Recall that a sphere is the set of all points in space that are equidistant from a given point. The distance from the center of a sphere to any point on the sphere is the radius.
You have seen the formula for the volume of a sphere before.
The volume of the sphere is the same as the volume of the space between the cylinder and the double cone.
Consider half of the double cone inside the cylinder and half the sphere (a hemisphere). If the radius of the sphere is 5 inches, label all the dimensions that you can. What is the area of the top surface of the hemisphere? What is the area of the top of the cylinder?
First consider the vertical cross section through the center of the cone in the cylinder.
Note that because the height and the radius of the cone are each 5 inches, isosceles right triangles are formed. Next consider the vertical cross section through the center of the sphere.
Now you can consider the horizontal cross sections.
Note that the shaded areas are the cross sections of the solids you are interested in. You are looking for the volume of the space between the cylinder and the cone and the volume of the sphere.
Confirm that the area of each shaded region below is the same. What does this tell you about the volume of the space between the cylinder and the cone compared to the volume of the sphere?
The area of the shaded region on the left is:
The area of the shaded region on the right is:
The areas are the same. Because the two solids lie between parallel planes, have the same heights, and have equal cross sectional areas, their volumes must be the same.
Earlier, you were asked about the formula for the volume of a sphere.
If this is also the volume of a hemisphere, then the volume of a sphere must be twice as big. The volume of a sphere is:
Find the volume of the space between the cylinder and the cone below.
Describe what portion of a sphere has the same volume as the volume calculated in #2.
A hemisphere with radius 12 in would have the same volume.
Find the volume of a sphere with a diameter of 15 cm.
1. Find the volume of a sphere with a radius of 3 inches.
2. Find the volume of a sphere with a diameter of 12 inches.
3. Find the volume of a sphere with a diameter of 8 inches.
4. In your own words, explain where the formula for the volume of a sphere came from. How does it relate to a double cone within a cylinder?
A bead is created from a sphere by drilling a cylinder through the sphere. The original sphere has a radius of 8 mm. The cylinder drilled through the center has a radius of 4 mm.
5. What is the height of the bead? (Hint: Draw a right triangle and use the Pythagorean Theorem.)
6. What is the volume of the original sphere? What is the volume of the cylinder?
7. Due to Cavalieri's principle, the volume of the space above the cylinder is the same as the volume between a cone and a cylinder (see picture below). What is the approximate volume of the space above and below the cylinder that was cut off when making the bead?
8. What is the approximate volume of the bead?
A cylindrical container holds three tennis balls. The diameter of the cylinder is 4 inches, which is approximately the same as the diameter of each tennis ball. The height of the cylinder is 12 inches.
9. What is the volume of one tennis ball?
10. What is the volume of the space between the tennis balls and the cylinder?
To see the Review answers, open this PDF file and look for section 9.3.