What if you were given \begin{align*}\triangle FGH\end{align*} and \begin{align*}\triangle XYZ\end{align*} and you were told that \begin{align*}\angle{F} \cong \angle{X}\end{align*} and \begin{align*}\angle{G} \cong \angle{Y}\end{align*}? What conclusion could you draw about \begin{align*}\angle{H}\end{align*} and \begin{align*}\angle{Z}\end{align*}? After completing this Concept, you'll be able to make such a conclusion.

### Watch This

CK-12 Foundation: Chapter4TheThirdAngleTheoremA

### Guidance

Find \begin{align*}m \angle C\end{align*} and \begin{align*}m \angle J\end{align*}.

The sum of the angles in each triangle is \begin{align*}180^\circ\end{align*} by the Triangle Sum Theorem. So, for \begin{align*}\triangle ABC, 35^\circ + 88^\circ + m \angle C = 180^\circ\end{align*} and \begin{align*}m \angle C = 57^\circ\end{align*}. For \begin{align*}\triangle HIJ\end{align*}, \begin{align*}35^\circ + 88^\circ + m \angle J = 180^\circ\end{align*} and \begin{align*}m \angle J\end{align*} is also \begin{align*}57^\circ\end{align*}.

Notice that we were given that \begin{align*}m \angle A = m \angle H\end{align*} and \begin{align*}m \angle B = m \angle I\end{align*} and we found out that \begin{align*}m \angle C = m \angle J\end{align*}. This can be generalized into the Third Angle Theorem.

**Third Angle Theorem:** If two angles in one triangle are congruent to two angles in another triangle, then the third pair of angles must also congruent.

In other words, for triangles \begin{align*}\triangle ABC\end{align*} and \begin{align*}\triangle DEF\end{align*}, if \begin{align*} \angle A \cong \angle D\end{align*} and \begin{align*}\angle B \cong \angle E\end{align*}, then \begin{align*}\angle C \cong \angle F\end{align*}.

Notice that this theorem does not state that the triangles are congruent. That is because if two sets of angles are congruent, the sides could be different lengths. See the picture below.

#### Example A

Determine the measure of the missing angles.

From the markings, we know that \begin{align*}\angle A \cong D\end{align*} and \begin{align*}\angle E \cong \angle B\end{align*}. Therefore, the Third Angle Theorem tells us that \begin{align*}\angle C \cong \angle F\end{align*}. So,

\begin{align*}m \angle A+m \angle B+m \angle C &= 180^\circ\\ m \angle D+m \angle B+m \angle C &= 180^\circ\\ 42^\circ+83^\circ+m \angle C &= 180^\circ\\ m \angle C &= 55^\circ=m \angle F\end{align*}

#### Example B

The Third Angle Theorem states that if two angles in one triangle are congruent to two angles in another triangle, then the third pair of angles must also congruent. What additional information would you need to know in order to be able to determine that the triangles are congruent?

In order for the triangles to be congruent, you need some information about the sides. If you know two pairs of angles are congruent and at least one pair of corresponding sides are congruent, then the triangles will be congruent.

#### Example C

Determine the measure of all the angles in the triangle:

First we can see that \begin{align*} m \angle DCA=15^\circ\end{align*}. This means that \begin{align*}m\angle BAC =15^\circ\end{align*} also because they are alternate interior angles. \begin{align*} m\angle ABC=153^\circ\end{align*} was given. This means by the Triangle Sum Theorem that \begin{align*} m \angle BCA=12^\circ\end{align*}. This means that \begin{align*} m\angle CAD=12^\circ\end{align*} also because they are alternate interior angles. Finally, \begin{align*} m\angle ADC =153^\circ\end{align*} by the Triangle Sum Theorem.

Watch this video for help with the Examples above.

CK-12 Foundation: Chapter4TheThirdAngleTheoremB

#### Concept Problem Revisited

For two given triangles \begin{align*} \triangle FGH\end{align*} and \begin{align*} \triangle XYZ\end{align*}, you were told that \begin{align*} \angle F \cong \angle X\end{align*} and \begin{align*} \angle G \cong \angle Y\end{align*}.

By the Third Angle Theorem, \begin{align*} \angle H \cong \angle Z \end{align*}.

### Vocabulary

Two figures are ** congruent** if they have exactly the same size and shape. Two triangles are

**if the three corresponding angles and sides are congruent. The**

*congruent***states that the measure of the three interior angles of any triangle will add up to \begin{align*}180^\circ\end{align*}. The**

*Triangle Sum Theorem***states that if two angles in one triangle are congruent to two angles in another triangle, then the third pair of angles must also congruent.**

*Third Angle Theorem*### Guided Practice

Determine the measure of all the angles in the each triangle.

1.

2.

3.

**Answers:**

1. \begin{align*}m\angle A=86\end{align*}, \begin{align*}m\angle C = 42\end{align*} and by the Triangle Sum Theorem \begin{align*}m\angle B=52\end{align*}.

\begin{align*}m\angle Y=42\end{align*}, \begin{align*} m\angle X = 86 \end{align*} and by the Triangle Sum Theorem, \begin{align*}m\angle Z = 52\end{align*}.

2. \begin{align*} m \angle C = m \angle A=m \angle Y=m \angle Z =35\end{align*}. By the Triangle Sum Theorem \begin{align*} m\angle B= m \angle X =110\end{align*}.

3. \begin{align*} m \angle A=28\end{align*}, \begin{align*}m \angle ABE = 90\end{align*} and by the Triangle Sum Theorem, \begin{align*}m \angle E = 62\end{align*}. \begin{align*} m\angle D= m\angle E=62\end{align*} because they are alternate interior angles and the lines are parallel. \begin{align*} m\angle C= m\angle A=28\end{align*} because they are alternate interior angles and the lines are parallel. \begin{align*} m \angle DBC = m\angle ABE = 90\end{align*} because they are vertical angles.

### Practice

Determine the measures of the unknown angles.

- \begin{align*}\angle XYZ\end{align*}
- \begin{align*}\angle ZXY\end{align*}
- \begin{align*}\angle LNM\end{align*}
- \begin{align*}\angle MLN\end{align*}

- \begin{align*}\angle CED\end{align*}
- \begin{align*}\angle GFH\end{align*}
- \begin{align*}\angle FHG\end{align*}

- \begin{align*}\angle ACB\end{align*}
- \begin{align*}\angle HIJ\end{align*}
- \begin{align*}\angle HJI\end{align*}
- \begin{align*}\angle IHJ\end{align*}

- \begin{align*}\angle RQS\end{align*}
- \begin{align*}\angle SRQ\end{align*}
- \begin{align*}\angle TSU\end{align*}
- \begin{align*}\angle TUS\end{align*}