#### Recycling Problem Revisited

The center of rotation is shown in the picture below. If we draw rays to the same point in each arrow, we see that the two images are a \begin{align*}120^\circ\end{align*} rotation in either direction.

### Examples

#### Example 1

The rotation of a quadrilateral is shown below. What is the measure of \begin{align*}x\end{align*} and \begin{align*}y\end{align*}?

Because a rotation is an isometry that produces congruent figures, we can set up two equations to solve for \begin{align*}x\end{align*} and \begin{align*}y\end{align*}.

\begin{align*}2y &= 80^\circ && \ 2x-3 =15\\ y &= 40^\circ && \qquad 2x = 18\\ &&& \qquad \ \ x = 9\end{align*}

#### Example 2

A rotation of \begin{align*}80^\circ\end{align*} clockwise is the same as what counterclockwise rotation?

There are \begin{align*}360^\circ\end{align*} around a point. So, an \begin{align*}80^\circ\end{align*} rotation clockwise is the same as a \begin{align*}360^\circ-80^\circ=280^\circ\end{align*} rotation counterclockwise.

#### Example 3

A rotation of \begin{align*}160^\circ\end{align*} counterclockwise is the same as what clockwise rotation?

\begin{align*}360^\circ-160^\circ=200^\circ\end{align*} clockwise rotation.

### Review

In the questions below, every rotation is *counterclockwise,* unless otherwise stated.

- If you rotated the letter \begin{align*}p \ 180^\circ\end{align*} counterclockwise, what letter would you have?
- If you rotated the letter \begin{align*}p \ 180^\circ\end{align*}
*clockwise,*what letter would you have? Why do you think that is? - A \begin{align*}90^\circ\end{align*} clockwise rotation is the same as what counterclockwise rotation?
- A \begin{align*}270^\circ\end{align*} clockwise rotation is the same as what counterclockwise rotation?
- Rotating a figure \begin{align*}360^\circ\end{align*} is the same as what other rotation?

Rotate each figure in the coordinate plane the given angle measure. The center of rotation is the origin.

- \begin{align*}180^\circ\end{align*}
- \begin{align*}90^\circ\end{align*}
- \begin{align*}180^\circ\end{align*}
- \begin{align*}270^\circ\end{align*}
- \begin{align*}90^\circ\end{align*}
- \begin{align*}270^\circ\end{align*}
- \begin{align*}180^\circ\end{align*}
- \begin{align*}270^\circ\end{align*}
- \begin{align*}90^\circ\end{align*}

** Algebra Connection** Find the measure of \begin{align*}x\end{align*} in the rotations below. The blue figure is the preimage.

Find the angle of rotation for the graphs below. The center of rotation is the origin and the blue figure is the preimage.

### Review (Answers)

To view the Review answers, open this PDF file and look for section 12.4.